how much did the trip cost the school
$begingroup$
The 200 seventh graders at John Witherspoon Middle School raised 80%
of the funds needed for a field trip. The school donated the remaining
20%. When they went to purchase the tickets, however, they were given
a 10% bulk rate discount after a $ 20 processing fee. Faced with an
unexpected surplus the students chose to buy each member of the class
one cookie and were still left with 18 dollar, which they gave to the
bus driver. If each of the cookies cost 0.30 dollar, how much did the
trip cost the school?
I solved this problem as follows-
Cost for cookies= 60 * 0.3 = 200
Tips to Bus Driver = 18
Total (Cookies + Bus Driver) = 78
If total cost for the school is x then, $x-.90x-20 = 78$
$Rightarrow$ x= 980
Cost of school= .20*980 = 196
What is wrong in my approach? Correct answer is given as 160!
algebra-precalculus
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
$endgroup$
add a comment |
$begingroup$
The 200 seventh graders at John Witherspoon Middle School raised 80%
of the funds needed for a field trip. The school donated the remaining
20%. When they went to purchase the tickets, however, they were given
a 10% bulk rate discount after a $ 20 processing fee. Faced with an
unexpected surplus the students chose to buy each member of the class
one cookie and were still left with 18 dollar, which they gave to the
bus driver. If each of the cookies cost 0.30 dollar, how much did the
trip cost the school?
I solved this problem as follows-
Cost for cookies= 60 * 0.3 = 200
Tips to Bus Driver = 18
Total (Cookies + Bus Driver) = 78
If total cost for the school is x then, $x-.90x-20 = 78$
$Rightarrow$ x= 980
Cost of school= .20*980 = 196
What is wrong in my approach? Correct answer is given as 160!
algebra-precalculus
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
$endgroup$
add a comment |
$begingroup$
The 200 seventh graders at John Witherspoon Middle School raised 80%
of the funds needed for a field trip. The school donated the remaining
20%. When they went to purchase the tickets, however, they were given
a 10% bulk rate discount after a $ 20 processing fee. Faced with an
unexpected surplus the students chose to buy each member of the class
one cookie and were still left with 18 dollar, which they gave to the
bus driver. If each of the cookies cost 0.30 dollar, how much did the
trip cost the school?
I solved this problem as follows-
Cost for cookies= 60 * 0.3 = 200
Tips to Bus Driver = 18
Total (Cookies + Bus Driver) = 78
If total cost for the school is x then, $x-.90x-20 = 78$
$Rightarrow$ x= 980
Cost of school= .20*980 = 196
What is wrong in my approach? Correct answer is given as 160!
algebra-precalculus
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
$endgroup$
The 200 seventh graders at John Witherspoon Middle School raised 80%
of the funds needed for a field trip. The school donated the remaining
20%. When they went to purchase the tickets, however, they were given
a 10% bulk rate discount after a $ 20 processing fee. Faced with an
unexpected surplus the students chose to buy each member of the class
one cookie and were still left with 18 dollar, which they gave to the
bus driver. If each of the cookies cost 0.30 dollar, how much did the
trip cost the school?
I solved this problem as follows-
Cost for cookies= 60 * 0.3 = 200
Tips to Bus Driver = 18
Total (Cookies + Bus Driver) = 78
If total cost for the school is x then, $x-.90x-20 = 78$
$Rightarrow$ x= 980
Cost of school= .20*980 = 196
What is wrong in my approach? Correct answer is given as 160!
algebra-precalculus
algebra-precalculus
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
asked Sep 17 '16 at 9:53
Mahmudul HasanMahmudul Hasan
4161312
4161312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
The 10% discount is given after a $$20$ processing fee. So $78 = (x-20)*0.1 = 0.1x - 2$. What you said is equivalent to $78 = 0.1x - 20$.
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
$endgroup$
add a comment |
$begingroup$
Let $x$ be the total amount of money contributed by students and the school as follows;
- 200 students contributed $0.8 x$,
- the school contributed $0.2x$,
$$$18 is the remaining amount they gave to the driver,
$$$20 processing fee for purchasing ticket,- 10% discount earned for purchasing the tickets,
$(x-20)0.9$ the money used for purchasing the tickets.
Therefore to solve for $x$, the following applies:
begin{align}
[x-(x-20)0.9+20]-60&=18 \
x-[0.9x-18+20]-60&=18 \
x-0.9x+18-20-60&=18 \
0.1x-62&=18 \
end{align}
Therefore $x= $800$. Since the school contributed 20%, the dollar amount contributed by the school towards the trip is $0.2cdot 800=$160$.
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
$endgroup$
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The 10% discount is given after a $$20$ processing fee. So $78 = (x-20)*0.1 = 0.1x - 2$. What you said is equivalent to $78 = 0.1x - 20$.
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
$endgroup$
add a comment |
$begingroup$
The 10% discount is given after a $$20$ processing fee. So $78 = (x-20)*0.1 = 0.1x - 2$. What you said is equivalent to $78 = 0.1x - 20$.
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
$endgroup$
add a comment |
$begingroup$
The 10% discount is given after a $$20$ processing fee. So $78 = (x-20)*0.1 = 0.1x - 2$. What you said is equivalent to $78 = 0.1x - 20$.
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
$endgroup$
The 10% discount is given after a $$20$ processing fee. So $78 = (x-20)*0.1 = 0.1x - 2$. What you said is equivalent to $78 = 0.1x - 20$.
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
answered Sep 17 '16 at 10:02
DWe1DWe1
60929
60929
add a comment |
add a comment |
$begingroup$
Let $x$ be the total amount of money contributed by students and the school as follows;
- 200 students contributed $0.8 x$,
- the school contributed $0.2x$,
$$$18 is the remaining amount they gave to the driver,
$$$20 processing fee for purchasing ticket,- 10% discount earned for purchasing the tickets,
$(x-20)0.9$ the money used for purchasing the tickets.
Therefore to solve for $x$, the following applies:
begin{align}
[x-(x-20)0.9+20]-60&=18 \
x-[0.9x-18+20]-60&=18 \
x-0.9x+18-20-60&=18 \
0.1x-62&=18 \
end{align}
Therefore $x= $800$. Since the school contributed 20%, the dollar amount contributed by the school towards the trip is $0.2cdot 800=$160$.
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
$endgroup$
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
add a comment |
$begingroup$
Let $x$ be the total amount of money contributed by students and the school as follows;
- 200 students contributed $0.8 x$,
- the school contributed $0.2x$,
$$$18 is the remaining amount they gave to the driver,
$$$20 processing fee for purchasing ticket,- 10% discount earned for purchasing the tickets,
$(x-20)0.9$ the money used for purchasing the tickets.
Therefore to solve for $x$, the following applies:
begin{align}
[x-(x-20)0.9+20]-60&=18 \
x-[0.9x-18+20]-60&=18 \
x-0.9x+18-20-60&=18 \
0.1x-62&=18 \
end{align}
Therefore $x= $800$. Since the school contributed 20%, the dollar amount contributed by the school towards the trip is $0.2cdot 800=$160$.
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
$endgroup$
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
add a comment |
$begingroup$
Let $x$ be the total amount of money contributed by students and the school as follows;
- 200 students contributed $0.8 x$,
- the school contributed $0.2x$,
$$$18 is the remaining amount they gave to the driver,
$$$20 processing fee for purchasing ticket,- 10% discount earned for purchasing the tickets,
$(x-20)0.9$ the money used for purchasing the tickets.
Therefore to solve for $x$, the following applies:
begin{align}
[x-(x-20)0.9+20]-60&=18 \
x-[0.9x-18+20]-60&=18 \
x-0.9x+18-20-60&=18 \
0.1x-62&=18 \
end{align}
Therefore $x= $800$. Since the school contributed 20%, the dollar amount contributed by the school towards the trip is $0.2cdot 800=$160$.
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
$endgroup$
Let $x$ be the total amount of money contributed by students and the school as follows;
- 200 students contributed $0.8 x$,
- the school contributed $0.2x$,
$$$18 is the remaining amount they gave to the driver,
$$$20 processing fee for purchasing ticket,- 10% discount earned for purchasing the tickets,
$(x-20)0.9$ the money used for purchasing the tickets.
Therefore to solve for $x$, the following applies:
begin{align}
[x-(x-20)0.9+20]-60&=18 \
x-[0.9x-18+20]-60&=18 \
x-0.9x+18-20-60&=18 \
0.1x-62&=18 \
end{align}
Therefore $x= $800$. Since the school contributed 20%, the dollar amount contributed by the school towards the trip is $0.2cdot 800=$160$.
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
edited Jan 17 at 20:19
Xander Henderson
15.1k103556
15.1k103556
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
answered Jan 17 at 19:55
Kudakwashe SakutukwaKudakwashe Sakutukwa
1
1
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
add a comment |
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
$begingroup$
Your answer, as originally written, was quite difficult to follow due to the poor formatting. I have attempted to clean it up. For future reference, please read the MathJax tutorial and use MathJax to write mathematics on this site.
$endgroup$
– Xander Henderson
Jan 17 at 20:20
add a comment |
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