Conditional Hypergeometric probability? [closed]
$begingroup$
I have an unusual question which I’m trying to find the answer to to satisfy my own curiosity. I understand how hypergeometric probability works but I want to know how to calculate it given 2 events occurring, and hopefully my title is correct because I think it would be dependent.
Ex. You draw 5 cards from a standard deck of playing cards. What is the probability that 2 of them are hearts AND 1 of the 5 is a spade.
Would I calculate the hypergeometric probabilities individually and then multiply them together? What if I wanted to know the probability of three events such as 2 hearts, 1 spade, and 1 club. Thanks!
statistics
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
$endgroup$
closed as off-topic by José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus Jan 13 at 4:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
I have an unusual question which I’m trying to find the answer to to satisfy my own curiosity. I understand how hypergeometric probability works but I want to know how to calculate it given 2 events occurring, and hopefully my title is correct because I think it would be dependent.
Ex. You draw 5 cards from a standard deck of playing cards. What is the probability that 2 of them are hearts AND 1 of the 5 is a spade.
Would I calculate the hypergeometric probabilities individually and then multiply them together? What if I wanted to know the probability of three events such as 2 hearts, 1 spade, and 1 club. Thanks!
statistics
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
$endgroup$
closed as off-topic by José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus Jan 13 at 4:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus
If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
1
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52
add a comment |
$begingroup$
I have an unusual question which I’m trying to find the answer to to satisfy my own curiosity. I understand how hypergeometric probability works but I want to know how to calculate it given 2 events occurring, and hopefully my title is correct because I think it would be dependent.
Ex. You draw 5 cards from a standard deck of playing cards. What is the probability that 2 of them are hearts AND 1 of the 5 is a spade.
Would I calculate the hypergeometric probabilities individually and then multiply them together? What if I wanted to know the probability of three events such as 2 hearts, 1 spade, and 1 club. Thanks!
statistics
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
$endgroup$
I have an unusual question which I’m trying to find the answer to to satisfy my own curiosity. I understand how hypergeometric probability works but I want to know how to calculate it given 2 events occurring, and hopefully my title is correct because I think it would be dependent.
Ex. You draw 5 cards from a standard deck of playing cards. What is the probability that 2 of them are hearts AND 1 of the 5 is a spade.
Would I calculate the hypergeometric probabilities individually and then multiply them together? What if I wanted to know the probability of three events such as 2 hearts, 1 spade, and 1 club. Thanks!
statistics
statistics
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
asked Jan 12 at 11:43
Joshua WoodJoshua Wood
61
61
closed as off-topic by José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus Jan 13 at 4:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus Jan 13 at 4:17
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Adrian Keister, Namaste, Paul Frost, clathratus
If this question can be reworded to fit the rules in the help center, please edit the question.
1
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
1
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52
add a comment |
1
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
1
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52
1
1
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
1
1
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52
add a comment |
0
active
oldest
votes
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
$begingroup$
@JoséCarlosSantos It's not an isolated problem; it's actually pretty solid.
$endgroup$
– Parcly Taxel
Jan 12 at 11:48
1
$begingroup$
@JoséCarlosSantos Also, there is context given in the first paragraph. Please avoid slapping this long comment indiscriminately onto questions.
$endgroup$
– Parcly Taxel
Jan 12 at 11:52