A bag contains 2 red, 3 green and 5 blue balls












2














A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times










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  • 1




    So how many times do you take a ball out from the bag (and put it back)?
    – Matti P.
    Dec 28 '18 at 14:02










  • I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
    – drhab
    Dec 28 '18 at 14:02












  • Yes 3 balls sorry I forgot to mention that
    – S. Surya
    Dec 28 '18 at 14:06










  • I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
    – lulu
    Dec 28 '18 at 14:23
















2














A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times










share|cite|improve this question




















  • 1




    So how many times do you take a ball out from the bag (and put it back)?
    – Matti P.
    Dec 28 '18 at 14:02










  • I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
    – drhab
    Dec 28 '18 at 14:02












  • Yes 3 balls sorry I forgot to mention that
    – S. Surya
    Dec 28 '18 at 14:06










  • I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
    – lulu
    Dec 28 '18 at 14:23














2












2








2







A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times










share|cite|improve this question















A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times







probability






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 28 '18 at 14:07







S. Surya

















asked Dec 28 '18 at 13:59









S. SuryaS. Surya

143




143








  • 1




    So how many times do you take a ball out from the bag (and put it back)?
    – Matti P.
    Dec 28 '18 at 14:02










  • I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
    – drhab
    Dec 28 '18 at 14:02












  • Yes 3 balls sorry I forgot to mention that
    – S. Surya
    Dec 28 '18 at 14:06










  • I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
    – lulu
    Dec 28 '18 at 14:23














  • 1




    So how many times do you take a ball out from the bag (and put it back)?
    – Matti P.
    Dec 28 '18 at 14:02










  • I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
    – drhab
    Dec 28 '18 at 14:02












  • Yes 3 balls sorry I forgot to mention that
    – S. Surya
    Dec 28 '18 at 14:06










  • I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
    – lulu
    Dec 28 '18 at 14:23








1




1




So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02




So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02












I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02






I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02














Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06




Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06












I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23




I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23










2 Answers
2






active

oldest

votes


















2














The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.






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    0














    Yes, you have to delete the last 2.



    Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$






    share|cite|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2














      The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.






      share|cite|improve this answer


























        2














        The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.






        share|cite|improve this answer
























          2












          2








          2






          The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.






          share|cite|improve this answer












          The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 28 '18 at 14:13









          Ross MillikanRoss Millikan

          292k23197371




          292k23197371























              0














              Yes, you have to delete the last 2.



              Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$






              share|cite|improve this answer


























                0














                Yes, you have to delete the last 2.



                Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$






                share|cite|improve this answer
























                  0












                  0








                  0






                  Yes, you have to delete the last 2.



                  Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$






                  share|cite|improve this answer












                  Yes, you have to delete the last 2.



                  Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Dec 28 '18 at 14:35









                  Angel MorenoAngel Moreno

                  37915




                  37915






























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