Asymptotes Parallel to the axes.
0
$begingroup$
I need proof of this theorem.
Theorem: A straight line $y=c$ is an asymptote of a curve $f(x,y)=0$ iff $y - c$ is a factor of the co-efficient of the highest power of $x$ in $f (x,y)$.
functions rational-functions
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
$endgroup$
add a comment |
0
$begingroup$
I need proof of this theorem.
Theorem: A straight line $y=c$ is an asymptote of a curve $f(x,y)=0$ iff $y - c$ is a factor of the co-efficient of the highest power of $x$ in $f (x,y)$.
functions rational-functions
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
$endgroup$
$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54
add a comment |
0
0
0
$begingroup$
I need proof of this theorem.
Theorem: A straight line $y=c$ is an asymptote of a curve $f(x,y)=0$ iff $y - c$ is a factor of the co-efficient of the highest power of $x$ in $f (x,y)$.
functions rational-functions
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
$endgroup$
I need proof of this theorem.
Theorem: A straight line $y=c$ is an asymptote of a curve $f(x,y)=0$ iff $y - c$ is a factor of the co-efficient of the highest power of $x$ in $f (x,y)$.
functions rational-functions
functions rational-functions
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
edited Jan 9 at 16:31
N. F. Taussig
44.5k93357
44.5k93357
asked Jan 9 at 16:10
KatakuriKatakuri
1
asked Jan 9 at 16:10
KatakuriKatakuri
1
asked Jan 9 at 16:10
KatakuriKatakuri
1
1
$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54
add a comment |
$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54
$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54
add a comment |
0
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$begingroup$
Do you assume that $f(x,y)$ is a polynomial?
$endgroup$
– Andrei
Jan 9 at 16:24
$begingroup$
@Andrei , Yes f(x,y) is a polynomial.
$endgroup$
– Katakuri
Jan 9 at 17:43
$begingroup$
@Andrei can you provide me the proof?
$endgroup$
– Katakuri
Jan 11 at 12:54