Applying the chain rule on vectors and matrices












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I need to find $frac{dy}{dx}$ for the following



y = $||A^Tx - b||_2^2$ where $A in R^{3x3}, b in R^{3x1}, x in R^{3x1}, y in R,$ and $||.||_2$ is the euclidean norm so for example $||z||_2^2 = z^Tz$ for $z in R^{3x1}$. I'm familiar with the chain rule but I've never really used it in this way. Also, I'm not sure what $R^{3x3}$ represents and how I can use it with the chain rule.










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    0












    $begingroup$


    I need to find $frac{dy}{dx}$ for the following



    y = $||A^Tx - b||_2^2$ where $A in R^{3x3}, b in R^{3x1}, x in R^{3x1}, y in R,$ and $||.||_2$ is the euclidean norm so for example $||z||_2^2 = z^Tz$ for $z in R^{3x1}$. I'm familiar with the chain rule but I've never really used it in this way. Also, I'm not sure what $R^{3x3}$ represents and how I can use it with the chain rule.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I need to find $frac{dy}{dx}$ for the following



      y = $||A^Tx - b||_2^2$ where $A in R^{3x3}, b in R^{3x1}, x in R^{3x1}, y in R,$ and $||.||_2$ is the euclidean norm so for example $||z||_2^2 = z^Tz$ for $z in R^{3x1}$. I'm familiar with the chain rule but I've never really used it in this way. Also, I'm not sure what $R^{3x3}$ represents and how I can use it with the chain rule.










      share|cite|improve this question









      $endgroup$




      I need to find $frac{dy}{dx}$ for the following



      y = $||A^Tx - b||_2^2$ where $A in R^{3x3}, b in R^{3x1}, x in R^{3x1}, y in R,$ and $||.||_2$ is the euclidean norm so for example $||z||_2^2 = z^Tz$ for $z in R^{3x1}$. I'm familiar with the chain rule but I've never really used it in this way. Also, I'm not sure what $R^{3x3}$ represents and how I can use it with the chain rule.







      matrices derivatives vectors real-numbers chain-rule






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      asked Jan 14 at 20:58









      Brandon MacLeodBrandon MacLeod

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          $begingroup$

          Define the vector
          $$z=A^Tx-b$$
          Write the function in terms of this new vector. Then find its differential and gradient.
          $$eqalign{
          y &= z^Tz cr
          dy &= 2z^Tdz = 2z^T(A^Tdx) = (2Az)^Tdx cr
          frac{partial y}{partial x} &= 2Az = 2A(A^Tx-b) crcr
          }$$

          The symbol ${mathbb R}^{mtimes n}$ denotes a matrix of real numbers with $m$ rows and $n$ columns.






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            1 Answer
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            $begingroup$

            Define the vector
            $$z=A^Tx-b$$
            Write the function in terms of this new vector. Then find its differential and gradient.
            $$eqalign{
            y &= z^Tz cr
            dy &= 2z^Tdz = 2z^T(A^Tdx) = (2Az)^Tdx cr
            frac{partial y}{partial x} &= 2Az = 2A(A^Tx-b) crcr
            }$$

            The symbol ${mathbb R}^{mtimes n}$ denotes a matrix of real numbers with $m$ rows and $n$ columns.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              Define the vector
              $$z=A^Tx-b$$
              Write the function in terms of this new vector. Then find its differential and gradient.
              $$eqalign{
              y &= z^Tz cr
              dy &= 2z^Tdz = 2z^T(A^Tdx) = (2Az)^Tdx cr
              frac{partial y}{partial x} &= 2Az = 2A(A^Tx-b) crcr
              }$$

              The symbol ${mathbb R}^{mtimes n}$ denotes a matrix of real numbers with $m$ rows and $n$ columns.






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                Define the vector
                $$z=A^Tx-b$$
                Write the function in terms of this new vector. Then find its differential and gradient.
                $$eqalign{
                y &= z^Tz cr
                dy &= 2z^Tdz = 2z^T(A^Tdx) = (2Az)^Tdx cr
                frac{partial y}{partial x} &= 2Az = 2A(A^Tx-b) crcr
                }$$

                The symbol ${mathbb R}^{mtimes n}$ denotes a matrix of real numbers with $m$ rows and $n$ columns.






                share|cite|improve this answer









                $endgroup$



                Define the vector
                $$z=A^Tx-b$$
                Write the function in terms of this new vector. Then find its differential and gradient.
                $$eqalign{
                y &= z^Tz cr
                dy &= 2z^Tdz = 2z^T(A^Tdx) = (2Az)^Tdx cr
                frac{partial y}{partial x} &= 2Az = 2A(A^Tx-b) crcr
                }$$

                The symbol ${mathbb R}^{mtimes n}$ denotes a matrix of real numbers with $m$ rows and $n$ columns.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Jan 15 at 18:37









                greggreg

                8,9951824




                8,9951824






























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