About fractional modulus
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I was reading paper and it had some expression modulo $1$, and modulo $frac12$. Could someone explain me what this $2$ things even mean? I'm confused mainly by the fact of divisibility over rationals. Is it maybe something more related to congruence as a property of groups?
group-theory elementary-number-theory
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
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add a comment |
$begingroup$
I was reading paper and it had some expression modulo $1$, and modulo $frac12$. Could someone explain me what this $2$ things even mean? I'm confused mainly by the fact of divisibility over rationals. Is it maybe something more related to congruence as a property of groups?
group-theory elementary-number-theory
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
$endgroup$
add a comment |
$begingroup$
I was reading paper and it had some expression modulo $1$, and modulo $frac12$. Could someone explain me what this $2$ things even mean? I'm confused mainly by the fact of divisibility over rationals. Is it maybe something more related to congruence as a property of groups?
group-theory elementary-number-theory
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
$endgroup$
I was reading paper and it had some expression modulo $1$, and modulo $frac12$. Could someone explain me what this $2$ things even mean? I'm confused mainly by the fact of divisibility over rationals. Is it maybe something more related to congruence as a property of groups?
group-theory elementary-number-theory
group-theory elementary-number-theory
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
asked Jan 7 at 9:49
Bruno AndradesBruno Andrades
1309
1309
add a comment |
add a comment |
1 Answer
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Without any more context I can't be certain, but I don't see any reason it should be different from regular modulus:
$$xequiv y pmod a iff exists nin Bbb Z: n(x-y) = a$$
answered Jan 7 at 10:02
ArthurArthur
115k7116198
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1 Answer
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1 Answer
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$begingroup$
Without any more context I can't be certain, but I don't see any reason it should be different from regular modulus:
$$xequiv y pmod a iff exists nin Bbb Z: n(x-y) = a$$
answered Jan 7 at 10:02
ArthurArthur
115k7116198
$endgroup$
add a comment |
$begingroup$
Without any more context I can't be certain, but I don't see any reason it should be different from regular modulus:
$$xequiv y pmod a iff exists nin Bbb Z: n(x-y) = a$$
answered Jan 7 at 10:02
ArthurArthur
115k7116198
$endgroup$
add a comment |
$begingroup$
Without any more context I can't be certain, but I don't see any reason it should be different from regular modulus:
$$xequiv y pmod a iff exists nin Bbb Z: n(x-y) = a$$
answered Jan 7 at 10:02
ArthurArthur
115k7116198
$endgroup$
Without any more context I can't be certain, but I don't see any reason it should be different from regular modulus:
$$xequiv y pmod a iff exists nin Bbb Z: n(x-y) = a$$
answered Jan 7 at 10:02
ArthurArthur
115k7116198
answered Jan 7 at 10:02
ArthurArthur
115k7116198
answered Jan 7 at 10:02
ArthurArthur
115k7116198
answered Jan 7 at 10:02
ArthurArthur
115k7116198
115k7116198
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