Why $|z^5|-2^5=0$ has $infty$ solutions in $mathbb{C}$?
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Given $z=x+iy$ a complex number, I can't understand why $|z^5|-2^5=0$ has infinite solutions in $mathbb{C}$ .
complex-numbers
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asked Jan 16 at 18:15
Kevin Kevin
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For any $thetain[0, 2pi/5),$ the complex number $z=2(costheta+isintheta)$ satisfies your equation.
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