determining the number of digits in text file
I have a data file as follows:
15 01 01 00 00 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 01 00 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 02 01 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 03 01 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
I need to count the digit number of the value in the first line and fourth column then I need to determine this digit number as a variable as follows:
first line and fourth column: 00
digit_number=2
scripts
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
add a comment |
I have a data file as follows:
15 01 01 00 00 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 01 00 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 02 01 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 03 01 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
I need to count the digit number of the value in the first line and fourth column then I need to determine this digit number as a variable as follows:
first line and fourth column: 00
digit_number=2
scripts
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
You can probably do this withsedandawksed 's/[^0-9]//g' dat | awk '{ print length }'I'm neither an expert insednorawkso I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)
– j-money
Jan 22 at 13:47
add a comment |
I have a data file as follows:
15 01 01 00 00 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 01 00 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 02 01 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 03 01 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
I need to count the digit number of the value in the first line and fourth column then I need to determine this digit number as a variable as follows:
first line and fourth column: 00
digit_number=2
scripts
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
I have a data file as follows:
15 01 01 00 00 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 01 00 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 02 01 0.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
15 01 01 03 01 30.0000000 0 22E19R13R12G15G26G24G21E20R19G13G18G29
I need to count the digit number of the value in the first line and fourth column then I need to determine this digit number as a variable as follows:
first line and fourth column: 00
digit_number=2
scripts
scripts
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
asked Jan 22 at 13:42
deepblue_86deepblue_86
5851024
5851024
Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
You can probably do this withsedandawksed 's/[^0-9]//g' dat | awk '{ print length }'I'm neither an expert insednorawkso I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)
– j-money
Jan 22 at 13:47
add a comment |
Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
You can probably do this withsedandawksed 's/[^0-9]//g' dat | awk '{ print length }'I'm neither an expert insednorawkso I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)
– j-money
Jan 22 at 13:47
Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
You can probably do this with
sed and awk sed 's/[^0-9]//g' dat | awk '{ print length }' I'm neither an expert in sed nor awk so I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)– j-money
Jan 22 at 13:47
You can probably do this with
sed and awk sed 's/[^0-9]//g' dat | awk '{ print length }' I'm neither an expert in sed nor awk so I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)– j-money
Jan 22 at 13:47
add a comment |
2 Answers
2
active
oldest
votes
If you don't need to actually check that the value is a number, you can simply check the length of the 4th field from the 1st record
awk 'FNR == 1 {print length($4); exit}' file
To assign to a shell variable:
digit_number=$(awk 'FNR == 1 {print length($4); exit}' file)
If you need to count how many digits are in the field, then you could modify the awk command to
awk 'FNR == 1 {print gsub(/[0-9]/,"",$4); exit}' file
Note that gsub will return a count of decimal digits [0-9] ignoring any non-digit characters in the field.
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
add a comment |
digit_number=$(head -1 {the file} | cut -d ' ' -f 4 | tr -d 'n' | wc -c)
Where:
head -1 {the file}print the first line of the file
cut -d ' ' -f 4takes the 4th space-delimited field
tr -d 'n'removes the trailing lf
wc -ccounts the bytes in the result
edited Jan 22 at 13:53
pa4080
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you don't need to actually check that the value is a number, you can simply check the length of the 4th field from the 1st record
awk 'FNR == 1 {print length($4); exit}' file
To assign to a shell variable:
digit_number=$(awk 'FNR == 1 {print length($4); exit}' file)
If you need to count how many digits are in the field, then you could modify the awk command to
awk 'FNR == 1 {print gsub(/[0-9]/,"",$4); exit}' file
Note that gsub will return a count of decimal digits [0-9] ignoring any non-digit characters in the field.
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
add a comment |
If you don't need to actually check that the value is a number, you can simply check the length of the 4th field from the 1st record
awk 'FNR == 1 {print length($4); exit}' file
To assign to a shell variable:
digit_number=$(awk 'FNR == 1 {print length($4); exit}' file)
If you need to count how many digits are in the field, then you could modify the awk command to
awk 'FNR == 1 {print gsub(/[0-9]/,"",$4); exit}' file
Note that gsub will return a count of decimal digits [0-9] ignoring any non-digit characters in the field.
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
add a comment |
If you don't need to actually check that the value is a number, you can simply check the length of the 4th field from the 1st record
awk 'FNR == 1 {print length($4); exit}' file
To assign to a shell variable:
digit_number=$(awk 'FNR == 1 {print length($4); exit}' file)
If you need to count how many digits are in the field, then you could modify the awk command to
awk 'FNR == 1 {print gsub(/[0-9]/,"",$4); exit}' file
Note that gsub will return a count of decimal digits [0-9] ignoring any non-digit characters in the field.
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
If you don't need to actually check that the value is a number, you can simply check the length of the 4th field from the 1st record
awk 'FNR == 1 {print length($4); exit}' file
To assign to a shell variable:
digit_number=$(awk 'FNR == 1 {print length($4); exit}' file)
If you need to count how many digits are in the field, then you could modify the awk command to
awk 'FNR == 1 {print gsub(/[0-9]/,"",$4); exit}' file
Note that gsub will return a count of decimal digits [0-9] ignoring any non-digit characters in the field.
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
answered Jan 22 at 13:49
steeldriversteeldriver
68.1k11113184
68.1k11113184
add a comment |
add a comment |
digit_number=$(head -1 {the file} | cut -d ' ' -f 4 | tr -d 'n' | wc -c)
Where:
head -1 {the file}print the first line of the file
cut -d ' ' -f 4takes the 4th space-delimited field
tr -d 'n'removes the trailing lf
wc -ccounts the bytes in the result
edited Jan 22 at 13:53
pa4080
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
add a comment |
digit_number=$(head -1 {the file} | cut -d ' ' -f 4 | tr -d 'n' | wc -c)
Where:
head -1 {the file}print the first line of the file
cut -d ' ' -f 4takes the 4th space-delimited field
tr -d 'n'removes the trailing lf
wc -ccounts the bytes in the result
edited Jan 22 at 13:53
pa4080
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
add a comment |
digit_number=$(head -1 {the file} | cut -d ' ' -f 4 | tr -d 'n' | wc -c)
Where:
head -1 {the file}print the first line of the file
cut -d ' ' -f 4takes the 4th space-delimited field
tr -d 'n'removes the trailing lf
wc -ccounts the bytes in the result
edited Jan 22 at 13:53
pa4080
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
digit_number=$(head -1 {the file} | cut -d ' ' -f 4 | tr -d 'n' | wc -c)
Where:
head -1 {the file}print the first line of the file
cut -d ' ' -f 4takes the 4th space-delimited field
tr -d 'n'removes the trailing lf
wc -ccounts the bytes in the result
edited Jan 22 at 13:53
pa4080
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
edited Jan 22 at 13:53
pa4080
14.3k52669
edited Jan 22 at 13:53
pa4080
14.3k52669
edited Jan 22 at 13:53
pa4080
14.3k52669
14.3k52669
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
answered Jan 22 at 13:51
xenoidxenoid
1,6531416
1,6531416
add a comment |
add a comment |
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Would be stack overflow the perfect place for this question?
– TDK
Jan 22 at 13:44
You can probably do this with
sedandawksed 's/[^0-9]//g' dat | awk '{ print length }'I'm neither an expert insednorawkso I expect someone to tell me this is very wrong :-) (also this only counts up all the numbers rather than just the first line and fourth column, again not an awk expert)– j-money
Jan 22 at 13:47