Let $C_1$ and $C_2$ be the zeros of quadratic polynomials $f_1$ and $f_2$ respectively that don't have a...












0












$begingroup$


Artin Algebra Chapter 11



enter image description here



This has been answered here, but my questions are about the solution of Brian Bi:



enter image description here



(a) On proving g is the product of linear polynomials:




  1. It seems Brian Bi deduces the degree of $g$ in y is at most 2 because the degree of $g$ is at most 2. What's the exact relationship here? I think for polynomial $g(x,y)$ and $m ge 1$,


$$deg(g) ge max{deg(g) text{in y},deg(g) text{in x}}$$



Is that correct?




  1. By the way, when we say a polynomial $p$ is any number of variables is linear (quadratic), does that imply $p$ is linear (quadratic) in each of the variables individually? Is the converse true (if it is not the case that the original statement is true by definition)?



  2. It seems Brian Bi has cases for when the degree of $g$ in y is 1 or 2 but not 0. Can we have degree of $g$ in $y$ to be $0$?




    • If we can: If degree of $g$ in $y$ is $0$, so $g$ is a constant, then constant functions are linear so $g$ is a product of a linear polynomial namely itself?


    • If we cannot: why?





(b) On proving $|C_1 cap C_2| le 4$





  1. Is $g$ a common factor of $f_1$ and $f_2$?




    • If so, why, and in the first place, why is $g$ a factor of either?


    • If not, what is the relevance of "don't have a common linear factor" ?




  2. Is the $S_1$ and $S_2$ part implicitly using Exercise 11.9.4?











share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    Artin Algebra Chapter 11



    enter image description here



    This has been answered here, but my questions are about the solution of Brian Bi:



    enter image description here



    (a) On proving g is the product of linear polynomials:




    1. It seems Brian Bi deduces the degree of $g$ in y is at most 2 because the degree of $g$ is at most 2. What's the exact relationship here? I think for polynomial $g(x,y)$ and $m ge 1$,


    $$deg(g) ge max{deg(g) text{in y},deg(g) text{in x}}$$



    Is that correct?




    1. By the way, when we say a polynomial $p$ is any number of variables is linear (quadratic), does that imply $p$ is linear (quadratic) in each of the variables individually? Is the converse true (if it is not the case that the original statement is true by definition)?



    2. It seems Brian Bi has cases for when the degree of $g$ in y is 1 or 2 but not 0. Can we have degree of $g$ in $y$ to be $0$?




      • If we can: If degree of $g$ in $y$ is $0$, so $g$ is a constant, then constant functions are linear so $g$ is a product of a linear polynomial namely itself?


      • If we cannot: why?





    (b) On proving $|C_1 cap C_2| le 4$





    1. Is $g$ a common factor of $f_1$ and $f_2$?




      • If so, why, and in the first place, why is $g$ a factor of either?


      • If not, what is the relevance of "don't have a common linear factor" ?




    2. Is the $S_1$ and $S_2$ part implicitly using Exercise 11.9.4?











    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Artin Algebra Chapter 11



      enter image description here



      This has been answered here, but my questions are about the solution of Brian Bi:



      enter image description here



      (a) On proving g is the product of linear polynomials:




      1. It seems Brian Bi deduces the degree of $g$ in y is at most 2 because the degree of $g$ is at most 2. What's the exact relationship here? I think for polynomial $g(x,y)$ and $m ge 1$,


      $$deg(g) ge max{deg(g) text{in y},deg(g) text{in x}}$$



      Is that correct?




      1. By the way, when we say a polynomial $p$ is any number of variables is linear (quadratic), does that imply $p$ is linear (quadratic) in each of the variables individually? Is the converse true (if it is not the case that the original statement is true by definition)?



      2. It seems Brian Bi has cases for when the degree of $g$ in y is 1 or 2 but not 0. Can we have degree of $g$ in $y$ to be $0$?




        • If we can: If degree of $g$ in $y$ is $0$, so $g$ is a constant, then constant functions are linear so $g$ is a product of a linear polynomial namely itself?


        • If we cannot: why?





      (b) On proving $|C_1 cap C_2| le 4$





      1. Is $g$ a common factor of $f_1$ and $f_2$?




        • If so, why, and in the first place, why is $g$ a factor of either?


        • If not, what is the relevance of "don't have a common linear factor" ?




      2. Is the $S_1$ and $S_2$ part implicitly using Exercise 11.9.4?











      share|cite|improve this question











      $endgroup$




      Artin Algebra Chapter 11



      enter image description here



      This has been answered here, but my questions are about the solution of Brian Bi:



      enter image description here



      (a) On proving g is the product of linear polynomials:




      1. It seems Brian Bi deduces the degree of $g$ in y is at most 2 because the degree of $g$ is at most 2. What's the exact relationship here? I think for polynomial $g(x,y)$ and $m ge 1$,


      $$deg(g) ge max{deg(g) text{in y},deg(g) text{in x}}$$



      Is that correct?




      1. By the way, when we say a polynomial $p$ is any number of variables is linear (quadratic), does that imply $p$ is linear (quadratic) in each of the variables individually? Is the converse true (if it is not the case that the original statement is true by definition)?



      2. It seems Brian Bi has cases for when the degree of $g$ in y is 1 or 2 but not 0. Can we have degree of $g$ in $y$ to be $0$?




        • If we can: If degree of $g$ in $y$ is $0$, so $g$ is a constant, then constant functions are linear so $g$ is a product of a linear polynomial namely itself?


        • If we cannot: why?





      (b) On proving $|C_1 cap C_2| le 4$





      1. Is $g$ a common factor of $f_1$ and $f_2$?




        • If so, why, and in the first place, why is $g$ a factor of either?


        • If not, what is the relevance of "don't have a common linear factor" ?




      2. Is the $S_1$ and $S_2$ part implicitly using Exercise 11.9.4?








      linear-algebra geometry algebraic-geometry polynomials ring-theory






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      edited Dec 30 '18 at 11:14

























      asked Dec 30 '18 at 11:08







      user198044





























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