How to find $ iiint_{S} xyz; dx dy dz$ for a given set $S$?












1












$begingroup$



Define the set
$
S:={(x,y,z)in mathbb R^{3}:-3<z<1,x^{2}+y^{2}=36}
$

Find the integral
$$
iiint_{S} xyz; dx dy dz.
$$




I am struggling with the equality $x^{2}+y^{2}=36$; I have only encountered inequalities until now: $x^{2}+y^{2}leq36$ would be easy, as



$$
int_{-3}^{1}int_{0}^{6}int_{-sqrt{36-y^2}}^{sqrt{36-y^2}}(xyz);dxdydz
$$



(I hope this is correct for the inequality case) But how can I treat equality $x^{2}+y^{2}=36$?










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$endgroup$








  • 1




    $begingroup$
    $S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
    $endgroup$
    – Will M.
    Jan 15 at 1:02


















1












$begingroup$



Define the set
$
S:={(x,y,z)in mathbb R^{3}:-3<z<1,x^{2}+y^{2}=36}
$

Find the integral
$$
iiint_{S} xyz; dx dy dz.
$$




I am struggling with the equality $x^{2}+y^{2}=36$; I have only encountered inequalities until now: $x^{2}+y^{2}leq36$ would be easy, as



$$
int_{-3}^{1}int_{0}^{6}int_{-sqrt{36-y^2}}^{sqrt{36-y^2}}(xyz);dxdydz
$$



(I hope this is correct for the inequality case) But how can I treat equality $x^{2}+y^{2}=36$?










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    $S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
    $endgroup$
    – Will M.
    Jan 15 at 1:02
















1












1








1





$begingroup$



Define the set
$
S:={(x,y,z)in mathbb R^{3}:-3<z<1,x^{2}+y^{2}=36}
$

Find the integral
$$
iiint_{S} xyz; dx dy dz.
$$




I am struggling with the equality $x^{2}+y^{2}=36$; I have only encountered inequalities until now: $x^{2}+y^{2}leq36$ would be easy, as



$$
int_{-3}^{1}int_{0}^{6}int_{-sqrt{36-y^2}}^{sqrt{36-y^2}}(xyz);dxdydz
$$



(I hope this is correct for the inequality case) But how can I treat equality $x^{2}+y^{2}=36$?










share|cite|improve this question











$endgroup$





Define the set
$
S:={(x,y,z)in mathbb R^{3}:-3<z<1,x^{2}+y^{2}=36}
$

Find the integral
$$
iiint_{S} xyz; dx dy dz.
$$




I am struggling with the equality $x^{2}+y^{2}=36$; I have only encountered inequalities until now: $x^{2}+y^{2}leq36$ would be easy, as



$$
int_{-3}^{1}int_{0}^{6}int_{-sqrt{36-y^2}}^{sqrt{36-y^2}}(xyz);dxdydz
$$



(I hope this is correct for the inequality case) But how can I treat equality $x^{2}+y^{2}=36$?







real-analysis integration multivariable-calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 15 at 2:19







user587192

















asked Jan 15 at 0:59









SABOYSABOY

683311




683311








  • 1




    $begingroup$
    $S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
    $endgroup$
    – Will M.
    Jan 15 at 1:02
















  • 1




    $begingroup$
    $S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
    $endgroup$
    – Will M.
    Jan 15 at 1:02










1




1




$begingroup$
$S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
$endgroup$
– Will M.
Jan 15 at 1:02






$begingroup$
$S$ is the sheet that forms a cylinder. What are you struggling with? Its has volume zero. There is probably a typo.
$endgroup$
– Will M.
Jan 15 at 1:02












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