Ric curvature and second fundamental form.












0












$begingroup$


Suppose $M$ is a minimal submanifod in $mathbb{R}^{n+1}$, by Gauss equation we have
$$operatorname{Ric}_Mgeq -|A|^2$$.



I have done similar calculations for surface in $mathbb{R}^3$. But it seems different, and here codimension is bigger than 1, I am kinda stuck. If anyone is familar with this calculation, could you show me some details?










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$endgroup$












  • $begingroup$
    What exactly are you trying to calculate?
    $endgroup$
    – Arctic Char
    Jan 23 at 23:22










  • $begingroup$
    Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
    $endgroup$
    – STUDENT
    Jan 25 at 1:50
















0












$begingroup$


Suppose $M$ is a minimal submanifod in $mathbb{R}^{n+1}$, by Gauss equation we have
$$operatorname{Ric}_Mgeq -|A|^2$$.



I have done similar calculations for surface in $mathbb{R}^3$. But it seems different, and here codimension is bigger than 1, I am kinda stuck. If anyone is familar with this calculation, could you show me some details?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What exactly are you trying to calculate?
    $endgroup$
    – Arctic Char
    Jan 23 at 23:22










  • $begingroup$
    Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
    $endgroup$
    – STUDENT
    Jan 25 at 1:50














0












0








0





$begingroup$


Suppose $M$ is a minimal submanifod in $mathbb{R}^{n+1}$, by Gauss equation we have
$$operatorname{Ric}_Mgeq -|A|^2$$.



I have done similar calculations for surface in $mathbb{R}^3$. But it seems different, and here codimension is bigger than 1, I am kinda stuck. If anyone is familar with this calculation, could you show me some details?










share|cite|improve this question









$endgroup$




Suppose $M$ is a minimal submanifod in $mathbb{R}^{n+1}$, by Gauss equation we have
$$operatorname{Ric}_Mgeq -|A|^2$$.



I have done similar calculations for surface in $mathbb{R}^3$. But it seems different, and here codimension is bigger than 1, I am kinda stuck. If anyone is familar with this calculation, could you show me some details?







riemannian-geometry






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 19 at 5:18









STUDENTSTUDENT

1207




1207












  • $begingroup$
    What exactly are you trying to calculate?
    $endgroup$
    – Arctic Char
    Jan 23 at 23:22










  • $begingroup$
    Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
    $endgroup$
    – STUDENT
    Jan 25 at 1:50


















  • $begingroup$
    What exactly are you trying to calculate?
    $endgroup$
    – Arctic Char
    Jan 23 at 23:22










  • $begingroup$
    Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
    $endgroup$
    – STUDENT
    Jan 25 at 1:50
















$begingroup$
What exactly are you trying to calculate?
$endgroup$
– Arctic Char
Jan 23 at 23:22




$begingroup$
What exactly are you trying to calculate?
$endgroup$
– Arctic Char
Jan 23 at 23:22












$begingroup$
Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
$endgroup$
– STUDENT
Jan 25 at 1:50




$begingroup$
Oh, I want to prove above inequality. But I have proved it myself after some help. Thanks for your interest.
$endgroup$
– STUDENT
Jan 25 at 1:50










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