How to set up patterns when using SequenceSplit
5
$begingroup$
Given a list
lst={0,0,0,0,0,"A1",0,0,0,"B2",0,0,"C3","D4","E5",0,0,0,"F6"}
How to split it as
{{0,0,0,0,0},{"A1",0,0,0},{"B2",0,0},{"C3"},{"D4"},{"E5",0,0,0},{"F6"}}
I want to use SequenceSplit but didn't know how to set up the right pattern.
SequenceSplit[lst, {_String} -> {}]
Thanks!
list-manipulation sequence
asked Jan 13 at 2:46
JerryJerry
1,380212
$endgroup$
add a comment |
5
$begingroup$
Given a list
lst={0,0,0,0,0,"A1",0,0,0,"B2",0,0,"C3","D4","E5",0,0,0,"F6"}
How to split it as
{{0,0,0,0,0},{"A1",0,0,0},{"B2",0,0},{"C3"},{"D4"},{"E5",0,0,0},{"F6"}}
I want to use SequenceSplit but didn't know how to set up the right pattern.
SequenceSplit[lst, {_String} -> {}]
Thanks!
list-manipulation sequence
asked Jan 13 at 2:46
JerryJerry
1,380212
$endgroup$
add a comment |
5
5
5
1
$begingroup$
Given a list
lst={0,0,0,0,0,"A1",0,0,0,"B2",0,0,"C3","D4","E5",0,0,0,"F6"}
How to split it as
{{0,0,0,0,0},{"A1",0,0,0},{"B2",0,0},{"C3"},{"D4"},{"E5",0,0,0},{"F6"}}
I want to use SequenceSplit but didn't know how to set up the right pattern.
SequenceSplit[lst, {_String} -> {}]
Thanks!
list-manipulation sequence
asked Jan 13 at 2:46
JerryJerry
1,380212
$endgroup$
Given a list
lst={0,0,0,0,0,"A1",0,0,0,"B2",0,0,"C3","D4","E5",0,0,0,"F6"}
How to split it as
{{0,0,0,0,0},{"A1",0,0,0},{"B2",0,0},{"C3"},{"D4"},{"E5",0,0,0},{"F6"}}
I want to use SequenceSplit but didn't know how to set up the right pattern.
SequenceSplit[lst, {_String} -> {}]
Thanks!
list-manipulation sequence
list-manipulation sequence
asked Jan 13 at 2:46
JerryJerry
1,380212
asked Jan 13 at 2:46
JerryJerry
1,380212
edited Jan 13 at 3:59
Jerry
asked Jan 13 at 2:46
JerryJerry
1,380212
asked Jan 13 at 2:46
JerryJerry
1,380212
asked Jan 13 at 2:46
JerryJerry
1,380212
1,380212
add a comment |
add a comment |
1 Answer
1
active
oldest
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5
$begingroup$
Split[lst, Not @ StringQ @ #2 &]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
SequenceSplit[lst, {s_String, a : Except[_String] ...} :> {s, a}]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
answered Jan 13 at 3:32
kglrkglr
181k10200413
$endgroup$
$begingroup$
Very nice,Thanks! what do#1and#2mean inSplitfunction?
$endgroup$
– Jerry
Jan 13 at 3:49
2
$begingroup$
@Jerry see Working with Pure Functions andSlot
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against!? :^)
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
$begingroup$
@Jerry, in a test function used as the second argument ofSplit,#1refers to the first element of a consecutive pair and#2to the second, See also animation - Split which illustrates how it works for the default test functionSameQ.
$endgroup$
– kglr
Jan 13 at 4:04
|
show 3 more comments
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1 Answer
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oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
$begingroup$
Split[lst, Not @ StringQ @ #2 &]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
SequenceSplit[lst, {s_String, a : Except[_String] ...} :> {s, a}]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
answered Jan 13 at 3:32
kglrkglr
181k10200413
$endgroup$
$begingroup$
Very nice,Thanks! what do#1and#2mean inSplitfunction?
$endgroup$
– Jerry
Jan 13 at 3:49
2
$begingroup$
@Jerry see Working with Pure Functions andSlot
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against!? :^)
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
$begingroup$
@Jerry, in a test function used as the second argument ofSplit,#1refers to the first element of a consecutive pair and#2to the second, See also animation - Split which illustrates how it works for the default test functionSameQ.
$endgroup$
– kglr
Jan 13 at 4:04
|
show 3 more comments
5
$begingroup$
Split[lst, Not @ StringQ @ #2 &]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
SequenceSplit[lst, {s_String, a : Except[_String] ...} :> {s, a}]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
answered Jan 13 at 3:32
kglrkglr
181k10200413
$endgroup$
$begingroup$
Very nice,Thanks! what do#1and#2mean inSplitfunction?
$endgroup$
– Jerry
Jan 13 at 3:49
2
$begingroup$
@Jerry see Working with Pure Functions andSlot
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against!? :^)
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
$begingroup$
@Jerry, in a test function used as the second argument ofSplit,#1refers to the first element of a consecutive pair and#2to the second, See also animation - Split which illustrates how it works for the default test functionSameQ.
$endgroup$
– kglr
Jan 13 at 4:04
|
show 3 more comments
5
5
5
$begingroup$
Split[lst, Not @ StringQ @ #2 &]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
SequenceSplit[lst, {s_String, a : Except[_String] ...} :> {s, a}]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
answered Jan 13 at 3:32
kglrkglr
181k10200413
$endgroup$
Split[lst, Not @ StringQ @ #2 &]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
SequenceSplit[lst, {s_String, a : Except[_String] ...} :> {s, a}]
{{0, 0, 0, 0, 0}, {"A1", 0, 0, 0}, {"B2", 0,
0}, {"C3"}, {"D4"}, {"E5", 0, 0, 0}, {"F6"}}
answered Jan 13 at 3:32
kglrkglr
181k10200413
edited Jan 13 at 20:25
answered Jan 13 at 3:32
kglrkglr
181k10200413
answered Jan 13 at 3:32
kglrkglr
181k10200413
answered Jan 13 at 3:32
kglrkglr
181k10200413
181k10200413
$begingroup$
Very nice,Thanks! what do#1and#2mean inSplitfunction?
$endgroup$
– Jerry
Jan 13 at 3:49
2
$begingroup$
@Jerry see Working with Pure Functions andSlot
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against!? :^)
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
$begingroup$
@Jerry, in a test function used as the second argument ofSplit,#1refers to the first element of a consecutive pair and#2to the second, See also animation - Split which illustrates how it works for the default test functionSameQ.
$endgroup$
– kglr
Jan 13 at 4:04
|
show 3 more comments
$begingroup$
Very nice,Thanks! what do#1and#2mean inSplitfunction?
$endgroup$
– Jerry
Jan 13 at 3:49
2
$begingroup$
@Jerry see Working with Pure Functions andSlot
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against!? :^)
$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
$begingroup$
@Jerry, in a test function used as the second argument ofSplit,#1refers to the first element of a consecutive pair and#2to the second, See also animation - Split which illustrates how it works for the default test functionSameQ.
$endgroup$
– kglr
Jan 13 at 4:04
$begingroup$
Very nice,Thanks! what do
#1 and #2 mean in Split function?$endgroup$
– Jerry
Jan 13 at 3:49
$begingroup$
Very nice,Thanks! what do
#1 and #2 mean in Split function?$endgroup$
– Jerry
Jan 13 at 3:49
2
2
$begingroup$
@Jerry see Working with Pure Functions and
Slot$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
@Jerry see Working with Pure Functions and
Slot$endgroup$
– Mr.Wizard♦
Jan 13 at 3:56
$begingroup$
kglr, do you have something against
!? :^)$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
kglr, do you have something against
!? :^)$endgroup$
– Mr.Wizard♦
Jan 13 at 3:57
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
$begingroup$
@Mr.Wizard, thank you.
$endgroup$
– kglr
Jan 13 at 4:01
2
2
$begingroup$
@Jerry, in a test function used as the second argument of
Split, #1 refers to the first element of a consecutive pair and #2 to the second, See also animation - Split which illustrates how it works for the default test function SameQ.$endgroup$
– kglr
Jan 13 at 4:04
$begingroup$
@Jerry, in a test function used as the second argument of
Split, #1 refers to the first element of a consecutive pair and #2 to the second, See also animation - Split which illustrates how it works for the default test function SameQ.$endgroup$
– kglr
Jan 13 at 4:04
|
show 3 more comments
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