how to sort the expression not based on the Heads in Times?
4
$begingroup$
Is there any way i can sort the following expression ?
a[k, l] b[i, j]
so that i would have:
b[i, j] a[k,l]
Mathematica does the ordering based on the heads. is there anyway to change it ?
sorting
asked Feb 7 at 15:08
user49047user49047
405213
$endgroup$
add a comment |
4
$begingroup$
Is there any way i can sort the following expression ?
a[k, l] b[i, j]
so that i would have:
b[i, j] a[k,l]
Mathematica does the ordering based on the heads. is there anyway to change it ?
sorting
asked Feb 7 at 15:08
user49047user49047
405213
$endgroup$
$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
1
$begingroup$
The expression you show here has headTimes: spaces are interpreted as multiplication (useFullFormto check if you're unsure).Timesis a symbol with the attributeOrderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want isInactivate[b[i, j] a[k, l], Times]
$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]
$endgroup$
– Bob Hanlon
Feb 7 at 16:29
add a comment |
4
4
4
$begingroup$
Is there any way i can sort the following expression ?
a[k, l] b[i, j]
so that i would have:
b[i, j] a[k,l]
Mathematica does the ordering based on the heads. is there anyway to change it ?
sorting
asked Feb 7 at 15:08
user49047user49047
405213
$endgroup$
Is there any way i can sort the following expression ?
a[k, l] b[i, j]
so that i would have:
b[i, j] a[k,l]
Mathematica does the ordering based on the heads. is there anyway to change it ?
sorting
sorting
asked Feb 7 at 15:08
user49047user49047
405213
asked Feb 7 at 15:08
user49047user49047
405213
edited Feb 8 at 11:18
user49047
asked Feb 7 at 15:08
user49047user49047
405213
asked Feb 7 at 15:08
user49047user49047
405213
asked Feb 7 at 15:08
user49047user49047
405213
405213
$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
1
$begingroup$
The expression you show here has headTimes: spaces are interpreted as multiplication (useFullFormto check if you're unsure).Timesis a symbol with the attributeOrderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want isInactivate[b[i, j] a[k, l], Times]
$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]
$endgroup$
– Bob Hanlon
Feb 7 at 16:29
add a comment |
$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
1
$begingroup$
The expression you show here has headTimes: spaces are interpreted as multiplication (useFullFormto check if you're unsure).Timesis a symbol with the attributeOrderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want isInactivate[b[i, j] a[k, l], Times]
$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]
$endgroup$
– Bob Hanlon
Feb 7 at 16:29
$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
1
1
$begingroup$
The expression you show here has head
Times: spaces are interpreted as multiplication (use FullForm to check if you're unsure). Times is a symbol with the attribute Orderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want is Inactivate[b[i, j] a[k, l], Times]$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
The expression you show here has head
Times: spaces are interpreted as multiplication (use FullForm to check if you're unsure). Times is a symbol with the attribute Orderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want is Inactivate[b[i, j] a[k, l], Times]$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]$endgroup$
– Bob Hanlon
Feb 7 at 16:29
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]$endgroup$
– Bob Hanlon
Feb 7 at 16:29
add a comment |
2 Answers
2
active
oldest
votes
5
$begingroup$
with the help of Bob Hanlon:
axx = HoldForm[
NonCommutativeMultiply @@
SortBy[List @@ (a[k, l] b[i, j]), First]] // ReleaseHold
axx //. NonCommutativeMultiply[a_, Y___] :> HoldForm[Times[a, Y]]
answered Feb 7 at 16:47
user49047user49047
405213
$endgroup$
add a comment |
0
$begingroup$
SortBy[Inactivate[a[m, n] b[i, j] c[k, l], Times], Function[x, #[[x]]]/@ Range[Length@#]&] /.
Inactive[Times] -> HoldForm@*Times
b[i,j] c[k,l] a[m,n]
answered Feb 8 at 0:13
kglrkglr
190k10206424
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
$begingroup$
with the help of Bob Hanlon:
axx = HoldForm[
NonCommutativeMultiply @@
SortBy[List @@ (a[k, l] b[i, j]), First]] // ReleaseHold
axx //. NonCommutativeMultiply[a_, Y___] :> HoldForm[Times[a, Y]]
answered Feb 7 at 16:47
user49047user49047
405213
$endgroup$
add a comment |
5
$begingroup$
with the help of Bob Hanlon:
axx = HoldForm[
NonCommutativeMultiply @@
SortBy[List @@ (a[k, l] b[i, j]), First]] // ReleaseHold
axx //. NonCommutativeMultiply[a_, Y___] :> HoldForm[Times[a, Y]]
answered Feb 7 at 16:47
user49047user49047
405213
$endgroup$
add a comment |
5
5
5
$begingroup$
with the help of Bob Hanlon:
axx = HoldForm[
NonCommutativeMultiply @@
SortBy[List @@ (a[k, l] b[i, j]), First]] // ReleaseHold
axx //. NonCommutativeMultiply[a_, Y___] :> HoldForm[Times[a, Y]]
answered Feb 7 at 16:47
user49047user49047
405213
$endgroup$
with the help of Bob Hanlon:
axx = HoldForm[
NonCommutativeMultiply @@
SortBy[List @@ (a[k, l] b[i, j]), First]] // ReleaseHold
axx //. NonCommutativeMultiply[a_, Y___] :> HoldForm[Times[a, Y]]
answered Feb 7 at 16:47
user49047user49047
405213
answered Feb 7 at 16:47
user49047user49047
405213
answered Feb 7 at 16:47
user49047user49047
405213
answered Feb 7 at 16:47
user49047user49047
405213
405213
add a comment |
add a comment |
0
$begingroup$
SortBy[Inactivate[a[m, n] b[i, j] c[k, l], Times], Function[x, #[[x]]]/@ Range[Length@#]&] /.
Inactive[Times] -> HoldForm@*Times
b[i,j] c[k,l] a[m,n]
answered Feb 8 at 0:13
kglrkglr
190k10206424
$endgroup$
add a comment |
0
$begingroup$
SortBy[Inactivate[a[m, n] b[i, j] c[k, l], Times], Function[x, #[[x]]]/@ Range[Length@#]&] /.
Inactive[Times] -> HoldForm@*Times
b[i,j] c[k,l] a[m,n]
answered Feb 8 at 0:13
kglrkglr
190k10206424
$endgroup$
add a comment |
0
0
0
$begingroup$
SortBy[Inactivate[a[m, n] b[i, j] c[k, l], Times], Function[x, #[[x]]]/@ Range[Length@#]&] /.
Inactive[Times] -> HoldForm@*Times
b[i,j] c[k,l] a[m,n]
answered Feb 8 at 0:13
kglrkglr
190k10206424
$endgroup$
SortBy[Inactivate[a[m, n] b[i, j] c[k, l], Times], Function[x, #[[x]]]/@ Range[Length@#]&] /.
Inactive[Times] -> HoldForm@*Times
b[i,j] c[k,l] a[m,n]
answered Feb 8 at 0:13
kglrkglr
190k10206424
answered Feb 8 at 0:13
kglrkglr
190k10206424
answered Feb 8 at 0:13
kglrkglr
190k10206424
answered Feb 8 at 0:13
kglrkglr
190k10206424
190k10206424
add a comment |
add a comment |
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$begingroup$
To be clear: you are seeking a way to sort the elements of that expression based on the lexicographical ordering of the arguments to those elements ?
$endgroup$
– High Performance Mark
Feb 7 at 15:33
$begingroup$
@High Performance Mark i want to order the expression based on their arguments rather than the heads. so if i have a[m,n] b[i,j] c[k,l] i want it to be like b[i,j] c[k,l] a[m,n]
$endgroup$
– user49047
Feb 7 at 16:15
1
$begingroup$
The expression you show here has head
Times: spaces are interpreted as multiplication (useFullFormto check if you're unsure).Timesis a symbol with the attributeOrderless, meaning that it will always sort its arguments in canonical order. The only way to have something close to what you want isInactivate[b[i, j] a[k, l], Times]$endgroup$
– Sjoerd Smit
Feb 7 at 16:15
$begingroup$
Inactive[Times] @@ SortBy[List @@ expr, First]$endgroup$
– Bob Hanlon
Feb 7 at 16:29