Calculating the distance function on a manifold, given the Riemannian metric in matrix form
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I come from a CS background (and this is for a CS project) and as such my skills and knowledge of geometry are pretty poor. I'm looking at a bunch of points on a Riemannian manifold (let's say, for convenience, the hyperboloid) with a metric G (which, for the hyperboloid, I believe takes the form of a diagonal matrix whose first entry is -1 and the rest are 1s).
I want to calculate a sequence of Riemannian metrics [in matrix form - from what I'm aware, Riemannian metrics are usually rank 2 tensors, so the matrix form is just the (1,1) representation of such a tensor?], where each new element in the sequence is a function of the last. In other words, if we have $G = G_0$, $G_n = F(G_{n-1})$ for some arbitrary $F$.
Is there any way I can calculate the distance function on the Riemannian manifold corresponding to the new Riemannian metric? For instance, I know (unless I am mistaken) that the distance function on the hyperboloid is $d(x, y) = arccosh(- x^T G y)$ where $G$ is given as above, and that generally computing the distance function on a Riemannian manifold involves an arc length integral, so I'm wondering if there's any closed form I can find for that integral [not necessarily a solution], either based generally on a metric $G_{n}$ or on, say, $arccosh(- x^T G_0 y)$, $F$, and $G_n$.
Thanks!
differential-geometry numerical-linear-algebra hyperbolic-geometry
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
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$begingroup$
I come from a CS background (and this is for a CS project) and as such my skills and knowledge of geometry are pretty poor. I'm looking at a bunch of points on a Riemannian manifold (let's say, for convenience, the hyperboloid) with a metric G (which, for the hyperboloid, I believe takes the form of a diagonal matrix whose first entry is -1 and the rest are 1s).
I want to calculate a sequence of Riemannian metrics [in matrix form - from what I'm aware, Riemannian metrics are usually rank 2 tensors, so the matrix form is just the (1,1) representation of such a tensor?], where each new element in the sequence is a function of the last. In other words, if we have $G = G_0$, $G_n = F(G_{n-1})$ for some arbitrary $F$.
Is there any way I can calculate the distance function on the Riemannian manifold corresponding to the new Riemannian metric? For instance, I know (unless I am mistaken) that the distance function on the hyperboloid is $d(x, y) = arccosh(- x^T G y)$ where $G$ is given as above, and that generally computing the distance function on a Riemannian manifold involves an arc length integral, so I'm wondering if there's any closed form I can find for that integral [not necessarily a solution], either based generally on a metric $G_{n}$ or on, say, $arccosh(- x^T G_0 y)$, $F$, and $G_n$.
Thanks!
differential-geometry numerical-linear-algebra hyperbolic-geometry
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
$endgroup$
add a comment |
$begingroup$
I come from a CS background (and this is for a CS project) and as such my skills and knowledge of geometry are pretty poor. I'm looking at a bunch of points on a Riemannian manifold (let's say, for convenience, the hyperboloid) with a metric G (which, for the hyperboloid, I believe takes the form of a diagonal matrix whose first entry is -1 and the rest are 1s).
I want to calculate a sequence of Riemannian metrics [in matrix form - from what I'm aware, Riemannian metrics are usually rank 2 tensors, so the matrix form is just the (1,1) representation of such a tensor?], where each new element in the sequence is a function of the last. In other words, if we have $G = G_0$, $G_n = F(G_{n-1})$ for some arbitrary $F$.
Is there any way I can calculate the distance function on the Riemannian manifold corresponding to the new Riemannian metric? For instance, I know (unless I am mistaken) that the distance function on the hyperboloid is $d(x, y) = arccosh(- x^T G y)$ where $G$ is given as above, and that generally computing the distance function on a Riemannian manifold involves an arc length integral, so I'm wondering if there's any closed form I can find for that integral [not necessarily a solution], either based generally on a metric $G_{n}$ or on, say, $arccosh(- x^T G_0 y)$, $F$, and $G_n$.
Thanks!
differential-geometry numerical-linear-algebra hyperbolic-geometry
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
$endgroup$
I come from a CS background (and this is for a CS project) and as such my skills and knowledge of geometry are pretty poor. I'm looking at a bunch of points on a Riemannian manifold (let's say, for convenience, the hyperboloid) with a metric G (which, for the hyperboloid, I believe takes the form of a diagonal matrix whose first entry is -1 and the rest are 1s).
I want to calculate a sequence of Riemannian metrics [in matrix form - from what I'm aware, Riemannian metrics are usually rank 2 tensors, so the matrix form is just the (1,1) representation of such a tensor?], where each new element in the sequence is a function of the last. In other words, if we have $G = G_0$, $G_n = F(G_{n-1})$ for some arbitrary $F$.
Is there any way I can calculate the distance function on the Riemannian manifold corresponding to the new Riemannian metric? For instance, I know (unless I am mistaken) that the distance function on the hyperboloid is $d(x, y) = arccosh(- x^T G y)$ where $G$ is given as above, and that generally computing the distance function on a Riemannian manifold involves an arc length integral, so I'm wondering if there's any closed form I can find for that integral [not necessarily a solution], either based generally on a metric $G_{n}$ or on, say, $arccosh(- x^T G_0 y)$, $F$, and $G_n$.
Thanks!
differential-geometry numerical-linear-algebra hyperbolic-geometry
differential-geometry numerical-linear-algebra hyperbolic-geometry
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
edited Jan 4 at 7:21
king_geedorah
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
asked Jan 4 at 4:00
king_geedorahking_geedorah
63
63
add a comment |
add a comment |
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