What mean $p_t(z,dy)=varepsilon _{z+t}(dy)$ ? (probability that ${X_t}$ just move to the right uniformly)
In the example 8 page 3 of this paper, what means : Let ${X_t}$ be the process that just moves to the right uniformly. That is $p_t(z,dy)=varepsilon _{z+t}(dy)$ ? I'm really not sure what it means exactly ?
probability
asked Dec 26 at 13:38
user623855
567
add a comment |
In the example 8 page 3 of this paper, what means : Let ${X_t}$ be the process that just moves to the right uniformly. That is $p_t(z,dy)=varepsilon _{z+t}(dy)$ ? I'm really not sure what it means exactly ?
probability
asked Dec 26 at 13:38
user623855
567
@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50
add a comment |
In the example 8 page 3 of this paper, what means : Let ${X_t}$ be the process that just moves to the right uniformly. That is $p_t(z,dy)=varepsilon _{z+t}(dy)$ ? I'm really not sure what it means exactly ?
probability
asked Dec 26 at 13:38
user623855
567
In the example 8 page 3 of this paper, what means : Let ${X_t}$ be the process that just moves to the right uniformly. That is $p_t(z,dy)=varepsilon _{z+t}(dy)$ ? I'm really not sure what it means exactly ?
probability
probability
asked Dec 26 at 13:38
user623855
567
asked Dec 26 at 13:38
user623855
567
edited Dec 27 at 10:59
asked Dec 26 at 13:38
user623855
567
asked Dec 26 at 13:38
user623855
567
asked Dec 26 at 13:38
user623855
567
567
@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50
add a comment |
@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50
@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50
@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50
add a comment |
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@Surb : could you explain a bit ? I don't understand.
– user623855
Dec 27 at 12:50