Consider the order $mathbb{Z}[sqrt[4]{24}]$. Find all ideals of norm 100.
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I have found that the ring of integers is $mathbb{Z}[alpha, alpha^3/4]$ where $alpha = sqrt[4]{24}$. I also know that in the ring of integers $(5)$ factors as two ideals of norm $25$, and $(2)$ factors as $(2, alpha)^4$ hence there are 2 ideals of norm $100$. How does this help me find the ideals of norm $100$ in the smaller order (where there is no longer unique factorization in prime ideals)?
I know there still is a primary decomposition of any ideal but I don't see how to find all ideals of norm $8$ above $(2)$ in $mathbb{Z}[alpha]$ for example.
algebraic-number-theory norm ideals
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add a comment |
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I have found that the ring of integers is $mathbb{Z}[alpha, alpha^3/4]$ where $alpha = sqrt[4]{24}$. I also know that in the ring of integers $(5)$ factors as two ideals of norm $25$, and $(2)$ factors as $(2, alpha)^4$ hence there are 2 ideals of norm $100$. How does this help me find the ideals of norm $100$ in the smaller order (where there is no longer unique factorization in prime ideals)?
I know there still is a primary decomposition of any ideal but I don't see how to find all ideals of norm $8$ above $(2)$ in $mathbb{Z}[alpha]$ for example.
algebraic-number-theory norm ideals
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Does that help? What do you mean?
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– Rubisk
Jan 16 at 19:01
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Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
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– Rubisk
Jan 19 at 21:38
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Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57
add a comment |
$begingroup$
I have found that the ring of integers is $mathbb{Z}[alpha, alpha^3/4]$ where $alpha = sqrt[4]{24}$. I also know that in the ring of integers $(5)$ factors as two ideals of norm $25$, and $(2)$ factors as $(2, alpha)^4$ hence there are 2 ideals of norm $100$. How does this help me find the ideals of norm $100$ in the smaller order (where there is no longer unique factorization in prime ideals)?
I know there still is a primary decomposition of any ideal but I don't see how to find all ideals of norm $8$ above $(2)$ in $mathbb{Z}[alpha]$ for example.
algebraic-number-theory norm ideals
$endgroup$
I have found that the ring of integers is $mathbb{Z}[alpha, alpha^3/4]$ where $alpha = sqrt[4]{24}$. I also know that in the ring of integers $(5)$ factors as two ideals of norm $25$, and $(2)$ factors as $(2, alpha)^4$ hence there are 2 ideals of norm $100$. How does this help me find the ideals of norm $100$ in the smaller order (where there is no longer unique factorization in prime ideals)?
I know there still is a primary decomposition of any ideal but I don't see how to find all ideals of norm $8$ above $(2)$ in $mathbb{Z}[alpha]$ for example.
algebraic-number-theory norm ideals
algebraic-number-theory norm ideals
edited Jan 19 at 21:39
Rubisk
asked Jan 16 at 17:02
RubiskRubisk
112
112
$begingroup$
Does that help? What do you mean?
$endgroup$
– Rubisk
Jan 16 at 19:01
$begingroup$
Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
$endgroup$
– Rubisk
Jan 19 at 21:38
$begingroup$
Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57
add a comment |
$begingroup$
Does that help? What do you mean?
$endgroup$
– Rubisk
Jan 16 at 19:01
$begingroup$
Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
$endgroup$
– Rubisk
Jan 19 at 21:38
$begingroup$
Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57
$begingroup$
Does that help? What do you mean?
$endgroup$
– Rubisk
Jan 16 at 19:01
$begingroup$
Does that help? What do you mean?
$endgroup$
– Rubisk
Jan 16 at 19:01
$begingroup$
Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
$endgroup$
– Rubisk
Jan 19 at 21:38
$begingroup$
Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
$endgroup$
– Rubisk
Jan 19 at 21:38
$begingroup$
Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57
$begingroup$
Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57
add a comment |
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$begingroup$
Does that help? What do you mean?
$endgroup$
– Rubisk
Jan 16 at 19:01
$begingroup$
Why? Couldn't an ideal of norm 100 contract to an ideal of norm 25 or something? And I am talking about the non-maximal order $mathbf{Z}[sqrt[4]{24}]$ (the cuberoot is a typo I dont know how to fix).
$endgroup$
– Rubisk
Jan 19 at 21:38
$begingroup$
Assuming the class group is trivial?
$endgroup$
– Rubisk
Jan 19 at 21:57