Help with a limit (without L'Hopital): $lim_{xto 0^+} x^{sin x}$ [closed]












-3














What is the limit?
$$lim_{xto 0^+} x^{sin x }$$










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closed as off-topic by Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad Dec 27 '18 at 12:08


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 27 '18 at 9:28










  • Here's a MathJax tutorial :)
    – Shaun
    Dec 27 '18 at 9:41
















-3














What is the limit?
$$lim_{xto 0^+} x^{sin x }$$










share|cite|improve this question









New contributor




Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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closed as off-topic by Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad Dec 27 '18 at 12:08


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 27 '18 at 9:28










  • Here's a MathJax tutorial :)
    – Shaun
    Dec 27 '18 at 9:41














-3












-3








-3







What is the limit?
$$lim_{xto 0^+} x^{sin x }$$










share|cite|improve this question









New contributor




Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











What is the limit?
$$lim_{xto 0^+} x^{sin x }$$







calculus limits trigonometry limits-without-lhopital






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Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question









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edited Dec 27 '18 at 10:49









Blue

47.6k870151




47.6k870151






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Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Dec 27 '18 at 9:24









Amit Yeffet

12




12




New contributor




Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Amit Yeffet is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




closed as off-topic by Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad Dec 27 '18 at 12:08


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad Dec 27 '18 at 12:08


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Henrik, Eevee Trainer, Shaun, Davide Giraudo, Saad

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 27 '18 at 9:28










  • Here's a MathJax tutorial :)
    – Shaun
    Dec 27 '18 at 9:41


















  • Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 27 '18 at 9:28










  • Here's a MathJax tutorial :)
    – Shaun
    Dec 27 '18 at 9:41
















Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Dec 27 '18 at 9:28




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Dec 27 '18 at 9:28












Here's a MathJax tutorial :)
– Shaun
Dec 27 '18 at 9:41




Here's a MathJax tutorial :)
– Shaun
Dec 27 '18 at 9:41










2 Answers
2






active

oldest

votes


















7














Rewrite as
$$
x^{sin x}=e^{sin xlog x}=e^{frac{sin x}{x}(xlog x)}
$$

and using $sin x/xto 1$ and $xlog xto 0$, the limit is $e^0=1$.






share|cite|improve this answer





























    1














    Hint: Use the expansion for $sin x$.



    $$sin x = x-frac{x^3}{3!}+frac{x^5}{5!}-…$$



    Apply this to



    $$x^{sin x}$$



    and let $x to 0^+$. Also, note that



    $$lim_{ x to 0^+} x^x = 1$$






    share|cite|improve this answer






























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      7














      Rewrite as
      $$
      x^{sin x}=e^{sin xlog x}=e^{frac{sin x}{x}(xlog x)}
      $$

      and using $sin x/xto 1$ and $xlog xto 0$, the limit is $e^0=1$.






      share|cite|improve this answer


























        7














        Rewrite as
        $$
        x^{sin x}=e^{sin xlog x}=e^{frac{sin x}{x}(xlog x)}
        $$

        and using $sin x/xto 1$ and $xlog xto 0$, the limit is $e^0=1$.






        share|cite|improve this answer
























          7












          7








          7






          Rewrite as
          $$
          x^{sin x}=e^{sin xlog x}=e^{frac{sin x}{x}(xlog x)}
          $$

          and using $sin x/xto 1$ and $xlog xto 0$, the limit is $e^0=1$.






          share|cite|improve this answer












          Rewrite as
          $$
          x^{sin x}=e^{sin xlog x}=e^{frac{sin x}{x}(xlog x)}
          $$

          and using $sin x/xto 1$ and $xlog xto 0$, the limit is $e^0=1$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 27 '18 at 9:28









          Pierpaolo Vivo

          5,3962624




          5,3962624























              1














              Hint: Use the expansion for $sin x$.



              $$sin x = x-frac{x^3}{3!}+frac{x^5}{5!}-…$$



              Apply this to



              $$x^{sin x}$$



              and let $x to 0^+$. Also, note that



              $$lim_{ x to 0^+} x^x = 1$$






              share|cite|improve this answer




























                1














                Hint: Use the expansion for $sin x$.



                $$sin x = x-frac{x^3}{3!}+frac{x^5}{5!}-…$$



                Apply this to



                $$x^{sin x}$$



                and let $x to 0^+$. Also, note that



                $$lim_{ x to 0^+} x^x = 1$$






                share|cite|improve this answer


























                  1












                  1








                  1






                  Hint: Use the expansion for $sin x$.



                  $$sin x = x-frac{x^3}{3!}+frac{x^5}{5!}-…$$



                  Apply this to



                  $$x^{sin x}$$



                  and let $x to 0^+$. Also, note that



                  $$lim_{ x to 0^+} x^x = 1$$






                  share|cite|improve this answer














                  Hint: Use the expansion for $sin x$.



                  $$sin x = x-frac{x^3}{3!}+frac{x^5}{5!}-…$$



                  Apply this to



                  $$x^{sin x}$$



                  and let $x to 0^+$. Also, note that



                  $$lim_{ x to 0^+} x^x = 1$$







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Dec 27 '18 at 9:33

























                  answered Dec 27 '18 at 9:28









                  KM101

                  5,0391423




                  5,0391423















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