How do I apply something like the double slash notation but not at the end of line?
$begingroup$
f[x_] = x^2;
Scan[Print[f[#]] &, {1, 2, 3}]
I want to do something like this, but I don't want to type so many brackets.
I'd like to have something like
f[x_] = x^2;
Scan[f[#] //Print &, {1, 2, 3}]
But this doesn't work. What's the correct symbol/method, to pipe the output of f[#] to Print ?
Sorry I googled "mathematica pipe output" but I don't think I'm using the correct keywords. But linux users have the terminology of "piping".
functions
asked Feb 9 at 18:26
seilguseilgu
1726
$endgroup$
add a comment |
$begingroup$
f[x_] = x^2;
Scan[Print[f[#]] &, {1, 2, 3}]
I want to do something like this, but I don't want to type so many brackets.
I'd like to have something like
f[x_] = x^2;
Scan[f[#] //Print &, {1, 2, 3}]
But this doesn't work. What's the correct symbol/method, to pipe the output of f[#] to Print ?
Sorry I googled "mathematica pipe output" but I don't think I'm using the correct keywords. But linux users have the terminology of "piping".
functions
asked Feb 9 at 18:26
seilguseilgu
1726
$endgroup$
add a comment |
$begingroup$
f[x_] = x^2;
Scan[Print[f[#]] &, {1, 2, 3}]
I want to do something like this, but I don't want to type so many brackets.
I'd like to have something like
f[x_] = x^2;
Scan[f[#] //Print &, {1, 2, 3}]
But this doesn't work. What's the correct symbol/method, to pipe the output of f[#] to Print ?
Sorry I googled "mathematica pipe output" but I don't think I'm using the correct keywords. But linux users have the terminology of "piping".
functions
asked Feb 9 at 18:26
seilguseilgu
1726
$endgroup$
f[x_] = x^2;
Scan[Print[f[#]] &, {1, 2, 3}]
I want to do something like this, but I don't want to type so many brackets.
I'd like to have something like
f[x_] = x^2;
Scan[f[#] //Print &, {1, 2, 3}]
But this doesn't work. What's the correct symbol/method, to pipe the output of f[#] to Print ?
Sorry I googled "mathematica pipe output" but I don't think I'm using the correct keywords. But linux users have the terminology of "piping".
functions
functions
asked Feb 9 at 18:26
seilguseilgu
1726
asked Feb 9 at 18:26
seilguseilgu
1726
asked Feb 9 at 18:26
seilguseilgu
1726
asked Feb 9 at 18:26
seilguseilgu
1726
asked Feb 9 at 18:26
seilguseilgu
1726
1726
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
To obtain the "pipeline" style with the data at the beginning of the expression, we can write:
{1, 2, 3} // Scan[f /* Print]
This combines f and Print into a single function using /* (right composition) and then uses the operator form of Scan to lift that function so that it operates upon lists.
This composed function is then applied to the list {1, 2, 3} using the postfix notation //.
We can dispense with brackets altogether by adding some infix notation...
f /* Print ~Scan~ {1, 2, 3}
... but perhaps this is taking it too far (and the initial value is no longer at the start of the pipeline).
Another way to get a similar visual result would be to write:
{1, 2, 3} // Map[f] // Column
If you are interested in combining operators in a concatenative style, you might want to check out Query. For example:
{1, 2, 3} // Query[Column, f]
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
$endgroup$
add a comment |
$begingroup$
The problem, as usual, is precedence. You need to use parenthesis to group expressions. The code
Scan[ (#^2 // Print) &, {1, 2, 3}]
will now do what you want. Your reference to "mathematica pipe output" is a good idea. You can think of//as the Mathematica equivalent to the Unix pipe symbol | or better yet the Forth postfix notation for executing "words" which use the data stack to operate on. In fact, Mathematica itself has an "evaluation stack" accessed using theStackand related functions.
answered Feb 9 at 18:33
SomosSomos
1,7451110
$endgroup$
add a comment |
$begingroup$
These are different ways to write the same:
(f[#] // Print) &
Print@f[#] &
Print[f[#]] &
f[#] // Print & is parsed as (f[#]) // (Print &)—mind the precendence.
The following are also effectively equivalent (though they denote a different expression):
Print @* f
f /* Print
See Composition, RightComposition
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
$endgroup$
1
$begingroup$
Use;to suppress output ofNulls:Print@*f /@ Range@3;
$endgroup$
– Bob Hanlon
Feb 9 at 22:21
add a comment |
$begingroup$
Another option by using the true name of &:
f[x_] = x^2;
Scan[f[#] //Print //Function, {1, 2, 3}]
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
To obtain the "pipeline" style with the data at the beginning of the expression, we can write:
{1, 2, 3} // Scan[f /* Print]
This combines f and Print into a single function using /* (right composition) and then uses the operator form of Scan to lift that function so that it operates upon lists.
This composed function is then applied to the list {1, 2, 3} using the postfix notation //.
We can dispense with brackets altogether by adding some infix notation...
f /* Print ~Scan~ {1, 2, 3}
... but perhaps this is taking it too far (and the initial value is no longer at the start of the pipeline).
Another way to get a similar visual result would be to write:
{1, 2, 3} // Map[f] // Column
If you are interested in combining operators in a concatenative style, you might want to check out Query. For example:
{1, 2, 3} // Query[Column, f]
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
$endgroup$
add a comment |
$begingroup$
To obtain the "pipeline" style with the data at the beginning of the expression, we can write:
{1, 2, 3} // Scan[f /* Print]
This combines f and Print into a single function using /* (right composition) and then uses the operator form of Scan to lift that function so that it operates upon lists.
This composed function is then applied to the list {1, 2, 3} using the postfix notation //.
We can dispense with brackets altogether by adding some infix notation...
f /* Print ~Scan~ {1, 2, 3}
... but perhaps this is taking it too far (and the initial value is no longer at the start of the pipeline).
Another way to get a similar visual result would be to write:
{1, 2, 3} // Map[f] // Column
If you are interested in combining operators in a concatenative style, you might want to check out Query. For example:
{1, 2, 3} // Query[Column, f]
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
$endgroup$
add a comment |
$begingroup$
To obtain the "pipeline" style with the data at the beginning of the expression, we can write:
{1, 2, 3} // Scan[f /* Print]
This combines f and Print into a single function using /* (right composition) and then uses the operator form of Scan to lift that function so that it operates upon lists.
This composed function is then applied to the list {1, 2, 3} using the postfix notation //.
We can dispense with brackets altogether by adding some infix notation...
f /* Print ~Scan~ {1, 2, 3}
... but perhaps this is taking it too far (and the initial value is no longer at the start of the pipeline).
Another way to get a similar visual result would be to write:
{1, 2, 3} // Map[f] // Column
If you are interested in combining operators in a concatenative style, you might want to check out Query. For example:
{1, 2, 3} // Query[Column, f]
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
$endgroup$
To obtain the "pipeline" style with the data at the beginning of the expression, we can write:
{1, 2, 3} // Scan[f /* Print]
This combines f and Print into a single function using /* (right composition) and then uses the operator form of Scan to lift that function so that it operates upon lists.
This composed function is then applied to the list {1, 2, 3} using the postfix notation //.
We can dispense with brackets altogether by adding some infix notation...
f /* Print ~Scan~ {1, 2, 3}
... but perhaps this is taking it too far (and the initial value is no longer at the start of the pipeline).
Another way to get a similar visual result would be to write:
{1, 2, 3} // Map[f] // Column
If you are interested in combining operators in a concatenative style, you might want to check out Query. For example:
{1, 2, 3} // Query[Column, f]
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
edited Feb 9 at 23:51
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
answered Feb 9 at 23:21
WReachWReach
53.5k2115214
53.5k2115214
add a comment |
add a comment |
$begingroup$
The problem, as usual, is precedence. You need to use parenthesis to group expressions. The code
Scan[ (#^2 // Print) &, {1, 2, 3}]
will now do what you want. Your reference to "mathematica pipe output" is a good idea. You can think of//as the Mathematica equivalent to the Unix pipe symbol | or better yet the Forth postfix notation for executing "words" which use the data stack to operate on. In fact, Mathematica itself has an "evaluation stack" accessed using theStackand related functions.
answered Feb 9 at 18:33
SomosSomos
1,7451110
$endgroup$
add a comment |
$begingroup$
The problem, as usual, is precedence. You need to use parenthesis to group expressions. The code
Scan[ (#^2 // Print) &, {1, 2, 3}]
will now do what you want. Your reference to "mathematica pipe output" is a good idea. You can think of//as the Mathematica equivalent to the Unix pipe symbol | or better yet the Forth postfix notation for executing "words" which use the data stack to operate on. In fact, Mathematica itself has an "evaluation stack" accessed using theStackand related functions.
answered Feb 9 at 18:33
SomosSomos
1,7451110
$endgroup$
add a comment |
$begingroup$
The problem, as usual, is precedence. You need to use parenthesis to group expressions. The code
Scan[ (#^2 // Print) &, {1, 2, 3}]
will now do what you want. Your reference to "mathematica pipe output" is a good idea. You can think of//as the Mathematica equivalent to the Unix pipe symbol | or better yet the Forth postfix notation for executing "words" which use the data stack to operate on. In fact, Mathematica itself has an "evaluation stack" accessed using theStackand related functions.
answered Feb 9 at 18:33
SomosSomos
1,7451110
$endgroup$
The problem, as usual, is precedence. You need to use parenthesis to group expressions. The code
Scan[ (#^2 // Print) &, {1, 2, 3}]
will now do what you want. Your reference to "mathematica pipe output" is a good idea. You can think of//as the Mathematica equivalent to the Unix pipe symbol | or better yet the Forth postfix notation for executing "words" which use the data stack to operate on. In fact, Mathematica itself has an "evaluation stack" accessed using theStackand related functions.
answered Feb 9 at 18:33
SomosSomos
1,7451110
edited Feb 10 at 1:05
answered Feb 9 at 18:33
SomosSomos
1,7451110
answered Feb 9 at 18:33
SomosSomos
1,7451110
answered Feb 9 at 18:33
SomosSomos
1,7451110
1,7451110
add a comment |
add a comment |
$begingroup$
These are different ways to write the same:
(f[#] // Print) &
Print@f[#] &
Print[f[#]] &
f[#] // Print & is parsed as (f[#]) // (Print &)—mind the precendence.
The following are also effectively equivalent (though they denote a different expression):
Print @* f
f /* Print
See Composition, RightComposition
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
$endgroup$
1
$begingroup$
Use;to suppress output ofNulls:Print@*f /@ Range@3;
$endgroup$
– Bob Hanlon
Feb 9 at 22:21
add a comment |
$begingroup$
These are different ways to write the same:
(f[#] // Print) &
Print@f[#] &
Print[f[#]] &
f[#] // Print & is parsed as (f[#]) // (Print &)—mind the precendence.
The following are also effectively equivalent (though they denote a different expression):
Print @* f
f /* Print
See Composition, RightComposition
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
$endgroup$
1
$begingroup$
Use;to suppress output ofNulls:Print@*f /@ Range@3;
$endgroup$
– Bob Hanlon
Feb 9 at 22:21
add a comment |
$begingroup$
These are different ways to write the same:
(f[#] // Print) &
Print@f[#] &
Print[f[#]] &
f[#] // Print & is parsed as (f[#]) // (Print &)—mind the precendence.
The following are also effectively equivalent (though they denote a different expression):
Print @* f
f /* Print
See Composition, RightComposition
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
$endgroup$
These are different ways to write the same:
(f[#] // Print) &
Print@f[#] &
Print[f[#]] &
f[#] // Print & is parsed as (f[#]) // (Print &)—mind the precendence.
The following are also effectively equivalent (though they denote a different expression):
Print @* f
f /* Print
See Composition, RightComposition
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
answered Feb 9 at 18:35
SzabolcsSzabolcs
163k14447944
163k14447944
1
$begingroup$
Use;to suppress output ofNulls:Print@*f /@ Range@3;
$endgroup$
– Bob Hanlon
Feb 9 at 22:21
add a comment |
1
$begingroup$
Use;to suppress output ofNulls:Print@*f /@ Range@3;
$endgroup$
– Bob Hanlon
Feb 9 at 22:21
1
1
$begingroup$
Use
; to suppress output of Nulls: Print@*f /@ Range@3;$endgroup$
– Bob Hanlon
Feb 9 at 22:21
$begingroup$
Use
; to suppress output of Nulls: Print@*f /@ Range@3;$endgroup$
– Bob Hanlon
Feb 9 at 22:21
add a comment |
$begingroup$
Another option by using the true name of &:
f[x_] = x^2;
Scan[f[#] //Print //Function, {1, 2, 3}]
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
$endgroup$
add a comment |
$begingroup$
Another option by using the true name of &:
f[x_] = x^2;
Scan[f[#] //Print //Function, {1, 2, 3}]
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
$endgroup$
add a comment |
$begingroup$
Another option by using the true name of &:
f[x_] = x^2;
Scan[f[#] //Print //Function, {1, 2, 3}]
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
$endgroup$
Another option by using the true name of &:
f[x_] = x^2;
Scan[f[#] //Print //Function, {1, 2, 3}]
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
answered Feb 9 at 23:30
b3m2a1b3m2a1
28.5k359164
28.5k359164
add a comment |
add a comment |
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