How to find point reflected over line in 3 dimensional space
0
$begingroup$
Find operator matrix of reflection over line x = 2y = z.
Can't find the reflected point, else should be easy
linear-algebra vector-spaces analytic-geometry
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
$endgroup$
add a comment |
0
$begingroup$
Find operator matrix of reflection over line x = 2y = z.
Can't find the reflected point, else should be easy
linear-algebra vector-spaces analytic-geometry
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
$endgroup$
$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03
add a comment |
0
0
0
$begingroup$
Find operator matrix of reflection over line x = 2y = z.
Can't find the reflected point, else should be easy
linear-algebra vector-spaces analytic-geometry
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
$endgroup$
Find operator matrix of reflection over line x = 2y = z.
Can't find the reflected point, else should be easy
linear-algebra vector-spaces analytic-geometry
linear-algebra vector-spaces analytic-geometry
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
asked Jan 14 at 21:03
l3tVb3l3tVb3
1
1
$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03
add a comment |
$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03
$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03
add a comment |
0
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$begingroup$
$vec P'=2vec n(vec ncdotvec P) - vec P$, where $vec n$ is line unit vector.
$endgroup$
– Aretino
Jan 14 at 21:11
$begingroup$
Pretty much solved it. Thanks
$endgroup$
– l3tVb3
Jan 14 at 22:03