The hcf or gcd of $ a$ and $b$ is $1$ . What is the hcf of the following term? (a^p and b^p)/(a-b) and (a-b)...
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The hcf or gcd of $a$ and $ b$ is $1$.
What is the hcf of the following term?
$dfrac{a^p - b^p}{a-b} $ and $a-b$, where $p $ is a prime number.
I study in grade 9. I can't solve this problem. Can anyone please help me?
number-theory
asked Dec 26 at 12:38
Shrestha Mukherjee
42
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Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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put on hold as off-topic by Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy Dec 26 at 19:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
0
The hcf or gcd of $a$ and $ b$ is $1$.
What is the hcf of the following term?
$dfrac{a^p - b^p}{a-b} $ and $a-b$, where $p $ is a prime number.
I study in grade 9. I can't solve this problem. Can anyone please help me?
number-theory
asked Dec 26 at 12:38
Shrestha Mukherjee
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy Dec 26 at 19:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy
If this question can be reworded to fit the rules in the help center, please edit the question.
3
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28
add a comment |
0
0
0
1
The hcf or gcd of $a$ and $ b$ is $1$.
What is the hcf of the following term?
$dfrac{a^p - b^p}{a-b} $ and $a-b$, where $p $ is a prime number.
I study in grade 9. I can't solve this problem. Can anyone please help me?
number-theory
asked Dec 26 at 12:38
Shrestha Mukherjee
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
The hcf or gcd of $a$ and $ b$ is $1$.
What is the hcf of the following term?
$dfrac{a^p - b^p}{a-b} $ and $a-b$, where $p $ is a prime number.
I study in grade 9. I can't solve this problem. Can anyone please help me?
number-theory
number-theory
asked Dec 26 at 12:38
Shrestha Mukherjee
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 26 at 12:38
Shrestha Mukherjee
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 at 16:38
asked Dec 26 at 12:38
Shrestha Mukherjee
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 26 at 12:38
Shrestha Mukherjee
42
asked Dec 26 at 12:38
Shrestha Mukherjee
42
42
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Shrestha Mukherjee is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy Dec 26 at 19:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy Dec 26 at 19:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Shailesh, Pierre-Guy Plamondon, metamorphy
If this question can be reworded to fit the rules in the help center, please edit the question.
3
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28
add a comment |
3
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28
3
3
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28
add a comment |
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kYm57X,y3b9Bu N43ujfXz31oxmDtHisKh9WkMPI Eb021FECwC,2FE jM1CCEvd,VUP,r
3
What have you tried? As a good starting point, work some examples..try to get a sense of the answer that way and then try to prove your conjecture.
– lulu
Dec 26 at 12:39
@lulu moreover, the expression that OP has provided to find the gcd of is somewhat nonsensical
– Don Thousand
Dec 26 at 12:50
You want $p$ to be an odd prime: the ratio $(a^2 + b^2)(a-b)$ is usually not an integer.
– KCd
Dec 26 at 14:04
@DonThousand True. I assumed the OP meant $frac {a^p-b^p}{a-b}$ but of course, that isn't what appears.
– lulu
Dec 26 at 14:28