Calculating expected payoff from, with $Pr(C>c)$ or $(1 - F(c))$.
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 '18 at 8:18
t.ysn
1357
edited Dec 27 '18 at 8:18
t.ysn
1357
edited Dec 27 '18 at 8:18
t.ysn
1357
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 27 '18 at 3:16
Yasir Khan
1
asked Dec 27 '18 at 3:16
Yasir Khan
1
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Yasir Khan is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3053564%2fcalculating-expected-payoff-from-with-prcc-or-1-fc%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yasir Khan is a new contributor. Be nice, and check out our Code of Conduct.
Yasir Khan is a new contributor. Be nice, and check out our Code of Conduct.
Yasir Khan is a new contributor. Be nice, and check out our Code of Conduct.
Yasir Khan is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3053564%2fcalculating-expected-payoff-from-with-prcc-or-1-fc%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
