How to re-scale a rectangle to a smaller area?












1












$begingroup$


I have a rectangle of X by Y, with an area Z. I need to re-scale the rectangle so that it's area is no larger than the pre-defined AREA_MAX, preserving the original aspect ratio. How would I go about doing that?



X*Y = Z
if(Z > AREA_MAX){
Z = AREA_MAX
X = ?
Y = ?
}


Thank you










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    I have a rectangle of X by Y, with an area Z. I need to re-scale the rectangle so that it's area is no larger than the pre-defined AREA_MAX, preserving the original aspect ratio. How would I go about doing that?



    X*Y = Z
    if(Z > AREA_MAX){
    Z = AREA_MAX
    X = ?
    Y = ?
    }


    Thank you










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      I have a rectangle of X by Y, with an area Z. I need to re-scale the rectangle so that it's area is no larger than the pre-defined AREA_MAX, preserving the original aspect ratio. How would I go about doing that?



      X*Y = Z
      if(Z > AREA_MAX){
      Z = AREA_MAX
      X = ?
      Y = ?
      }


      Thank you










      share|cite|improve this question









      $endgroup$




      I have a rectangle of X by Y, with an area Z. I need to re-scale the rectangle so that it's area is no larger than the pre-defined AREA_MAX, preserving the original aspect ratio. How would I go about doing that?



      X*Y = Z
      if(Z > AREA_MAX){
      Z = AREA_MAX
      X = ?
      Y = ?
      }


      Thank you







      geometry rectangles






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      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Jan 16 at 12:33









      Katya SKatya S

      1082




      1082






















          1 Answer
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          $begingroup$

          Well, you have
          $$
          XY = Z qquad Rightarrow qquad frac{Z_{text{max}}}{Z} XY =
          frac{Z_{text{max}}}{Z} Z = Z_{text{max}}
          $$

          And if you want to scale both $X$ and $Y$ equally, you can put
          $$
          sqrt{frac{Z_{text{max}}}{Z}} X times sqrt{frac{Z_{text{max}}}{Z}} Y = Z_{text{max}}
          $$

          Therefore, you can scale both $X$ and $Y$ by $sqrt{frac{Z_{text{max}}}{Z}} $, where $Z=XY$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very muich for a a seedy response! :)
            $endgroup$
            – Katya S
            Jan 16 at 12:45












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          1 Answer
          1






          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1












          $begingroup$

          Well, you have
          $$
          XY = Z qquad Rightarrow qquad frac{Z_{text{max}}}{Z} XY =
          frac{Z_{text{max}}}{Z} Z = Z_{text{max}}
          $$

          And if you want to scale both $X$ and $Y$ equally, you can put
          $$
          sqrt{frac{Z_{text{max}}}{Z}} X times sqrt{frac{Z_{text{max}}}{Z}} Y = Z_{text{max}}
          $$

          Therefore, you can scale both $X$ and $Y$ by $sqrt{frac{Z_{text{max}}}{Z}} $, where $Z=XY$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very muich for a a seedy response! :)
            $endgroup$
            – Katya S
            Jan 16 at 12:45
















          1












          $begingroup$

          Well, you have
          $$
          XY = Z qquad Rightarrow qquad frac{Z_{text{max}}}{Z} XY =
          frac{Z_{text{max}}}{Z} Z = Z_{text{max}}
          $$

          And if you want to scale both $X$ and $Y$ equally, you can put
          $$
          sqrt{frac{Z_{text{max}}}{Z}} X times sqrt{frac{Z_{text{max}}}{Z}} Y = Z_{text{max}}
          $$

          Therefore, you can scale both $X$ and $Y$ by $sqrt{frac{Z_{text{max}}}{Z}} $, where $Z=XY$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you very muich for a a seedy response! :)
            $endgroup$
            – Katya S
            Jan 16 at 12:45














          1












          1








          1





          $begingroup$

          Well, you have
          $$
          XY = Z qquad Rightarrow qquad frac{Z_{text{max}}}{Z} XY =
          frac{Z_{text{max}}}{Z} Z = Z_{text{max}}
          $$

          And if you want to scale both $X$ and $Y$ equally, you can put
          $$
          sqrt{frac{Z_{text{max}}}{Z}} X times sqrt{frac{Z_{text{max}}}{Z}} Y = Z_{text{max}}
          $$

          Therefore, you can scale both $X$ and $Y$ by $sqrt{frac{Z_{text{max}}}{Z}} $, where $Z=XY$.






          share|cite|improve this answer









          $endgroup$



          Well, you have
          $$
          XY = Z qquad Rightarrow qquad frac{Z_{text{max}}}{Z} XY =
          frac{Z_{text{max}}}{Z} Z = Z_{text{max}}
          $$

          And if you want to scale both $X$ and $Y$ equally, you can put
          $$
          sqrt{frac{Z_{text{max}}}{Z}} X times sqrt{frac{Z_{text{max}}}{Z}} Y = Z_{text{max}}
          $$

          Therefore, you can scale both $X$ and $Y$ by $sqrt{frac{Z_{text{max}}}{Z}} $, where $Z=XY$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 16 at 12:41









          Matti P.Matti P.

          2,2811514




          2,2811514












          • $begingroup$
            Thank you very muich for a a seedy response! :)
            $endgroup$
            – Katya S
            Jan 16 at 12:45


















          • $begingroup$
            Thank you very muich for a a seedy response! :)
            $endgroup$
            – Katya S
            Jan 16 at 12:45
















          $begingroup$
          Thank you very muich for a a seedy response! :)
          $endgroup$
          – Katya S
          Jan 16 at 12:45




          $begingroup$
          Thank you very muich for a a seedy response! :)
          $endgroup$
          – Katya S
          Jan 16 at 12:45


















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