23-bit mantissa and 9-bit exponent range and precision












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I have the following problem which I would like to make sure that I understand correctly. So I would appreciate your help in this matter.




Some computers (such as IBM mainframes) used to implement real data
using a 23-bit mantissa and a 9-bit exponent. What precision and range
can we expect from real data on these machines?




My understanding:



This floating point system has the following representation:



S EEEEEEEEE MMMMMMMMMMMMMMMMMMMMMMM



with S being the sign bit, E being the exponent bits, and M the mantissa bits. Is it true, then, that this FP system would have the range of $-2^{255}cdot 2^{23}$ to $2^{255}cdot 2^{23}$?



As to this FP's precision, the smallest distance between numbers would be the distance between $2^{-256} cdot 2^{-22}$ and $2^{-256} cdot 2^{-21}$.



Is this correct?










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    0












    $begingroup$


    I have the following problem which I would like to make sure that I understand correctly. So I would appreciate your help in this matter.




    Some computers (such as IBM mainframes) used to implement real data
    using a 23-bit mantissa and a 9-bit exponent. What precision and range
    can we expect from real data on these machines?




    My understanding:



    This floating point system has the following representation:



    S EEEEEEEEE MMMMMMMMMMMMMMMMMMMMMMM



    with S being the sign bit, E being the exponent bits, and M the mantissa bits. Is it true, then, that this FP system would have the range of $-2^{255}cdot 2^{23}$ to $2^{255}cdot 2^{23}$?



    As to this FP's precision, the smallest distance between numbers would be the distance between $2^{-256} cdot 2^{-22}$ and $2^{-256} cdot 2^{-21}$.



    Is this correct?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I have the following problem which I would like to make sure that I understand correctly. So I would appreciate your help in this matter.




      Some computers (such as IBM mainframes) used to implement real data
      using a 23-bit mantissa and a 9-bit exponent. What precision and range
      can we expect from real data on these machines?




      My understanding:



      This floating point system has the following representation:



      S EEEEEEEEE MMMMMMMMMMMMMMMMMMMMMMM



      with S being the sign bit, E being the exponent bits, and M the mantissa bits. Is it true, then, that this FP system would have the range of $-2^{255}cdot 2^{23}$ to $2^{255}cdot 2^{23}$?



      As to this FP's precision, the smallest distance between numbers would be the distance between $2^{-256} cdot 2^{-22}$ and $2^{-256} cdot 2^{-21}$.



      Is this correct?










      share|cite|improve this question









      $endgroup$




      I have the following problem which I would like to make sure that I understand correctly. So I would appreciate your help in this matter.




      Some computers (such as IBM mainframes) used to implement real data
      using a 23-bit mantissa and a 9-bit exponent. What precision and range
      can we expect from real data on these machines?




      My understanding:



      This floating point system has the following representation:



      S EEEEEEEEE MMMMMMMMMMMMMMMMMMMMMMM



      with S being the sign bit, E being the exponent bits, and M the mantissa bits. Is it true, then, that this FP system would have the range of $-2^{255}cdot 2^{23}$ to $2^{255}cdot 2^{23}$?



      As to this FP's precision, the smallest distance between numbers would be the distance between $2^{-256} cdot 2^{-22}$ and $2^{-256} cdot 2^{-21}$.



      Is this correct?







      computer-science binary computational-mathematics floating-point






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      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 11 at 23:00









      sequencesequence

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