Difference between $[a,b]in mathbb R$ and $[a,b]subset mathbb R$?












1












$begingroup$


What is the difference between the following?



Are they both mathematically correct?



begin{align}
[a,b]in mathbb R tag 1 \
[a,b]subset mathbb R tag 2
end{align}



And also, which one should I use If I want to say "the interval between $a$ and $b$ is real"? Feel free to correct me if this phrasing is inaccurate.










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    $in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
    $endgroup$
    – Yanko
    Jan 12 at 16:05








  • 1




    $begingroup$
    As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
    $endgroup$
    – J.G.
    Jan 12 at 16:10










  • $begingroup$
    @J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
    $endgroup$
    – Henning Makholm
    Jan 12 at 16:29










  • $begingroup$
    @HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
    $endgroup$
    – J.G.
    Jan 12 at 16:34
















1












$begingroup$


What is the difference between the following?



Are they both mathematically correct?



begin{align}
[a,b]in mathbb R tag 1 \
[a,b]subset mathbb R tag 2
end{align}



And also, which one should I use If I want to say "the interval between $a$ and $b$ is real"? Feel free to correct me if this phrasing is inaccurate.










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    $in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
    $endgroup$
    – Yanko
    Jan 12 at 16:05








  • 1




    $begingroup$
    As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
    $endgroup$
    – J.G.
    Jan 12 at 16:10










  • $begingroup$
    @J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
    $endgroup$
    – Henning Makholm
    Jan 12 at 16:29










  • $begingroup$
    @HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
    $endgroup$
    – J.G.
    Jan 12 at 16:34














1












1








1





$begingroup$


What is the difference between the following?



Are they both mathematically correct?



begin{align}
[a,b]in mathbb R tag 1 \
[a,b]subset mathbb R tag 2
end{align}



And also, which one should I use If I want to say "the interval between $a$ and $b$ is real"? Feel free to correct me if this phrasing is inaccurate.










share|cite|improve this question









$endgroup$




What is the difference between the following?



Are they both mathematically correct?



begin{align}
[a,b]in mathbb R tag 1 \
[a,b]subset mathbb R tag 2
end{align}



And also, which one should I use If I want to say "the interval between $a$ and $b$ is real"? Feel free to correct me if this phrasing is inaccurate.







real-analysis calculus elementary-set-theory notation






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 12 at 16:04









JDoeDoeJDoeDoe

7701614




7701614








  • 1




    $begingroup$
    $in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
    $endgroup$
    – Yanko
    Jan 12 at 16:05








  • 1




    $begingroup$
    As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
    $endgroup$
    – J.G.
    Jan 12 at 16:10










  • $begingroup$
    @J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
    $endgroup$
    – Henning Makholm
    Jan 12 at 16:29










  • $begingroup$
    @HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
    $endgroup$
    – J.G.
    Jan 12 at 16:34














  • 1




    $begingroup$
    $in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
    $endgroup$
    – Yanko
    Jan 12 at 16:05








  • 1




    $begingroup$
    As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
    $endgroup$
    – J.G.
    Jan 12 at 16:10










  • $begingroup$
    @J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
    $endgroup$
    – Henning Makholm
    Jan 12 at 16:29










  • $begingroup$
    @HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
    $endgroup$
    – J.G.
    Jan 12 at 16:34








1




1




$begingroup$
$in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
$endgroup$
– Yanko
Jan 12 at 16:05






$begingroup$
$in$ is for elements and $subset$ is for sets. The first would be valid only if $[a,b]$ were a real number.
$endgroup$
– Yanko
Jan 12 at 16:05






1




1




$begingroup$
As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
$endgroup$
– J.G.
Jan 12 at 16:10




$begingroup$
As has already been explained, (1) is incorrect while (2) is correct. This misconception may have come from the fact both elements and subsets of $Bbb R$ are sometimes described as "in" $Bbb R$. We sometimes say for clarity that $Bbb R$ contains or includes its subsets, and owns its elements. In other words, (1) is wrong because it claims ownership rather than inclusion.
$endgroup$
– J.G.
Jan 12 at 16:10












$begingroup$
@J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
$endgroup$
– Henning Makholm
Jan 12 at 16:29




$begingroup$
@J.G. I don't think I've ever heard "owns" used in that context in English. (On the other hand the Danish pronunciation of $in$ literally means "is owned by", so I agree that metaphor is not crazy -- just that it doesn't seem to be common in English).
$endgroup$
– Henning Makholm
Jan 12 at 16:29












$begingroup$
@HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
$endgroup$
– J.G.
Jan 12 at 16:34




$begingroup$
@HenningMakholm Also, $xin y$ can be rewritten as $yowns x$; $owns$ comes from the LaTeX owns.
$endgroup$
– J.G.
Jan 12 at 16:34










2 Answers
2






active

oldest

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4












$begingroup$

Since $[a,b]$ is a set then only second is validate:



$$ [a,b] := {xin mathbb{R}; aleq xleq b} implies [a,b]subset mathbb{R}$$



If the question was, is $[a,b]in mathcal{P}(mathbb{R})$ (that is the power set of $mathbb{R}$) then the answer would be yes.






share|cite|improve this answer











$endgroup$





















    5












    $begingroup$

    Assuming that $a$ and be are real numbers and that $aleqslant b$, then the assertion $[a,b]inmathbb R$ is false, since it means that the interval $[a,b]$ is an element of $mathbb R$. If you want to assert that $[a,b]$ is a subset of $mathbb R$, you write $[a,b]subsetmathbb R$.






    share|cite|improve this answer











    $endgroup$













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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4












      $begingroup$

      Since $[a,b]$ is a set then only second is validate:



      $$ [a,b] := {xin mathbb{R}; aleq xleq b} implies [a,b]subset mathbb{R}$$



      If the question was, is $[a,b]in mathcal{P}(mathbb{R})$ (that is the power set of $mathbb{R}$) then the answer would be yes.






      share|cite|improve this answer











      $endgroup$


















        4












        $begingroup$

        Since $[a,b]$ is a set then only second is validate:



        $$ [a,b] := {xin mathbb{R}; aleq xleq b} implies [a,b]subset mathbb{R}$$



        If the question was, is $[a,b]in mathcal{P}(mathbb{R})$ (that is the power set of $mathbb{R}$) then the answer would be yes.






        share|cite|improve this answer











        $endgroup$
















          4












          4








          4





          $begingroup$

          Since $[a,b]$ is a set then only second is validate:



          $$ [a,b] := {xin mathbb{R}; aleq xleq b} implies [a,b]subset mathbb{R}$$



          If the question was, is $[a,b]in mathcal{P}(mathbb{R})$ (that is the power set of $mathbb{R}$) then the answer would be yes.






          share|cite|improve this answer











          $endgroup$



          Since $[a,b]$ is a set then only second is validate:



          $$ [a,b] := {xin mathbb{R}; aleq xleq b} implies [a,b]subset mathbb{R}$$



          If the question was, is $[a,b]in mathcal{P}(mathbb{R})$ (that is the power set of $mathbb{R}$) then the answer would be yes.







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Jan 12 at 16:25









          David C. Ullrich

          61.3k43994




          61.3k43994










          answered Jan 12 at 16:05









          Maria MazurMaria Mazur

          46.9k1260120




          46.9k1260120























              5












              $begingroup$

              Assuming that $a$ and be are real numbers and that $aleqslant b$, then the assertion $[a,b]inmathbb R$ is false, since it means that the interval $[a,b]$ is an element of $mathbb R$. If you want to assert that $[a,b]$ is a subset of $mathbb R$, you write $[a,b]subsetmathbb R$.






              share|cite|improve this answer











              $endgroup$


















                5












                $begingroup$

                Assuming that $a$ and be are real numbers and that $aleqslant b$, then the assertion $[a,b]inmathbb R$ is false, since it means that the interval $[a,b]$ is an element of $mathbb R$. If you want to assert that $[a,b]$ is a subset of $mathbb R$, you write $[a,b]subsetmathbb R$.






                share|cite|improve this answer











                $endgroup$
















                  5












                  5








                  5





                  $begingroup$

                  Assuming that $a$ and be are real numbers and that $aleqslant b$, then the assertion $[a,b]inmathbb R$ is false, since it means that the interval $[a,b]$ is an element of $mathbb R$. If you want to assert that $[a,b]$ is a subset of $mathbb R$, you write $[a,b]subsetmathbb R$.






                  share|cite|improve this answer











                  $endgroup$



                  Assuming that $a$ and be are real numbers and that $aleqslant b$, then the assertion $[a,b]inmathbb R$ is false, since it means that the interval $[a,b]$ is an element of $mathbb R$. If you want to assert that $[a,b]$ is a subset of $mathbb R$, you write $[a,b]subsetmathbb R$.







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Jan 12 at 16:21

























                  answered Jan 12 at 16:08









                  José Carlos SantosJosé Carlos Santos

                  167k22132235




                  167k22132235






























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