Iwahori versus Bruhat decompositions












10












$begingroup$


I am faced with the following issue that I do not understand but seems contradictory, coming from the book of Roberts and Schmidt about $GSp(4)$. Consider a local non-archimedean field $F$, let $p$ be its maximal ideal, $mathcal{O}$ its ring of integers and $G=GSp(4, F)$. We are interested in the following Klingen congruence subgroup
$$K =
left(
begin{array}{cccc}
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
p & mathcal{O} & mathcal{O} & mathcal{O} \
p & mathcal{O} & mathcal{O} & mathcal{O} \
p & p & p & mathcal{O}
end{array}
right)
$$



(from now on all the subgroups written in this matrix-entries form is meant to be their intersection with $GSp(4, F)$. I am interested in computing the index of this subgroup in the maximal compact subgroup $K_0$ (where all the entries are integers).



Iwahori decomposition
We have
$$
K =
left(
begin{array}{cccc}
1 & & & \
p & 1 & & \
p & & 1 & \
p & p & p & 1
end{array}
right)
left(
begin{array}{cccc}
mathcal{O}^times & & & \
& mathcal{O} & mathcal{O} & \
& mathcal{O} & mathcal{O} & \
& & & mathcal{O}^times
end{array}
right)
left(
begin{array}{cccc}
1 & mathcal{O} & mathcal{O} & mathcal{O} \
& 1 & & mathcal{O} \
& & 1 & mathcal{O} \
& & & 1
end{array}
right)
$$



so that in particular by decomposing the left subgroup we should obtain
$$
left(
begin{array}{cccc}
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O}
end{array}
right)
=
bigsqcup_{a, b, c in mathcal{O}/p}
left(
begin{array}{cccc}
1 & & & \
a & 1 & & \
b & & 1 & \
c & b & -a & 1
end{array}
right)
K
$$



(where the fact that the entries on the right are this way comes from the conditions of belonging to $GSp(4)$). So that in particular the index should be, writting $N(p)$ for the norm of $p$,




$$[K_0:K] =N(p)^3$$




Bruhat decomposition
On the other hand, introducing the subgroup
$$
Q =
left(
begin{array}{cccc}
mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
& mathcal{O} & mathcal{O} & mathcal{O} \
& mathcal{O} & mathcal{O} & mathcal{O} \
& & & mathcal{O}
end{array}
right)
$$



the Bruhat decomposition yields that for any field $k$,
$$
GSp(4, k) = Q
sqcup Qx
left(
begin{array}{cccc}
1 & k & & \
& 1 & & \
& & 1 & k \
& & & 1
end{array}
right)
sqcup
Qxy
left(
begin{array}{cccc}
1 & & k & \
& 1 & k & k \
& & 1 & \
& & & 1
end{array}
right)
sqcup
Qxyx
left(
begin{array}{cccc}
1 & k & k & k\
& 1 & & k\
& & 1 & k \
& & & 1
end{array}
right)
$$



where the transformations $x$ and $y$ are defined by
$$x=
left(
begin{array}{cccc}
& 1& & \
1 & & & \
& & & 1 \
& &1 &
end{array}
right)
$$

$$y =
left(
begin{array}{cccc}
1 & & &\
& & 1 & \
& -1 & & \
& & & 1
end{array}
right)
$$



In particular if $k$ is the finite field with $N(p)$ elements, the index we search for is exactly the cardinality of $GSp(4,k) / Q$, and this one is $(1+N(p))(1+N(p)^2)$, so that we should say




$$[K_0:K] =(1+N(p))(1+N(p)^2)$$




Here is the question following from this discussion:




Both results are different even if asymptotically equivalent, what is
happening?











share|cite|improve this question











$endgroup$

















    10












    $begingroup$


    I am faced with the following issue that I do not understand but seems contradictory, coming from the book of Roberts and Schmidt about $GSp(4)$. Consider a local non-archimedean field $F$, let $p$ be its maximal ideal, $mathcal{O}$ its ring of integers and $G=GSp(4, F)$. We are interested in the following Klingen congruence subgroup
    $$K =
    left(
    begin{array}{cccc}
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
    p & mathcal{O} & mathcal{O} & mathcal{O} \
    p & mathcal{O} & mathcal{O} & mathcal{O} \
    p & p & p & mathcal{O}
    end{array}
    right)
    $$



    (from now on all the subgroups written in this matrix-entries form is meant to be their intersection with $GSp(4, F)$. I am interested in computing the index of this subgroup in the maximal compact subgroup $K_0$ (where all the entries are integers).



    Iwahori decomposition
    We have
    $$
    K =
    left(
    begin{array}{cccc}
    1 & & & \
    p & 1 & & \
    p & & 1 & \
    p & p & p & 1
    end{array}
    right)
    left(
    begin{array}{cccc}
    mathcal{O}^times & & & \
    & mathcal{O} & mathcal{O} & \
    & mathcal{O} & mathcal{O} & \
    & & & mathcal{O}^times
    end{array}
    right)
    left(
    begin{array}{cccc}
    1 & mathcal{O} & mathcal{O} & mathcal{O} \
    & 1 & & mathcal{O} \
    & & 1 & mathcal{O} \
    & & & 1
    end{array}
    right)
    $$



    so that in particular by decomposing the left subgroup we should obtain
    $$
    left(
    begin{array}{cccc}
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O}
    end{array}
    right)
    =
    bigsqcup_{a, b, c in mathcal{O}/p}
    left(
    begin{array}{cccc}
    1 & & & \
    a & 1 & & \
    b & & 1 & \
    c & b & -a & 1
    end{array}
    right)
    K
    $$



    (where the fact that the entries on the right are this way comes from the conditions of belonging to $GSp(4)$). So that in particular the index should be, writting $N(p)$ for the norm of $p$,




    $$[K_0:K] =N(p)^3$$




    Bruhat decomposition
    On the other hand, introducing the subgroup
    $$
    Q =
    left(
    begin{array}{cccc}
    mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
    & mathcal{O} & mathcal{O} & mathcal{O} \
    & mathcal{O} & mathcal{O} & mathcal{O} \
    & & & mathcal{O}
    end{array}
    right)
    $$



    the Bruhat decomposition yields that for any field $k$,
    $$
    GSp(4, k) = Q
    sqcup Qx
    left(
    begin{array}{cccc}
    1 & k & & \
    & 1 & & \
    & & 1 & k \
    & & & 1
    end{array}
    right)
    sqcup
    Qxy
    left(
    begin{array}{cccc}
    1 & & k & \
    & 1 & k & k \
    & & 1 & \
    & & & 1
    end{array}
    right)
    sqcup
    Qxyx
    left(
    begin{array}{cccc}
    1 & k & k & k\
    & 1 & & k\
    & & 1 & k \
    & & & 1
    end{array}
    right)
    $$



    where the transformations $x$ and $y$ are defined by
    $$x=
    left(
    begin{array}{cccc}
    & 1& & \
    1 & & & \
    & & & 1 \
    & &1 &
    end{array}
    right)
    $$

    $$y =
    left(
    begin{array}{cccc}
    1 & & &\
    & & 1 & \
    & -1 & & \
    & & & 1
    end{array}
    right)
    $$



    In particular if $k$ is the finite field with $N(p)$ elements, the index we search for is exactly the cardinality of $GSp(4,k) / Q$, and this one is $(1+N(p))(1+N(p)^2)$, so that we should say




    $$[K_0:K] =(1+N(p))(1+N(p)^2)$$




    Here is the question following from this discussion:




    Both results are different even if asymptotically equivalent, what is
    happening?











    share|cite|improve this question











    $endgroup$















      10












      10








      10


      1



      $begingroup$


      I am faced with the following issue that I do not understand but seems contradictory, coming from the book of Roberts and Schmidt about $GSp(4)$. Consider a local non-archimedean field $F$, let $p$ be its maximal ideal, $mathcal{O}$ its ring of integers and $G=GSp(4, F)$. We are interested in the following Klingen congruence subgroup
      $$K =
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      p & mathcal{O} & mathcal{O} & mathcal{O} \
      p & mathcal{O} & mathcal{O} & mathcal{O} \
      p & p & p & mathcal{O}
      end{array}
      right)
      $$



      (from now on all the subgroups written in this matrix-entries form is meant to be their intersection with $GSp(4, F)$. I am interested in computing the index of this subgroup in the maximal compact subgroup $K_0$ (where all the entries are integers).



      Iwahori decomposition
      We have
      $$
      K =
      left(
      begin{array}{cccc}
      1 & & & \
      p & 1 & & \
      p & & 1 & \
      p & p & p & 1
      end{array}
      right)
      left(
      begin{array}{cccc}
      mathcal{O}^times & & & \
      & mathcal{O} & mathcal{O} & \
      & mathcal{O} & mathcal{O} & \
      & & & mathcal{O}^times
      end{array}
      right)
      left(
      begin{array}{cccc}
      1 & mathcal{O} & mathcal{O} & mathcal{O} \
      & 1 & & mathcal{O} \
      & & 1 & mathcal{O} \
      & & & 1
      end{array}
      right)
      $$



      so that in particular by decomposing the left subgroup we should obtain
      $$
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O}
      end{array}
      right)
      =
      bigsqcup_{a, b, c in mathcal{O}/p}
      left(
      begin{array}{cccc}
      1 & & & \
      a & 1 & & \
      b & & 1 & \
      c & b & -a & 1
      end{array}
      right)
      K
      $$



      (where the fact that the entries on the right are this way comes from the conditions of belonging to $GSp(4)$). So that in particular the index should be, writting $N(p)$ for the norm of $p$,




      $$[K_0:K] =N(p)^3$$




      Bruhat decomposition
      On the other hand, introducing the subgroup
      $$
      Q =
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      & mathcal{O} & mathcal{O} & mathcal{O} \
      & mathcal{O} & mathcal{O} & mathcal{O} \
      & & & mathcal{O}
      end{array}
      right)
      $$



      the Bruhat decomposition yields that for any field $k$,
      $$
      GSp(4, k) = Q
      sqcup Qx
      left(
      begin{array}{cccc}
      1 & k & & \
      & 1 & & \
      & & 1 & k \
      & & & 1
      end{array}
      right)
      sqcup
      Qxy
      left(
      begin{array}{cccc}
      1 & & k & \
      & 1 & k & k \
      & & 1 & \
      & & & 1
      end{array}
      right)
      sqcup
      Qxyx
      left(
      begin{array}{cccc}
      1 & k & k & k\
      & 1 & & k\
      & & 1 & k \
      & & & 1
      end{array}
      right)
      $$



      where the transformations $x$ and $y$ are defined by
      $$x=
      left(
      begin{array}{cccc}
      & 1& & \
      1 & & & \
      & & & 1 \
      & &1 &
      end{array}
      right)
      $$

      $$y =
      left(
      begin{array}{cccc}
      1 & & &\
      & & 1 & \
      & -1 & & \
      & & & 1
      end{array}
      right)
      $$



      In particular if $k$ is the finite field with $N(p)$ elements, the index we search for is exactly the cardinality of $GSp(4,k) / Q$, and this one is $(1+N(p))(1+N(p)^2)$, so that we should say




      $$[K_0:K] =(1+N(p))(1+N(p)^2)$$




      Here is the question following from this discussion:




      Both results are different even if asymptotically equivalent, what is
      happening?











      share|cite|improve this question











      $endgroup$




      I am faced with the following issue that I do not understand but seems contradictory, coming from the book of Roberts and Schmidt about $GSp(4)$. Consider a local non-archimedean field $F$, let $p$ be its maximal ideal, $mathcal{O}$ its ring of integers and $G=GSp(4, F)$. We are interested in the following Klingen congruence subgroup
      $$K =
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      p & mathcal{O} & mathcal{O} & mathcal{O} \
      p & mathcal{O} & mathcal{O} & mathcal{O} \
      p & p & p & mathcal{O}
      end{array}
      right)
      $$



      (from now on all the subgroups written in this matrix-entries form is meant to be their intersection with $GSp(4, F)$. I am interested in computing the index of this subgroup in the maximal compact subgroup $K_0$ (where all the entries are integers).



      Iwahori decomposition
      We have
      $$
      K =
      left(
      begin{array}{cccc}
      1 & & & \
      p & 1 & & \
      p & & 1 & \
      p & p & p & 1
      end{array}
      right)
      left(
      begin{array}{cccc}
      mathcal{O}^times & & & \
      & mathcal{O} & mathcal{O} & \
      & mathcal{O} & mathcal{O} & \
      & & & mathcal{O}^times
      end{array}
      right)
      left(
      begin{array}{cccc}
      1 & mathcal{O} & mathcal{O} & mathcal{O} \
      & 1 & & mathcal{O} \
      & & 1 & mathcal{O} \
      & & & 1
      end{array}
      right)
      $$



      so that in particular by decomposing the left subgroup we should obtain
      $$
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O}
      end{array}
      right)
      =
      bigsqcup_{a, b, c in mathcal{O}/p}
      left(
      begin{array}{cccc}
      1 & & & \
      a & 1 & & \
      b & & 1 & \
      c & b & -a & 1
      end{array}
      right)
      K
      $$



      (where the fact that the entries on the right are this way comes from the conditions of belonging to $GSp(4)$). So that in particular the index should be, writting $N(p)$ for the norm of $p$,




      $$[K_0:K] =N(p)^3$$




      Bruhat decomposition
      On the other hand, introducing the subgroup
      $$
      Q =
      left(
      begin{array}{cccc}
      mathcal{O} & mathcal{O} & mathcal{O} & mathcal{O} \
      & mathcal{O} & mathcal{O} & mathcal{O} \
      & mathcal{O} & mathcal{O} & mathcal{O} \
      & & & mathcal{O}
      end{array}
      right)
      $$



      the Bruhat decomposition yields that for any field $k$,
      $$
      GSp(4, k) = Q
      sqcup Qx
      left(
      begin{array}{cccc}
      1 & k & & \
      & 1 & & \
      & & 1 & k \
      & & & 1
      end{array}
      right)
      sqcup
      Qxy
      left(
      begin{array}{cccc}
      1 & & k & \
      & 1 & k & k \
      & & 1 & \
      & & & 1
      end{array}
      right)
      sqcup
      Qxyx
      left(
      begin{array}{cccc}
      1 & k & k & k\
      & 1 & & k\
      & & 1 & k \
      & & & 1
      end{array}
      right)
      $$



      where the transformations $x$ and $y$ are defined by
      $$x=
      left(
      begin{array}{cccc}
      & 1& & \
      1 & & & \
      & & & 1 \
      & &1 &
      end{array}
      right)
      $$

      $$y =
      left(
      begin{array}{cccc}
      1 & & &\
      & & 1 & \
      & -1 & & \
      & & & 1
      end{array}
      right)
      $$



      In particular if $k$ is the finite field with $N(p)$ elements, the index we search for is exactly the cardinality of $GSp(4,k) / Q$, and this one is $(1+N(p))(1+N(p)^2)$, so that we should say




      $$[K_0:K] =(1+N(p))(1+N(p)^2)$$




      Here is the question following from this discussion:




      Both results are different even if asymptotically equivalent, what is
      happening?








      group-theory number-theory proof-verification






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 13 at 9:40







      TheStudent

















      asked Jan 10 at 9:21









      TheStudentTheStudent

      3239




      3239






















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