Decrease in temperature of a aqueous salt solution decreases conductivity
$begingroup$
Why does the conductivity of a water solution drop as the temperature decreases?
How are these two related?
aqueous-solution solutions temperature conductivity
edited Feb 4 at 1:21
uhoh
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
$endgroup$
add a comment |
$begingroup$
Why does the conductivity of a water solution drop as the temperature decreases?
How are these two related?
aqueous-solution solutions temperature conductivity
edited Feb 4 at 1:21
uhoh
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
$endgroup$
$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42
add a comment |
$begingroup$
Why does the conductivity of a water solution drop as the temperature decreases?
How are these two related?
aqueous-solution solutions temperature conductivity
edited Feb 4 at 1:21
uhoh
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
$endgroup$
Why does the conductivity of a water solution drop as the temperature decreases?
How are these two related?
aqueous-solution solutions temperature conductivity
aqueous-solution solutions temperature conductivity
edited Feb 4 at 1:21
uhoh
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
edited Feb 4 at 1:21
uhoh
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
edited Feb 4 at 1:21
uhoh
1,746840
edited Feb 4 at 1:21
uhoh
1,746840
edited Feb 4 at 1:21
uhoh
1,746840
1,746840
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
asked Feb 3 at 16:46
Tonakis2108Tonakis2108
1519
1519
$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42
add a comment |
$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42
$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
According to the Stokes-Einstein-Debye theory, and assuming the ionic composition remains constant (say for a fully dissociated salt), the main factor accounting for the response of the conductivity to temperature is the change in the viscosity of the solvent.
In the SED theory the frictional drag coefficient $f$ of a charged particle is proportional to the viscosity $eta$:
$$ f propto eta$$
As a result the electrical mobility $mu$ of an ion of charge $q$ is inversely proportional to the viscosity, since
$$ mu =q/fpropto eta^{-1}$$
and since the specific conductance $ kappa$ depends linearly on the mobilities (approximately, at constant ionic strength), $$ kappa propto eta^{-1}$$
Since the viscosity usually increases with decreasing temperature, the conductivity decreases.
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
$endgroup$
add a comment |
$begingroup$
Decrease in temperature has two effects, both attributing to lower electrolytic conductivity:
decreases the mobility of the charge carriers (e.g. $ce{H3O+}$ and $ce{OH-}$ for pure water);
suppresses auto-ionization of water (higher $mathrm{p}K_mathrm{w}$), reducing the total number of charge carriers.
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
According to the Stokes-Einstein-Debye theory, and assuming the ionic composition remains constant (say for a fully dissociated salt), the main factor accounting for the response of the conductivity to temperature is the change in the viscosity of the solvent.
In the SED theory the frictional drag coefficient $f$ of a charged particle is proportional to the viscosity $eta$:
$$ f propto eta$$
As a result the electrical mobility $mu$ of an ion of charge $q$ is inversely proportional to the viscosity, since
$$ mu =q/fpropto eta^{-1}$$
and since the specific conductance $ kappa$ depends linearly on the mobilities (approximately, at constant ionic strength), $$ kappa propto eta^{-1}$$
Since the viscosity usually increases with decreasing temperature, the conductivity decreases.
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
$endgroup$
add a comment |
$begingroup$
According to the Stokes-Einstein-Debye theory, and assuming the ionic composition remains constant (say for a fully dissociated salt), the main factor accounting for the response of the conductivity to temperature is the change in the viscosity of the solvent.
In the SED theory the frictional drag coefficient $f$ of a charged particle is proportional to the viscosity $eta$:
$$ f propto eta$$
As a result the electrical mobility $mu$ of an ion of charge $q$ is inversely proportional to the viscosity, since
$$ mu =q/fpropto eta^{-1}$$
and since the specific conductance $ kappa$ depends linearly on the mobilities (approximately, at constant ionic strength), $$ kappa propto eta^{-1}$$
Since the viscosity usually increases with decreasing temperature, the conductivity decreases.
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
$endgroup$
add a comment |
$begingroup$
According to the Stokes-Einstein-Debye theory, and assuming the ionic composition remains constant (say for a fully dissociated salt), the main factor accounting for the response of the conductivity to temperature is the change in the viscosity of the solvent.
In the SED theory the frictional drag coefficient $f$ of a charged particle is proportional to the viscosity $eta$:
$$ f propto eta$$
As a result the electrical mobility $mu$ of an ion of charge $q$ is inversely proportional to the viscosity, since
$$ mu =q/fpropto eta^{-1}$$
and since the specific conductance $ kappa$ depends linearly on the mobilities (approximately, at constant ionic strength), $$ kappa propto eta^{-1}$$
Since the viscosity usually increases with decreasing temperature, the conductivity decreases.
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
$endgroup$
According to the Stokes-Einstein-Debye theory, and assuming the ionic composition remains constant (say for a fully dissociated salt), the main factor accounting for the response of the conductivity to temperature is the change in the viscosity of the solvent.
In the SED theory the frictional drag coefficient $f$ of a charged particle is proportional to the viscosity $eta$:
$$ f propto eta$$
As a result the electrical mobility $mu$ of an ion of charge $q$ is inversely proportional to the viscosity, since
$$ mu =q/fpropto eta^{-1}$$
and since the specific conductance $ kappa$ depends linearly on the mobilities (approximately, at constant ionic strength), $$ kappa propto eta^{-1}$$
Since the viscosity usually increases with decreasing temperature, the conductivity decreases.
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
edited Feb 3 at 19:51
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
answered Feb 3 at 19:20
Night WriterNight Writer
2,243222
2,243222
add a comment |
add a comment |
$begingroup$
Decrease in temperature has two effects, both attributing to lower electrolytic conductivity:
decreases the mobility of the charge carriers (e.g. $ce{H3O+}$ and $ce{OH-}$ for pure water);
suppresses auto-ionization of water (higher $mathrm{p}K_mathrm{w}$), reducing the total number of charge carriers.
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
$endgroup$
add a comment |
$begingroup$
Decrease in temperature has two effects, both attributing to lower electrolytic conductivity:
decreases the mobility of the charge carriers (e.g. $ce{H3O+}$ and $ce{OH-}$ for pure water);
suppresses auto-ionization of water (higher $mathrm{p}K_mathrm{w}$), reducing the total number of charge carriers.
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
$endgroup$
add a comment |
$begingroup$
Decrease in temperature has two effects, both attributing to lower electrolytic conductivity:
decreases the mobility of the charge carriers (e.g. $ce{H3O+}$ and $ce{OH-}$ for pure water);
suppresses auto-ionization of water (higher $mathrm{p}K_mathrm{w}$), reducing the total number of charge carriers.
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
$endgroup$
Decrease in temperature has two effects, both attributing to lower electrolytic conductivity:
decreases the mobility of the charge carriers (e.g. $ce{H3O+}$ and $ce{OH-}$ for pure water);
suppresses auto-ionization of water (higher $mathrm{p}K_mathrm{w}$), reducing the total number of charge carriers.
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
answered Feb 3 at 17:19
andseliskandselisk
18.1k656119
18.1k656119
add a comment |
add a comment |
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$begingroup$
I'm in the middle of understanding the relation since it's a question made by my professor at the university. There is no data to compare yet although I would be glad to provide a much more detailed question to help others who may read this.
$endgroup$
– Tonakis2108
Feb 3 at 17:28
$begingroup$
I've asked a follow-up question: Is there an electronic component to water conductivity?
$endgroup$
– uhoh
Feb 4 at 0:42