Formal statement that functions intersect
$begingroup$
How do I express the following as a mathematical statement with quantification of all variables and making the universe explicit.
"The curves $y=1-x^2$ and $y=3x-2$ intersect"
So far I have $(exists (x,y)in mathbb{R})$
calculus proof-verification proof-explanation
$endgroup$
add a comment |
$begingroup$
How do I express the following as a mathematical statement with quantification of all variables and making the universe explicit.
"The curves $y=1-x^2$ and $y=3x-2$ intersect"
So far I have $(exists (x,y)in mathbb{R})$
calculus proof-verification proof-explanation
$endgroup$
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29
add a comment |
$begingroup$
How do I express the following as a mathematical statement with quantification of all variables and making the universe explicit.
"The curves $y=1-x^2$ and $y=3x-2$ intersect"
So far I have $(exists (x,y)in mathbb{R})$
calculus proof-verification proof-explanation
$endgroup$
How do I express the following as a mathematical statement with quantification of all variables and making the universe explicit.
"The curves $y=1-x^2$ and $y=3x-2$ intersect"
So far I have $(exists (x,y)in mathbb{R})$
calculus proof-verification proof-explanation
calculus proof-verification proof-explanation
edited Jan 10 at 23:42
David G. Stork
11k41432
11k41432
asked Jan 10 at 23:20
ForextraderForextrader
808
808
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29
add a comment |
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
No need to even mention the irrelevant $y$:
$$exists x in mathbb{R} s.t. 1-x^2 = 3 x-2$$
Just for "culture," here is a graph confirming there are two solutions:
$endgroup$
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
add a comment |
$begingroup$
$$exists xin mathbb{R},, exists y in mathbb{R},,,y=1-x^2 ,wedge, y=3x-2$$
$endgroup$
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3069300%2fformal-statement-that-functions-intersect%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
No need to even mention the irrelevant $y$:
$$exists x in mathbb{R} s.t. 1-x^2 = 3 x-2$$
Just for "culture," here is a graph confirming there are two solutions:
$endgroup$
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
add a comment |
$begingroup$
No need to even mention the irrelevant $y$:
$$exists x in mathbb{R} s.t. 1-x^2 = 3 x-2$$
Just for "culture," here is a graph confirming there are two solutions:
$endgroup$
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
add a comment |
$begingroup$
No need to even mention the irrelevant $y$:
$$exists x in mathbb{R} s.t. 1-x^2 = 3 x-2$$
Just for "culture," here is a graph confirming there are two solutions:
$endgroup$
No need to even mention the irrelevant $y$:
$$exists x in mathbb{R} s.t. 1-x^2 = 3 x-2$$
Just for "culture," here is a graph confirming there are two solutions:
edited Jan 11 at 0:18
answered Jan 10 at 23:43
David G. StorkDavid G. Stork
11k41432
11k41432
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
add a comment |
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
$begingroup$
Thank you, that makes sense
$endgroup$
– Forextrader
Jan 10 at 23:46
add a comment |
$begingroup$
$$exists xin mathbb{R},, exists y in mathbb{R},,,y=1-x^2 ,wedge, y=3x-2$$
$endgroup$
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
add a comment |
$begingroup$
$$exists xin mathbb{R},, exists y in mathbb{R},,,y=1-x^2 ,wedge, y=3x-2$$
$endgroup$
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
add a comment |
$begingroup$
$$exists xin mathbb{R},, exists y in mathbb{R},,,y=1-x^2 ,wedge, y=3x-2$$
$endgroup$
$$exists xin mathbb{R},, exists y in mathbb{R},,,y=1-x^2 ,wedge, y=3x-2$$
answered Jan 10 at 23:26
MindlackMindlack
4,830210
4,830210
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
add a comment |
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Thank you, but wouldn't this also suffice $(exists (x,y)in mathbb{R},y=1-x^2 wedge y=3x-2$ )
$endgroup$
– Forextrader
Jan 10 at 23:30
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
$begingroup$
Isn't this statement redundant? It's sufficient to state that there exists an $x$ for which $1-x^2=3x-2$. Correct?
$endgroup$
– Matteo
Jan 10 at 23:31
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3069300%2fformal-statement-that-functions-intersect%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
How would you say that a point $(x,y)$ is on one of the curves?
$endgroup$
– John Douma
Jan 10 at 23:26
$begingroup$
Hint: if a point belongs to both lines (i.e. they intersect), then it's abscissa will give the same ordinate when substituted into the lines' equations.
$endgroup$
– Matteo
Jan 10 at 23:28
$begingroup$
Ahh right, if both are true. under the original condition
$endgroup$
– Forextrader
Jan 10 at 23:29