Unable to take user input command in pssh command
I am trying to get the OS command from user input and export and use in function, like below
export command5=date
export command4=uname
Its working in below command
pssh -h /tmp/cus6 -i "$command5;$command4"
[1] 04:17:06 [SUCCESS] Server1
Mon Jan 28 03:17:06 UTC 2019
Linux
[2] 04:17:06 [SUCCESS] Server2
Mon Jan 28 03:17:06 UTC 2019
Linux
But didn't work when trying to keep commands in one line
pssh -h /tmp/cus6 -i 'echo $(echo ), $(command5), $(command4)'
[1] 04:26:45 [SUCCESS] Server1
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
[2] 04:26:45 [SUCCESS] Server2
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
But same is working in keeping commands instead of command5 & command4
pssh -h /tmp/cus6 -i 'echo $(echo ), $(date), $(uname)'
[1] 04:30:01 [SUCCESS] Server1
, Mon Jan 28 03:30:01 UTC 2019, Linux
[2] 04:30:01 [SUCCESS] Server2
, Mon Jan 28 03:30:01 UTC 2019, Linux
bash
edited Jan 28 at 3:44
Olorin
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
add a comment |
I am trying to get the OS command from user input and export and use in function, like below
export command5=date
export command4=uname
Its working in below command
pssh -h /tmp/cus6 -i "$command5;$command4"
[1] 04:17:06 [SUCCESS] Server1
Mon Jan 28 03:17:06 UTC 2019
Linux
[2] 04:17:06 [SUCCESS] Server2
Mon Jan 28 03:17:06 UTC 2019
Linux
But didn't work when trying to keep commands in one line
pssh -h /tmp/cus6 -i 'echo $(echo ), $(command5), $(command4)'
[1] 04:26:45 [SUCCESS] Server1
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
[2] 04:26:45 [SUCCESS] Server2
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
But same is working in keeping commands instead of command5 & command4
pssh -h /tmp/cus6 -i 'echo $(echo ), $(date), $(uname)'
[1] 04:30:01 [SUCCESS] Server1
, Mon Jan 28 03:30:01 UTC 2019, Linux
[2] 04:30:01 [SUCCESS] Server2
, Mon Jan 28 03:30:01 UTC 2019, Linux
bash
edited Jan 28 at 3:44
Olorin
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
add a comment |
I am trying to get the OS command from user input and export and use in function, like below
export command5=date
export command4=uname
Its working in below command
pssh -h /tmp/cus6 -i "$command5;$command4"
[1] 04:17:06 [SUCCESS] Server1
Mon Jan 28 03:17:06 UTC 2019
Linux
[2] 04:17:06 [SUCCESS] Server2
Mon Jan 28 03:17:06 UTC 2019
Linux
But didn't work when trying to keep commands in one line
pssh -h /tmp/cus6 -i 'echo $(echo ), $(command5), $(command4)'
[1] 04:26:45 [SUCCESS] Server1
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
[2] 04:26:45 [SUCCESS] Server2
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
But same is working in keeping commands instead of command5 & command4
pssh -h /tmp/cus6 -i 'echo $(echo ), $(date), $(uname)'
[1] 04:30:01 [SUCCESS] Server1
, Mon Jan 28 03:30:01 UTC 2019, Linux
[2] 04:30:01 [SUCCESS] Server2
, Mon Jan 28 03:30:01 UTC 2019, Linux
bash
edited Jan 28 at 3:44
Olorin
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
I am trying to get the OS command from user input and export and use in function, like below
export command5=date
export command4=uname
Its working in below command
pssh -h /tmp/cus6 -i "$command5;$command4"
[1] 04:17:06 [SUCCESS] Server1
Mon Jan 28 03:17:06 UTC 2019
Linux
[2] 04:17:06 [SUCCESS] Server2
Mon Jan 28 03:17:06 UTC 2019
Linux
But didn't work when trying to keep commands in one line
pssh -h /tmp/cus6 -i 'echo $(echo ), $(command5), $(command4)'
[1] 04:26:45 [SUCCESS] Server1
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
[2] 04:26:45 [SUCCESS] Server2
, ,
Stderr: bash: command5: command not found
bash: command4: command not found
But same is working in keeping commands instead of command5 & command4
pssh -h /tmp/cus6 -i 'echo $(echo ), $(date), $(uname)'
[1] 04:30:01 [SUCCESS] Server1
, Mon Jan 28 03:30:01 UTC 2019, Linux
[2] 04:30:01 [SUCCESS] Server2
, Mon Jan 28 03:30:01 UTC 2019, Linux
bash
bash
edited Jan 28 at 3:44
Olorin
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
edited Jan 28 at 3:44
Olorin
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
edited Jan 28 at 3:44
Olorin
2,621924
edited Jan 28 at 3:44
Olorin
2,621924
edited Jan 28 at 3:44
Olorin
2,621924
2,621924
asked Jan 28 at 3:32
Sin15Sin15
62
asked Jan 28 at 3:32
Sin15Sin15
62
asked Jan 28 at 3:32
Sin15Sin15
62
62
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
In order for the local variable to be expanded, you will need to replace the outer single quotes with double quotes.
Then, in order to pass the command substitution to the remote shell, you will need to quote (or escape) that.
Ex.
$ cmd='uname -r'
$ parallel-ssh -h hostsfile -i "echo $($cmd)"
[1] 22:38:52 [SUCCESS] vm
4.4.0-141-generic
[2] 22:38:52 [SUCCESS] localhost
4.15.0-43-generic
Related: In some places awk doesn't work in pssh command
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
In order for the local variable to be expanded, you will need to replace the outer single quotes with double quotes.
Then, in order to pass the command substitution to the remote shell, you will need to quote (or escape) that.
Ex.
$ cmd='uname -r'
$ parallel-ssh -h hostsfile -i "echo $($cmd)"
[1] 22:38:52 [SUCCESS] vm
4.4.0-141-generic
[2] 22:38:52 [SUCCESS] localhost
4.15.0-43-generic
Related: In some places awk doesn't work in pssh command
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
add a comment |
In order for the local variable to be expanded, you will need to replace the outer single quotes with double quotes.
Then, in order to pass the command substitution to the remote shell, you will need to quote (or escape) that.
Ex.
$ cmd='uname -r'
$ parallel-ssh -h hostsfile -i "echo $($cmd)"
[1] 22:38:52 [SUCCESS] vm
4.4.0-141-generic
[2] 22:38:52 [SUCCESS] localhost
4.15.0-43-generic
Related: In some places awk doesn't work in pssh command
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
add a comment |
In order for the local variable to be expanded, you will need to replace the outer single quotes with double quotes.
Then, in order to pass the command substitution to the remote shell, you will need to quote (or escape) that.
Ex.
$ cmd='uname -r'
$ parallel-ssh -h hostsfile -i "echo $($cmd)"
[1] 22:38:52 [SUCCESS] vm
4.4.0-141-generic
[2] 22:38:52 [SUCCESS] localhost
4.15.0-43-generic
Related: In some places awk doesn't work in pssh command
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
In order for the local variable to be expanded, you will need to replace the outer single quotes with double quotes.
Then, in order to pass the command substitution to the remote shell, you will need to quote (or escape) that.
Ex.
$ cmd='uname -r'
$ parallel-ssh -h hostsfile -i "echo $($cmd)"
[1] 22:38:52 [SUCCESS] vm
4.4.0-141-generic
[2] 22:38:52 [SUCCESS] localhost
4.15.0-43-generic
Related: In some places awk doesn't work in pssh command
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
answered Jan 28 at 3:46
steeldriversteeldriver
68.7k11113184
68.7k11113184
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
add a comment |
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
awk again having an issue, when user inputs any command with awk - uname -a|awk "{print $3}" is not taking . command1:, command, not found
– Sin15
Jan 28 at 5:09
add a comment |
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