A bag contains 2 red, 3 green and 5 blue balls
A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times
probability
add a comment |
A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times
probability
1
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23
add a comment |
A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times
probability
A ball is drawn, observed and put again in the bag. Find the probability of getting all colours different.
My teacher's solution:
2/10 × 3/10 × 5/10 × 3! × 2
I don't get why that last 2 was necessary
Edit: balls are drawn 3 times
probability
probability
edited Dec 28 '18 at 14:07
S. Surya
asked Dec 28 '18 at 13:59
S. SuryaS. Surya
143
143
1
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23
add a comment |
1
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23
1
1
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23
add a comment |
2 Answers
2
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oldest
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The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.
add a comment |
Yes, you have to delete the last 2.
Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$
add a comment |
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2 Answers
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2 Answers
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The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.
add a comment |
The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.
add a comment |
The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.
The last $2$ should not be there. The first three terms give the chance of getting specifically red,green,blue. The $3!$ is the number of orders of colors and you are done.
answered Dec 28 '18 at 14:13
Ross MillikanRoss Millikan
292k23197371
292k23197371
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Yes, you have to delete the last 2.
Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$
add a comment |
Yes, you have to delete the last 2.
Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$
add a comment |
Yes, you have to delete the last 2.
Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$
Yes, you have to delete the last 2.
Maybe the teacher wanted to just put $3 cdot 2$ and not $3! cdot 2$
answered Dec 28 '18 at 14:35
Angel MorenoAngel Moreno
37915
37915
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1
So how many times do you take a ball out from the bag (and put it back)?
– Matti P.
Dec 28 '18 at 14:02
I guess you draw $3$ balls after each other. Is that correct? Further (just like you) I think that multiplying by $2$ is not correct.
– drhab
Dec 28 '18 at 14:02
Yes 3 balls sorry I forgot to mention that
– S. Surya
Dec 28 '18 at 14:06
I expect the teacher meant to write $3times 2$ instead of $3!times 2$.
– lulu
Dec 28 '18 at 14:23