rolling a dice multiple times: when the distribution is binomial and when it is not
I suppose we roll a 6-sided dice three times. A probability to to obtain two times number 3 can be framed as binomial because I can define as "p" a probability to obtain 3 and "1-p" the remaining outcomes. But if the question is the probability to obtain twice 3 and once 1, the problem cannot be solved using binomial, because there are more than two potential outcomes (3, 1 and anything else). Am I right?
Thanks
probability binomial-distribution
asked Dec 26 '18 at 17:10
John
1156
add a comment |
I suppose we roll a 6-sided dice three times. A probability to to obtain two times number 3 can be framed as binomial because I can define as "p" a probability to obtain 3 and "1-p" the remaining outcomes. But if the question is the probability to obtain twice 3 and once 1, the problem cannot be solved using binomial, because there are more than two potential outcomes (3, 1 and anything else). Am I right?
Thanks
probability binomial-distribution
asked Dec 26 '18 at 17:10
John
1156
1
Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Thanks for help!
– John
Dec 26 '18 at 17:29
add a comment |
I suppose we roll a 6-sided dice three times. A probability to to obtain two times number 3 can be framed as binomial because I can define as "p" a probability to obtain 3 and "1-p" the remaining outcomes. But if the question is the probability to obtain twice 3 and once 1, the problem cannot be solved using binomial, because there are more than two potential outcomes (3, 1 and anything else). Am I right?
Thanks
probability binomial-distribution
asked Dec 26 '18 at 17:10
John
1156
I suppose we roll a 6-sided dice three times. A probability to to obtain two times number 3 can be framed as binomial because I can define as "p" a probability to obtain 3 and "1-p" the remaining outcomes. But if the question is the probability to obtain twice 3 and once 1, the problem cannot be solved using binomial, because there are more than two potential outcomes (3, 1 and anything else). Am I right?
Thanks
probability binomial-distribution
probability binomial-distribution
asked Dec 26 '18 at 17:10
John
1156
asked Dec 26 '18 at 17:10
John
1156
asked Dec 26 '18 at 17:10
John
1156
asked Dec 26 '18 at 17:10
John
1156
asked Dec 26 '18 at 17:10
John
1156
1156
1
Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Thanks for help!
– John
Dec 26 '18 at 17:29
add a comment |
1
Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Thanks for help!
– John
Dec 26 '18 at 17:29
1
1
Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Thanks for help!
– John
Dec 26 '18 at 17:29
Thanks for help!
– John
Dec 26 '18 at 17:29
add a comment |
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Yes, you're correct. The last question could be answered using the multinomial distribution, by the way.
– littleO
Dec 26 '18 at 17:19
Thanks for help!
– John
Dec 26 '18 at 17:29