simple nuclear $C^*$ algebra [closed]
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Does there exist an infinite dimensional simple nuclear $C^*$ algebra which admits a tracial state?
operator-theory operator-algebras c-star-algebras
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closed as off-topic by Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos Jan 18 at 11:27
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Does there exist an infinite dimensional simple nuclear $C^*$ algebra which admits a tracial state?
operator-theory operator-algebras c-star-algebras
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closed as off-topic by Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos Jan 18 at 11:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Does there exist an infinite dimensional simple nuclear $C^*$ algebra which admits a tracial state?
operator-theory operator-algebras c-star-algebras
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Does there exist an infinite dimensional simple nuclear $C^*$ algebra which admits a tracial state?
operator-theory operator-algebras c-star-algebras
operator-theory operator-algebras c-star-algebras
asked Jan 12 at 6:15
mathrookiemathrookie
922512
922512
closed as off-topic by Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos Jan 18 at 11:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos Jan 18 at 11:27
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Claude Leibovici, Cesareo, A. Pongrácz, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
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1 Answer
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Yes, many. A prominent example is the CAR-algebra. Another example is the Jiang-Su algebra which is not a UHF-algebra.
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This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
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– user42761
Jan 12 at 13:03
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1 Answer
1
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
Yes, many. A prominent example is the CAR-algebra. Another example is the Jiang-Su algebra which is not a UHF-algebra.
$endgroup$
$begingroup$
This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
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– user42761
Jan 12 at 13:03
add a comment |
$begingroup$
Yes, many. A prominent example is the CAR-algebra. Another example is the Jiang-Su algebra which is not a UHF-algebra.
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$begingroup$
This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
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– user42761
Jan 12 at 13:03
add a comment |
$begingroup$
Yes, many. A prominent example is the CAR-algebra. Another example is the Jiang-Su algebra which is not a UHF-algebra.
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Yes, many. A prominent example is the CAR-algebra. Another example is the Jiang-Su algebra which is not a UHF-algebra.
answered Jan 12 at 8:47
user42761
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This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
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– user42761
Jan 12 at 13:03
add a comment |
$begingroup$
This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
$endgroup$
– user42761
Jan 12 at 13:03
$begingroup$
This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
$endgroup$
– user42761
Jan 12 at 13:03
$begingroup$
This is also no obstruction. For example the Jacelon-Razak algebra is an example, see arxiv.org/abs/1006.5397. I am sure there are more basic examples.
$endgroup$
– user42761
Jan 12 at 13:03
add a comment |