Why Does GraphPlot mislabel Vertices from a Graph?
$begingroup$
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
$endgroup$
add a comment |
$begingroup$
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
$endgroup$
add a comment |
$begingroup$
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
$endgroup$
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
graphs-and-networks
asked Jan 6 at 16:22
tjm167ustjm167us
506211
506211
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
GraphPlot
supports inputs in several different formats. Originally, it took either a list of Rule
s or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot
also takes Graph
expressions as input. But it handles Graph
s by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
$endgroup$
1
$begingroup$
One of SW's Twitch videos showed thatGraphPlot
is being updated for version 12.0, so you can expect this to be fixed.
$endgroup$
– Szabolcs
Jan 6 at 16:35
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f188941%2fwhy-does-graphplot-mislabel-vertices-from-a-graph%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
GraphPlot
supports inputs in several different formats. Originally, it took either a list of Rule
s or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot
also takes Graph
expressions as input. But it handles Graph
s by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
$endgroup$
1
$begingroup$
One of SW's Twitch videos showed thatGraphPlot
is being updated for version 12.0, so you can expect this to be fixed.
$endgroup$
– Szabolcs
Jan 6 at 16:35
add a comment |
$begingroup$
GraphPlot
supports inputs in several different formats. Originally, it took either a list of Rule
s or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot
also takes Graph
expressions as input. But it handles Graph
s by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
$endgroup$
1
$begingroup$
One of SW's Twitch videos showed thatGraphPlot
is being updated for version 12.0, so you can expect this to be fixed.
$endgroup$
– Szabolcs
Jan 6 at 16:35
add a comment |
$begingroup$
GraphPlot
supports inputs in several different formats. Originally, it took either a list of Rule
s or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot
also takes Graph
expressions as input. But it handles Graph
s by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
$endgroup$
GraphPlot
supports inputs in several different formats. Originally, it took either a list of Rule
s or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot
also takes Graph
expressions as input. But it handles Graph
s by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
edited Jan 6 at 18:59
answered Jan 6 at 16:35
SzabolcsSzabolcs
159k13435930
159k13435930
1
$begingroup$
One of SW's Twitch videos showed thatGraphPlot
is being updated for version 12.0, so you can expect this to be fixed.
$endgroup$
– Szabolcs
Jan 6 at 16:35
add a comment |
1
$begingroup$
One of SW's Twitch videos showed thatGraphPlot
is being updated for version 12.0, so you can expect this to be fixed.
$endgroup$
– Szabolcs
Jan 6 at 16:35
1
1
$begingroup$
One of SW's Twitch videos showed that
GraphPlot
is being updated for version 12.0, so you can expect this to be fixed.$endgroup$
– Szabolcs
Jan 6 at 16:35
$begingroup$
One of SW's Twitch videos showed that
GraphPlot
is being updated for version 12.0, so you can expect this to be fixed.$endgroup$
– Szabolcs
Jan 6 at 16:35
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f188941%2fwhy-does-graphplot-mislabel-vertices-from-a-graph%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown