How many colors does it take?












9












$begingroup$


This question is from a popular monthly science magazine in my country:



You have an 8x8 square where any 3 squares forming a tromino (including reflections and rotations) must consist of three different colored squares. At least how many colors do you need to paint the entire board?



Bonus: How about larger boards?










share|improve this question











$endgroup$












  • $begingroup$
    Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
    $endgroup$
    – Nautilus
    Feb 11 at 14:41


















9












$begingroup$


This question is from a popular monthly science magazine in my country:



You have an 8x8 square where any 3 squares forming a tromino (including reflections and rotations) must consist of three different colored squares. At least how many colors do you need to paint the entire board?



Bonus: How about larger boards?










share|improve this question











$endgroup$












  • $begingroup$
    Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
    $endgroup$
    – Nautilus
    Feb 11 at 14:41
















9












9








9


1



$begingroup$


This question is from a popular monthly science magazine in my country:



You have an 8x8 square where any 3 squares forming a tromino (including reflections and rotations) must consist of three different colored squares. At least how many colors do you need to paint the entire board?



Bonus: How about larger boards?










share|improve this question











$endgroup$




This question is from a popular monthly science magazine in my country:



You have an 8x8 square where any 3 squares forming a tromino (including reflections and rotations) must consist of three different colored squares. At least how many colors do you need to paint the entire board?



Bonus: How about larger boards?







graph-theory polyomino






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 11 at 11:11









Bass

31k472188




31k472188










asked Feb 11 at 9:54









NautilusNautilus

4,078525




4,078525












  • $begingroup$
    Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
    $endgroup$
    – Nautilus
    Feb 11 at 14:41




















  • $begingroup$
    Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
    $endgroup$
    – Nautilus
    Feb 11 at 14:41


















$begingroup$
Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
$endgroup$
– Nautilus
Feb 11 at 14:41






$begingroup$
Re: the edits, I was sure that the right name was triomino (based on tri(o)-), but I had put the word "popular" right before "science" because I wanted to stress that the magazine deals with popular science, so I don't think it necessarily breaks the adjective order rule.
$endgroup$
– Nautilus
Feb 11 at 14:41












1 Answer
1






active

oldest

votes


















12












$begingroup$

I think the answer is




5




using the following coloring:




8x8 board




For other board sizes,




5 is sufficient as well; the pattern can just be repeated. (Of course, a 2x2 board needs only 4 colors because there are only 4 squares. And does 1x1 even count as a board?)




Reasoning:




Consider a square not on the edge of the board with its 4 orthogonal neighbours; they all have to have different colors since each pair is part of a tromino. Therefore, we need at least 5 different colors; the pattern shows 5 is sufficient.







share|improve this answer











$endgroup$













  • $begingroup$
    I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
    $endgroup$
    – Rémi Henry
    Feb 11 at 10:09










  • $begingroup$
    They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
    $endgroup$
    – Glorfindel
    Feb 11 at 10:11






  • 1




    $begingroup$
    @Oray what's wrong with just extending the pattern?
    $endgroup$
    – Glorfindel
    Feb 11 at 10:39






  • 1




    $begingroup$
    If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
    $endgroup$
    – Bass
    Feb 11 at 11:23






  • 1




    $begingroup$
    Yeah, good idea.
    $endgroup$
    – Glorfindel
    Feb 11 at 11:31












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









12












$begingroup$

I think the answer is




5




using the following coloring:




8x8 board




For other board sizes,




5 is sufficient as well; the pattern can just be repeated. (Of course, a 2x2 board needs only 4 colors because there are only 4 squares. And does 1x1 even count as a board?)




Reasoning:




Consider a square not on the edge of the board with its 4 orthogonal neighbours; they all have to have different colors since each pair is part of a tromino. Therefore, we need at least 5 different colors; the pattern shows 5 is sufficient.







share|improve this answer











$endgroup$













  • $begingroup$
    I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
    $endgroup$
    – Rémi Henry
    Feb 11 at 10:09










  • $begingroup$
    They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
    $endgroup$
    – Glorfindel
    Feb 11 at 10:11






  • 1




    $begingroup$
    @Oray what's wrong with just extending the pattern?
    $endgroup$
    – Glorfindel
    Feb 11 at 10:39






  • 1




    $begingroup$
    If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
    $endgroup$
    – Bass
    Feb 11 at 11:23






  • 1




    $begingroup$
    Yeah, good idea.
    $endgroup$
    – Glorfindel
    Feb 11 at 11:31
















12












$begingroup$

I think the answer is




5




using the following coloring:




8x8 board




For other board sizes,




5 is sufficient as well; the pattern can just be repeated. (Of course, a 2x2 board needs only 4 colors because there are only 4 squares. And does 1x1 even count as a board?)




Reasoning:




Consider a square not on the edge of the board with its 4 orthogonal neighbours; they all have to have different colors since each pair is part of a tromino. Therefore, we need at least 5 different colors; the pattern shows 5 is sufficient.







share|improve this answer











$endgroup$













  • $begingroup$
    I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
    $endgroup$
    – Rémi Henry
    Feb 11 at 10:09










  • $begingroup$
    They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
    $endgroup$
    – Glorfindel
    Feb 11 at 10:11






  • 1




    $begingroup$
    @Oray what's wrong with just extending the pattern?
    $endgroup$
    – Glorfindel
    Feb 11 at 10:39






  • 1




    $begingroup$
    If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
    $endgroup$
    – Bass
    Feb 11 at 11:23






  • 1




    $begingroup$
    Yeah, good idea.
    $endgroup$
    – Glorfindel
    Feb 11 at 11:31














12












12








12





$begingroup$

I think the answer is




5




using the following coloring:




8x8 board




For other board sizes,




5 is sufficient as well; the pattern can just be repeated. (Of course, a 2x2 board needs only 4 colors because there are only 4 squares. And does 1x1 even count as a board?)




Reasoning:




Consider a square not on the edge of the board with its 4 orthogonal neighbours; they all have to have different colors since each pair is part of a tromino. Therefore, we need at least 5 different colors; the pattern shows 5 is sufficient.







share|improve this answer











$endgroup$



I think the answer is




5




using the following coloring:




8x8 board




For other board sizes,




5 is sufficient as well; the pattern can just be repeated. (Of course, a 2x2 board needs only 4 colors because there are only 4 squares. And does 1x1 even count as a board?)




Reasoning:




Consider a square not on the edge of the board with its 4 orthogonal neighbours; they all have to have different colors since each pair is part of a tromino. Therefore, we need at least 5 different colors; the pattern shows 5 is sufficient.








share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 11 at 15:00

























answered Feb 11 at 10:02









GlorfindelGlorfindel

14.4k45486




14.4k45486












  • $begingroup$
    I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
    $endgroup$
    – Rémi Henry
    Feb 11 at 10:09










  • $begingroup$
    They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
    $endgroup$
    – Glorfindel
    Feb 11 at 10:11






  • 1




    $begingroup$
    @Oray what's wrong with just extending the pattern?
    $endgroup$
    – Glorfindel
    Feb 11 at 10:39






  • 1




    $begingroup$
    If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
    $endgroup$
    – Bass
    Feb 11 at 11:23






  • 1




    $begingroup$
    Yeah, good idea.
    $endgroup$
    – Glorfindel
    Feb 11 at 11:31


















  • $begingroup$
    I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
    $endgroup$
    – Rémi Henry
    Feb 11 at 10:09










  • $begingroup$
    They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
    $endgroup$
    – Glorfindel
    Feb 11 at 10:11






  • 1




    $begingroup$
    @Oray what's wrong with just extending the pattern?
    $endgroup$
    – Glorfindel
    Feb 11 at 10:39






  • 1




    $begingroup$
    If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
    $endgroup$
    – Bass
    Feb 11 at 11:23






  • 1




    $begingroup$
    Yeah, good idea.
    $endgroup$
    – Glorfindel
    Feb 11 at 11:31
















$begingroup$
I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
$endgroup$
– Rémi Henry
Feb 11 at 10:09




$begingroup$
I think it's wrong, the angular triomino "2 5 3" (with the 5 at the angle) is repeating. The 2 on first line, 2nd column, and the 2 on 4th line 3rd column, they make the same triomino with the same colours.
$endgroup$
– Rémi Henry
Feb 11 at 10:09












$begingroup$
They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
$endgroup$
– Glorfindel
Feb 11 at 10:11




$begingroup$
They are all repeating (since it's a pattern); the point is that each triomino has three different colours. Triominos are not compared with each other (at least that's how I interpreted the puzzle).
$endgroup$
– Glorfindel
Feb 11 at 10:11




1




1




$begingroup$
@Oray what's wrong with just extending the pattern?
$endgroup$
– Glorfindel
Feb 11 at 10:39




$begingroup$
@Oray what's wrong with just extending the pattern?
$endgroup$
– Glorfindel
Feb 11 at 10:39




1




1




$begingroup$
If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
$endgroup$
– Bass
Feb 11 at 11:23




$begingroup$
If at all possible, it's good to use something else than different shades of red and green for conveying significant information.
$endgroup$
– Bass
Feb 11 at 11:23




1




1




$begingroup$
Yeah, good idea.
$endgroup$
– Glorfindel
Feb 11 at 11:31




$begingroup$
Yeah, good idea.
$endgroup$
– Glorfindel
Feb 11 at 11:31


















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