Regex search list of emails












2















So I have a long list of email and I want to search these based on just a few sections of the email string.



I want to try and search these emails more efficently so I want to match the start of the email. Is there a simple way to match the first character/first few characters, the @ and the following character and end of the email.



Here's an example search:



cal****@a**m


So then if I used a search on the following list it would only pull the top 2



callum@aol.com
callumsmith@aol.com
callumfrrg@test.com
someemail@test.com









share|improve this question





























    2















    So I have a long list of email and I want to search these based on just a few sections of the email string.



    I want to try and search these emails more efficently so I want to match the start of the email. Is there a simple way to match the first character/first few characters, the @ and the following character and end of the email.



    Here's an example search:



    cal****@a**m


    So then if I used a search on the following list it would only pull the top 2



    callum@aol.com
    callumsmith@aol.com
    callumfrrg@test.com
    someemail@test.com









    share|improve this question



























      2












      2








      2


      1






      So I have a long list of email and I want to search these based on just a few sections of the email string.



      I want to try and search these emails more efficently so I want to match the start of the email. Is there a simple way to match the first character/first few characters, the @ and the following character and end of the email.



      Here's an example search:



      cal****@a**m


      So then if I used a search on the following list it would only pull the top 2



      callum@aol.com
      callumsmith@aol.com
      callumfrrg@test.com
      someemail@test.com









      share|improve this question
















      So I have a long list of email and I want to search these based on just a few sections of the email string.



      I want to try and search these emails more efficently so I want to match the start of the email. Is there a simple way to match the first character/first few characters, the @ and the following character and end of the email.



      Here's an example search:



      cal****@a**m


      So then if I used a search on the following list it would only pull the top 2



      callum@aol.com
      callumsmith@aol.com
      callumfrrg@test.com
      someemail@test.com






      regular-expression






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 28 at 9:47









      Olorin

      3,8581721




      3,8581721










      asked Jan 28 at 9:45









      CallumCallum

      1133




      1133






















          1 Answer
          1






          active

          oldest

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          7














          With grep:



          grep '^cal.*@a.*m$' input.txt


          This matches lines beginning ^ with cal, followed by anything (.*), followed by @a, again followed by anything, with m at the end ($).






          share|improve this answer



















          • 1





            grep -x would get rid of the need for explicit anchors.

            – Kusalananda
            Jan 28 at 10:03











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          7














          With grep:



          grep '^cal.*@a.*m$' input.txt


          This matches lines beginning ^ with cal, followed by anything (.*), followed by @a, again followed by anything, with m at the end ($).






          share|improve this answer



















          • 1





            grep -x would get rid of the need for explicit anchors.

            – Kusalananda
            Jan 28 at 10:03
















          7














          With grep:



          grep '^cal.*@a.*m$' input.txt


          This matches lines beginning ^ with cal, followed by anything (.*), followed by @a, again followed by anything, with m at the end ($).






          share|improve this answer



















          • 1





            grep -x would get rid of the need for explicit anchors.

            – Kusalananda
            Jan 28 at 10:03














          7












          7








          7







          With grep:



          grep '^cal.*@a.*m$' input.txt


          This matches lines beginning ^ with cal, followed by anything (.*), followed by @a, again followed by anything, with m at the end ($).






          share|improve this answer













          With grep:



          grep '^cal.*@a.*m$' input.txt


          This matches lines beginning ^ with cal, followed by anything (.*), followed by @a, again followed by anything, with m at the end ($).







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jan 28 at 9:49









          OlorinOlorin

          3,8581721




          3,8581721








          • 1





            grep -x would get rid of the need for explicit anchors.

            – Kusalananda
            Jan 28 at 10:03














          • 1





            grep -x would get rid of the need for explicit anchors.

            – Kusalananda
            Jan 28 at 10:03








          1




          1





          grep -x would get rid of the need for explicit anchors.

          – Kusalananda
          Jan 28 at 10:03





          grep -x would get rid of the need for explicit anchors.

          – Kusalananda
          Jan 28 at 10:03


















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