Calculate $sin20^circcdotcos50^circcdotsin60^circcdotcos10^circ$ [closed]
-7
How to calculate $sin20^circcdotcos50^circcdotsin60^circcdotcos10^circ$?
trigonometry
closed as off-topic by KM101, Shaun, Key Flex, José Carlos Santos, Masacroso Dec 28 '18 at 8:21
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KM101, Shaun, Key Flex, José Carlos Santos, Masacroso
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
-7
How to calculate $sin20^circcdotcos50^circcdotsin60^circcdotcos10^circ$?
trigonometry
closed as off-topic by KM101, Shaun, Key Flex, José Carlos Santos, Masacroso Dec 28 '18 at 8:21
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KM101, Shaun, Key Flex, José Carlos Santos, Masacroso
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53
add a comment |
-7
-7
-7
How to calculate $sin20^circcdotcos50^circcdotsin60^circcdotcos10^circ$?
trigonometry
How to calculate $sin20^circcdotcos50^circcdotsin60^circcdotcos10^circ$?
trigonometry
trigonometry
edited Dec 28 '18 at 8:10
Kemono Chen
2,626437
2,626437
asked Dec 28 '18 at 7:55
Marjan Lukavy
1
1
closed as off-topic by KM101, Shaun, Key Flex, José Carlos Santos, Masacroso Dec 28 '18 at 8:21
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KM101, Shaun, Key Flex, José Carlos Santos, Masacroso
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by KM101, Shaun, Key Flex, José Carlos Santos, Masacroso Dec 28 '18 at 8:21
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KM101, Shaun, Key Flex, José Carlos Santos, Masacroso
If this question can be reworded to fit the rules in the help center, please edit the question.
3
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53
add a comment |
3
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53
3
3
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53
add a comment |
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3
Isn't this equal to $sinleft(20^circright)sinleft(40^circright)sinleft(60^circright)sinleft(80^circright)$?
– robjohn♦
Dec 28 '18 at 8:21
math.stackexchange.com/questions/2874439/… and math.stackexchange.com/questions/1145406/…
– lab bhattacharjee
Dec 28 '18 at 8:38
It's too bad that this question lacks context; it has a pretty nice solution. If context were added, the question could be reopened and answered.
– robjohn♦
Dec 28 '18 at 8:46
In fact, there is a nice closed form for $prodlimits_{k=1}^nsinleft(frac{pi k}{2n+1}right)$. This question is $n=4$. See this answer for the case $n=3$.
– robjohn♦
Dec 28 '18 at 8:53