How to reverse values in a reciprocal
0
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How do i reverse the values of a reciprocal so that at 0 the speed of light the reciprocal is 0.0 and near at the speed of light the reciprocal is 1. Basically I want to reverse the values in the third column.
inverse
asked Jan 7 at 3:58
AneikeiAneikei
222
$endgroup$
add a comment |
0
$begingroup$
How do i reverse the values of a reciprocal so that at 0 the speed of light the reciprocal is 0.0 and near at the speed of light the reciprocal is 1. Basically I want to reverse the values in the third column.
inverse
asked Jan 7 at 3:58
AneikeiAneikei
222
$endgroup$
2
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34
add a comment |
0
0
0
$begingroup$
How do i reverse the values of a reciprocal so that at 0 the speed of light the reciprocal is 0.0 and near at the speed of light the reciprocal is 1. Basically I want to reverse the values in the third column.
inverse
asked Jan 7 at 3:58
AneikeiAneikei
222
$endgroup$
How do i reverse the values of a reciprocal so that at 0 the speed of light the reciprocal is 0.0 and near at the speed of light the reciprocal is 1. Basically I want to reverse the values in the third column.
inverse
inverse
asked Jan 7 at 3:58
AneikeiAneikei
222
asked Jan 7 at 3:58
AneikeiAneikei
222
asked Jan 7 at 3:58
AneikeiAneikei
222
asked Jan 7 at 3:58
AneikeiAneikei
222
asked Jan 7 at 3:58
AneikeiAneikei
222
222
2
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34
add a comment |
2
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34
2
2
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34
add a comment |
0
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2
$begingroup$
Have you tried subtracting 1 / $gamma$ from 1, or you could use trignometric functions if you so choose.
$endgroup$
– L. McDonald
Jan 7 at 4:23
$begingroup$
Also, may I ask, why is this important, and you may want to ask further questions on this topic on the physics stack exchange: physics.stackexchange.com.
$endgroup$
– L. McDonald
Jan 7 at 4:25
$begingroup$
Thank you. It's important because I'm working on a new constant.
$endgroup$
– Aneikei
Jan 7 at 5:34