Why is there a diode on the RX pin of the Adafruit Ultimate GPS board?
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I can't seem to understand why there is a diode at the Rx pin on this Adafruit Ultimate GPS board. If we are sending data to the GPS, why put a diode that prevents current flow into this pin?
diodes uart gps
asked Jan 13 at 0:35
YNGVVYNGVV
395
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add a comment |
$begingroup$
I can't seem to understand why there is a diode at the Rx pin on this Adafruit Ultimate GPS board. If we are sending data to the GPS, why put a diode that prevents current flow into this pin?
diodes uart gps
asked Jan 13 at 0:35
YNGVVYNGVV
395
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7
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Are you referring to D1? Did you read the note in the schematic telling you what it's for?
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– brhans
Jan 13 at 0:43
add a comment |
$begingroup$
I can't seem to understand why there is a diode at the Rx pin on this Adafruit Ultimate GPS board. If we are sending data to the GPS, why put a diode that prevents current flow into this pin?
diodes uart gps
asked Jan 13 at 0:35
YNGVVYNGVV
395
$endgroup$
I can't seem to understand why there is a diode at the Rx pin on this Adafruit Ultimate GPS board. If we are sending data to the GPS, why put a diode that prevents current flow into this pin?
diodes uart gps
diodes uart gps
asked Jan 13 at 0:35
YNGVVYNGVV
395
asked Jan 13 at 0:35
YNGVVYNGVV
395
asked Jan 13 at 0:35
YNGVVYNGVV
395
asked Jan 13 at 0:35
YNGVVYNGVV
395
asked Jan 13 at 0:35
YNGVVYNGVV
395
395
7
$begingroup$
Are you referring to D1? Did you read the note in the schematic telling you what it's for?
$endgroup$
– brhans
Jan 13 at 0:43
add a comment |
7
$begingroup$
Are you referring to D1? Did you read the note in the schematic telling you what it's for?
$endgroup$
– brhans
Jan 13 at 0:43
7
7
$begingroup$
Are you referring to D1? Did you read the note in the schematic telling you what it's for?
$endgroup$
– brhans
Jan 13 at 0:43
$begingroup$
Are you referring to D1? Did you read the note in the schematic telling you what it's for?
$endgroup$
– brhans
Jan 13 at 0:43
add a comment |
2 Answers
2
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oldest
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The pull-up resistor to 3.3V and the diode means that even if you feed the circuit with 5V logic (most Arduino boards use 5V logic) the GPS chipset will see a maximum of 3.3v. The MT3339 device may be damaged or operate incorrectly if any of its pins go above its 3.3V supply rail.
If the signal RX_5V goes to a logic low the diode will conduct and pull the MT3339 RX pin to ~0.7V that it will treat as a logic low.
If RX_5V goes to 5V resistor R3 will pull the MT3339 RX up to 3.3V and the diode will be reverse biased.
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
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1
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and that sir is the answer!!!
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– Edwin Fairchild
Jan 13 at 5:43
add a comment |
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The purpose of the diode is documented in a line of text near it on the schematic. The diode and resistor protect the RX input.
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
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$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
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– YNGVV
Jan 13 at 1:00
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
The pull-up resistor to 3.3V and the diode means that even if you feed the circuit with 5V logic (most Arduino boards use 5V logic) the GPS chipset will see a maximum of 3.3v. The MT3339 device may be damaged or operate incorrectly if any of its pins go above its 3.3V supply rail.
If the signal RX_5V goes to a logic low the diode will conduct and pull the MT3339 RX pin to ~0.7V that it will treat as a logic low.
If RX_5V goes to 5V resistor R3 will pull the MT3339 RX up to 3.3V and the diode will be reverse biased.
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
$endgroup$
1
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
add a comment |
$begingroup$
The pull-up resistor to 3.3V and the diode means that even if you feed the circuit with 5V logic (most Arduino boards use 5V logic) the GPS chipset will see a maximum of 3.3v. The MT3339 device may be damaged or operate incorrectly if any of its pins go above its 3.3V supply rail.
If the signal RX_5V goes to a logic low the diode will conduct and pull the MT3339 RX pin to ~0.7V that it will treat as a logic low.
If RX_5V goes to 5V resistor R3 will pull the MT3339 RX up to 3.3V and the diode will be reverse biased.
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
$endgroup$
1
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
add a comment |
$begingroup$
The pull-up resistor to 3.3V and the diode means that even if you feed the circuit with 5V logic (most Arduino boards use 5V logic) the GPS chipset will see a maximum of 3.3v. The MT3339 device may be damaged or operate incorrectly if any of its pins go above its 3.3V supply rail.
If the signal RX_5V goes to a logic low the diode will conduct and pull the MT3339 RX pin to ~0.7V that it will treat as a logic low.
If RX_5V goes to 5V resistor R3 will pull the MT3339 RX up to 3.3V and the diode will be reverse biased.
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
$endgroup$
The pull-up resistor to 3.3V and the diode means that even if you feed the circuit with 5V logic (most Arduino boards use 5V logic) the GPS chipset will see a maximum of 3.3v. The MT3339 device may be damaged or operate incorrectly if any of its pins go above its 3.3V supply rail.
If the signal RX_5V goes to a logic low the diode will conduct and pull the MT3339 RX pin to ~0.7V that it will treat as a logic low.
If RX_5V goes to 5V resistor R3 will pull the MT3339 RX up to 3.3V and the diode will be reverse biased.
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
edited Jan 13 at 4:39
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
answered Jan 13 at 1:00
Kevin WhiteKevin White
13k11522
13k11522
1
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
add a comment |
1
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
1
1
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
$begingroup$
and that sir is the answer!!!
$endgroup$
– Edwin Fairchild
Jan 13 at 5:43
add a comment |
$begingroup$
The purpose of the diode is documented in a line of text near it on the schematic. The diode and resistor protect the RX input.
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
$endgroup$
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
add a comment |
$begingroup$
The purpose of the diode is documented in a line of text near it on the schematic. The diode and resistor protect the RX input.
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
$endgroup$
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
add a comment |
$begingroup$
The purpose of the diode is documented in a line of text near it on the schematic. The diode and resistor protect the RX input.
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
$endgroup$
The purpose of the diode is documented in a line of text near it on the schematic. The diode and resistor protect the RX input.
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
answered Jan 13 at 0:43
Elliot AldersonElliot Alderson
6,48611022
6,48611022
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
add a comment |
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
$begingroup$
I should have elaborated. Yes, I see the note on the schematic and see that if a voltage higher than 3.3V is at RX_5V then current will be blocked by D1. But I do not understand how this allows any data to be transferred to the Rx pin if D1 is blocking all current flow from RX_5V. Could it be that if RX_5V is grounded/low/off, then RX will read 0 and if RX_5V is high (~3.3V or greater), RX will read 1 while being protected from any signal >3.3V? EDIT: Just saw @Kevin White's follow-up. Thanks!
$endgroup$
– YNGVV
Jan 13 at 1:00
add a comment |
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$begingroup$
Are you referring to D1? Did you read the note in the schematic telling you what it's for?
$endgroup$
– brhans
Jan 13 at 0:43