Evaluate $int vec{F}.ndS$ where $S$ is the entire surface of the solid formed by?












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Evaluate $int vec{F}.ndS$ where $S$ is the entire surface of the solid formed by $x^2+y^2=a^2, z=x+1, z=0$ and $n$ is the outward drawn unit normal and the vector function $vec{F}=langle2x,-3y,zrangle$



My question is, can I directly apply the divergence theorem in this?
Using the divergence theorem, since divergence of F is zero, we are getting zero.










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  • $begingroup$
    I can't see why wouldn't you be able to use the divergence theorem...
    $endgroup$
    – DonAntonio
    Jan 10 at 13:11
















0












$begingroup$


Evaluate $int vec{F}.ndS$ where $S$ is the entire surface of the solid formed by $x^2+y^2=a^2, z=x+1, z=0$ and $n$ is the outward drawn unit normal and the vector function $vec{F}=langle2x,-3y,zrangle$



My question is, can I directly apply the divergence theorem in this?
Using the divergence theorem, since divergence of F is zero, we are getting zero.










share|cite|improve this question









$endgroup$












  • $begingroup$
    I can't see why wouldn't you be able to use the divergence theorem...
    $endgroup$
    – DonAntonio
    Jan 10 at 13:11














0












0








0





$begingroup$


Evaluate $int vec{F}.ndS$ where $S$ is the entire surface of the solid formed by $x^2+y^2=a^2, z=x+1, z=0$ and $n$ is the outward drawn unit normal and the vector function $vec{F}=langle2x,-3y,zrangle$



My question is, can I directly apply the divergence theorem in this?
Using the divergence theorem, since divergence of F is zero, we are getting zero.










share|cite|improve this question









$endgroup$




Evaluate $int vec{F}.ndS$ where $S$ is the entire surface of the solid formed by $x^2+y^2=a^2, z=x+1, z=0$ and $n$ is the outward drawn unit normal and the vector function $vec{F}=langle2x,-3y,zrangle$



My question is, can I directly apply the divergence theorem in this?
Using the divergence theorem, since divergence of F is zero, we are getting zero.







vector-analysis vector-fields






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asked Jan 10 at 12:51









AbhayAbhay

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3739












  • $begingroup$
    I can't see why wouldn't you be able to use the divergence theorem...
    $endgroup$
    – DonAntonio
    Jan 10 at 13:11


















  • $begingroup$
    I can't see why wouldn't you be able to use the divergence theorem...
    $endgroup$
    – DonAntonio
    Jan 10 at 13:11
















$begingroup$
I can't see why wouldn't you be able to use the divergence theorem...
$endgroup$
– DonAntonio
Jan 10 at 13:11




$begingroup$
I can't see why wouldn't you be able to use the divergence theorem...
$endgroup$
– DonAntonio
Jan 10 at 13:11










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You can apply the divergence theorem here. $$nablacdotvec F=Big(frac{partial}{partial x},frac{partial}{partial y},frac{partial}{partial z}Big)cdotbig(2x,-3y,zbig)=2-3+1=0$$giving the answer $0$.






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    $begingroup$

    You can apply the divergence theorem here. $$nablacdotvec F=Big(frac{partial}{partial x},frac{partial}{partial y},frac{partial}{partial z}Big)cdotbig(2x,-3y,zbig)=2-3+1=0$$giving the answer $0$.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      You can apply the divergence theorem here. $$nablacdotvec F=Big(frac{partial}{partial x},frac{partial}{partial y},frac{partial}{partial z}Big)cdotbig(2x,-3y,zbig)=2-3+1=0$$giving the answer $0$.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        You can apply the divergence theorem here. $$nablacdotvec F=Big(frac{partial}{partial x},frac{partial}{partial y},frac{partial}{partial z}Big)cdotbig(2x,-3y,zbig)=2-3+1=0$$giving the answer $0$.






        share|cite|improve this answer











        $endgroup$



        You can apply the divergence theorem here. $$nablacdotvec F=Big(frac{partial}{partial x},frac{partial}{partial y},frac{partial}{partial z}Big)cdotbig(2x,-3y,zbig)=2-3+1=0$$giving the answer $0$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Jan 10 at 16:57

























        answered Jan 10 at 16:52









        Shubham JohriShubham Johri

        5,204718




        5,204718






























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