Composite of Holomorphic Functions is Holomorphic
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Let $f(z)$ and $g(w)$ be holomorphic functions. I want to prove that the composite $g(f(z))$ is also holomorphic by using Cauchy-Riemann Equation directly.
Let $g(f(z))=s(u(x,y), v(x,y)),+,i t(u(x,y), v(x,y))$.
Then we have $left{ begin{array} frac{partial s}{partial x}=frac{partial s}{partial u}frac{partial u}{partial x}+frac{partial s}{partial v}frac{partial v}{partial x}\ frac{partial t}{partial y}=frac{partial t}{partial u}frac{partial u}{partial y}+frac{partial t}{partial v}frac{partial v}{partial y}end{array}right.$.
If we can show that $frac{partial s}{partial x}=frac{partial t}{partial y}$ and $frac{partial s}{partial y}=-frac{partial t}{partial x}$, we can conclude that the composite $g(f(z))$ is holomorphic. Thus I tried to compute $frac{partial s}{partial x}-frac{partial t}{partial y}$, but I found it difficult to yield the desired result $0$ using Cauchy-Riemann equations of $f$ and $g$. Can I get some advices or hints to proceed more? Thank you.
complex-analysis cauchy-riemann-equations
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$begingroup$
Let $f(z)$ and $g(w)$ be holomorphic functions. I want to prove that the composite $g(f(z))$ is also holomorphic by using Cauchy-Riemann Equation directly.
Let $g(f(z))=s(u(x,y), v(x,y)),+,i t(u(x,y), v(x,y))$.
Then we have $left{ begin{array} frac{partial s}{partial x}=frac{partial s}{partial u}frac{partial u}{partial x}+frac{partial s}{partial v}frac{partial v}{partial x}\ frac{partial t}{partial y}=frac{partial t}{partial u}frac{partial u}{partial y}+frac{partial t}{partial v}frac{partial v}{partial y}end{array}right.$.
If we can show that $frac{partial s}{partial x}=frac{partial t}{partial y}$ and $frac{partial s}{partial y}=-frac{partial t}{partial x}$, we can conclude that the composite $g(f(z))$ is holomorphic. Thus I tried to compute $frac{partial s}{partial x}-frac{partial t}{partial y}$, but I found it difficult to yield the desired result $0$ using Cauchy-Riemann equations of $f$ and $g$. Can I get some advices or hints to proceed more? Thank you.
complex-analysis cauchy-riemann-equations
$endgroup$
add a comment |
$begingroup$
Let $f(z)$ and $g(w)$ be holomorphic functions. I want to prove that the composite $g(f(z))$ is also holomorphic by using Cauchy-Riemann Equation directly.
Let $g(f(z))=s(u(x,y), v(x,y)),+,i t(u(x,y), v(x,y))$.
Then we have $left{ begin{array} frac{partial s}{partial x}=frac{partial s}{partial u}frac{partial u}{partial x}+frac{partial s}{partial v}frac{partial v}{partial x}\ frac{partial t}{partial y}=frac{partial t}{partial u}frac{partial u}{partial y}+frac{partial t}{partial v}frac{partial v}{partial y}end{array}right.$.
If we can show that $frac{partial s}{partial x}=frac{partial t}{partial y}$ and $frac{partial s}{partial y}=-frac{partial t}{partial x}$, we can conclude that the composite $g(f(z))$ is holomorphic. Thus I tried to compute $frac{partial s}{partial x}-frac{partial t}{partial y}$, but I found it difficult to yield the desired result $0$ using Cauchy-Riemann equations of $f$ and $g$. Can I get some advices or hints to proceed more? Thank you.
complex-analysis cauchy-riemann-equations
$endgroup$
Let $f(z)$ and $g(w)$ be holomorphic functions. I want to prove that the composite $g(f(z))$ is also holomorphic by using Cauchy-Riemann Equation directly.
Let $g(f(z))=s(u(x,y), v(x,y)),+,i t(u(x,y), v(x,y))$.
Then we have $left{ begin{array} frac{partial s}{partial x}=frac{partial s}{partial u}frac{partial u}{partial x}+frac{partial s}{partial v}frac{partial v}{partial x}\ frac{partial t}{partial y}=frac{partial t}{partial u}frac{partial u}{partial y}+frac{partial t}{partial v}frac{partial v}{partial y}end{array}right.$.
If we can show that $frac{partial s}{partial x}=frac{partial t}{partial y}$ and $frac{partial s}{partial y}=-frac{partial t}{partial x}$, we can conclude that the composite $g(f(z))$ is holomorphic. Thus I tried to compute $frac{partial s}{partial x}-frac{partial t}{partial y}$, but I found it difficult to yield the desired result $0$ using Cauchy-Riemann equations of $f$ and $g$. Can I get some advices or hints to proceed more? Thank you.
complex-analysis cauchy-riemann-equations
complex-analysis cauchy-riemann-equations
asked Jan 17 at 19:33
SH LeeSH Lee
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Since $f$ and $g$ are holomorphic, you know that $partial s/partial u=partial t/partial v$ and $partial u/partial x=partial v/partial y$. Therefore the first term in the expression of $partial s/partial x$ equals the second one in the expression for $partial t/partial y$. Using the other CR equations for $f$ and $g$ you can show that the other two terms are equal as well (the minus signs will cancel)
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Oh, I got it. Thanks a lot!
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– SH Lee
Jan 17 at 19:54
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$begingroup$
Since $f$ and $g$ are holomorphic, you know that $partial s/partial u=partial t/partial v$ and $partial u/partial x=partial v/partial y$. Therefore the first term in the expression of $partial s/partial x$ equals the second one in the expression for $partial t/partial y$. Using the other CR equations for $f$ and $g$ you can show that the other two terms are equal as well (the minus signs will cancel)
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$begingroup$
Oh, I got it. Thanks a lot!
$endgroup$
– SH Lee
Jan 17 at 19:54
add a comment |
$begingroup$
Since $f$ and $g$ are holomorphic, you know that $partial s/partial u=partial t/partial v$ and $partial u/partial x=partial v/partial y$. Therefore the first term in the expression of $partial s/partial x$ equals the second one in the expression for $partial t/partial y$. Using the other CR equations for $f$ and $g$ you can show that the other two terms are equal as well (the minus signs will cancel)
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$begingroup$
Oh, I got it. Thanks a lot!
$endgroup$
– SH Lee
Jan 17 at 19:54
add a comment |
$begingroup$
Since $f$ and $g$ are holomorphic, you know that $partial s/partial u=partial t/partial v$ and $partial u/partial x=partial v/partial y$. Therefore the first term in the expression of $partial s/partial x$ equals the second one in the expression for $partial t/partial y$. Using the other CR equations for $f$ and $g$ you can show that the other two terms are equal as well (the minus signs will cancel)
$endgroup$
Since $f$ and $g$ are holomorphic, you know that $partial s/partial u=partial t/partial v$ and $partial u/partial x=partial v/partial y$. Therefore the first term in the expression of $partial s/partial x$ equals the second one in the expression for $partial t/partial y$. Using the other CR equations for $f$ and $g$ you can show that the other two terms are equal as well (the minus signs will cancel)
answered Jan 17 at 19:49
GReyesGReyes
2,52815
2,52815
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Oh, I got it. Thanks a lot!
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– SH Lee
Jan 17 at 19:54
add a comment |
$begingroup$
Oh, I got it. Thanks a lot!
$endgroup$
– SH Lee
Jan 17 at 19:54
$begingroup$
Oh, I got it. Thanks a lot!
$endgroup$
– SH Lee
Jan 17 at 19:54
$begingroup$
Oh, I got it. Thanks a lot!
$endgroup$
– SH Lee
Jan 17 at 19:54
add a comment |
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