Select by Attributes With OR Operator












2















I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.



Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.



"H1"  =  '31p'  OR  '34n'  OR  '61f'  OR  '31q' 
"H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'


None of them work. Should I use "IS" logical operator instead of "="?










share|improve this question





























    2















    I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.



    Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.



    "H1"  =  '31p'  OR  '34n'  OR  '61f'  OR  '31q' 
    "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'


    None of them work. Should I use "IS" logical operator instead of "="?










    share|improve this question



























      2












      2








      2








      I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.



      Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.



      "H1"  =  '31p'  OR  '34n'  OR  '61f'  OR  '31q' 
      "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'


      None of them work. Should I use "IS" logical operator instead of "="?










      share|improve this question
















      I know this is a very basic question, but I've been looking for an answer and haven't been able to find one, so here it goes. I am trying to build a long query to select features that have different values in the same field, in order to make it as agile as poossible. All in one selection.



      Example: In a given attribute table, in the field "H1" select features that have values "31p", "34n", "61f" and "31q" in it.



      "H1"  =  '31p'  OR  '34n'  OR  '61f'  OR  '31q' 
      "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR = '31q'


      None of them work. Should I use "IS" logical operator instead of "="?







      qgis






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 24 at 20:13









      PolyGeo

      53.6k1780240




      53.6k1780240










      asked Jan 24 at 10:59









      dmasanadmasana

      334




      334






















          1 Answer
          1






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          8














          You should repeat the column name for each value in the query



          "H1" = '31p' or "H1" = '34n' ...


          You had better to use "in" operator like



          "H1" in ('31p', '34n', '31q', '61f')





          share|improve this answer


























          • The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

            – dmasana
            Jan 24 at 13:17











          • I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

            – Zoltan
            Jan 24 at 15:54













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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8














          You should repeat the column name for each value in the query



          "H1" = '31p' or "H1" = '34n' ...


          You had better to use "in" operator like



          "H1" in ('31p', '34n', '31q', '61f')





          share|improve this answer


























          • The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

            – dmasana
            Jan 24 at 13:17











          • I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

            – Zoltan
            Jan 24 at 15:54


















          8














          You should repeat the column name for each value in the query



          "H1" = '31p' or "H1" = '34n' ...


          You had better to use "in" operator like



          "H1" in ('31p', '34n', '31q', '61f')





          share|improve this answer


























          • The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

            – dmasana
            Jan 24 at 13:17











          • I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

            – Zoltan
            Jan 24 at 15:54
















          8












          8








          8







          You should repeat the column name for each value in the query



          "H1" = '31p' or "H1" = '34n' ...


          You had better to use "in" operator like



          "H1" in ('31p', '34n', '31q', '61f')





          share|improve this answer















          You should repeat the column name for each value in the query



          "H1" = '31p' or "H1" = '34n' ...


          You had better to use "in" operator like



          "H1" in ('31p', '34n', '31q', '61f')






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 24 at 11:40









          BERA

          16.1k52042




          16.1k52042










          answered Jan 24 at 11:09









          ZoltanZoltan

          3,309917




          3,309917













          • The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

            – dmasana
            Jan 24 at 13:17











          • I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

            – Zoltan
            Jan 24 at 15:54





















          • The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

            – dmasana
            Jan 24 at 13:17











          • I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

            – Zoltan
            Jan 24 at 15:54



















          The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

          – dmasana
          Jan 24 at 13:17





          The first way you suggested doesn't work (I had already tried). But I was able to do it with the "in" operator. Thanks

          – dmasana
          Jan 24 at 13:17













          I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

          – Zoltan
          Jan 24 at 15:54







          I put here the whole expression: "H1" = '31p' OR "H1" = '34n' OR "H1" = '61f' OR "H1" = '31q' it will work.

          – Zoltan
          Jan 24 at 15:54




















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