How do I calculate SS of a Variable and Error provided data












0












$begingroup$


Yields are noted for tree samples from four different varieties in crops in Argentina.



The following varieties are:
Variety A = 15, 14, 12, 13



Variety B = 11, 18, 13



Variety C = 18, 25, 19, 20



Variety D = 19, 20, 24.



My "teacher" gave me the values of:



SS Variety = 172.36
SS Error = 74



I am competent with calculating degrees of freedom. But here, he provided me with these values, I would like to ask how they calculated.



My knowledge with ANOVA is that SS = Sum of Squares. With other examples I would square each data value - but I would think that it would clearly exceed the value given.



And so I am asking - how this value is calculated.



Thanks.










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$endgroup$

















    0












    $begingroup$


    Yields are noted for tree samples from four different varieties in crops in Argentina.



    The following varieties are:
    Variety A = 15, 14, 12, 13



    Variety B = 11, 18, 13



    Variety C = 18, 25, 19, 20



    Variety D = 19, 20, 24.



    My "teacher" gave me the values of:



    SS Variety = 172.36
    SS Error = 74



    I am competent with calculating degrees of freedom. But here, he provided me with these values, I would like to ask how they calculated.



    My knowledge with ANOVA is that SS = Sum of Squares. With other examples I would square each data value - but I would think that it would clearly exceed the value given.



    And so I am asking - how this value is calculated.



    Thanks.










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      Yields are noted for tree samples from four different varieties in crops in Argentina.



      The following varieties are:
      Variety A = 15, 14, 12, 13



      Variety B = 11, 18, 13



      Variety C = 18, 25, 19, 20



      Variety D = 19, 20, 24.



      My "teacher" gave me the values of:



      SS Variety = 172.36
      SS Error = 74



      I am competent with calculating degrees of freedom. But here, he provided me with these values, I would like to ask how they calculated.



      My knowledge with ANOVA is that SS = Sum of Squares. With other examples I would square each data value - but I would think that it would clearly exceed the value given.



      And so I am asking - how this value is calculated.



      Thanks.










      share|cite|improve this question











      $endgroup$




      Yields are noted for tree samples from four different varieties in crops in Argentina.



      The following varieties are:
      Variety A = 15, 14, 12, 13



      Variety B = 11, 18, 13



      Variety C = 18, 25, 19, 20



      Variety D = 19, 20, 24.



      My "teacher" gave me the values of:



      SS Variety = 172.36
      SS Error = 74



      I am competent with calculating degrees of freedom. But here, he provided me with these values, I would like to ask how they calculated.



      My knowledge with ANOVA is that SS = Sum of Squares. With other examples I would square each data value - but I would think that it would clearly exceed the value given.



      And so I am asking - how this value is calculated.



      Thanks.







      statistics statistical-inference






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      edited Jan 8 at 22:55







      princetongirl818

















      asked Jan 8 at 22:22









      princetongirl818princetongirl818

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          $begingroup$

          The overall mean is about $17.21429$ while the means for each variety are $13.5,14,20.5,21$



          What you are describing as SS Variety is calculated as $$4times (13.5-17.21429)^2 + 3times (14-17.21429)^2 + 4times (20.5-17.21429)^2 + 3times (21.5-17.21429)^2$$



          What you are describing as SS Error is calculated as $$(15-13.5)^2 + (14-13.5)^2 + (12-13.5)^2 + (13-13.5)^2 + \ (11-14)^2 + (13-14)^2 + (18-14)^2 + \ (18-20.5)^2 + (25-20.5)^2 + (19-20.5)^2 + (20-20.5)^2 + \ (19-21)^2 + (20-21)^2 + (24-21)^2 $$



          If you add these together, you get the overall sum of squares of differences from the overall mean of about $246.3571$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you a lot for your help. This made things a lot clearer.
            $endgroup$
            – princetongirl818
            Jan 10 at 22:29











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          1 Answer
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          $begingroup$

          The overall mean is about $17.21429$ while the means for each variety are $13.5,14,20.5,21$



          What you are describing as SS Variety is calculated as $$4times (13.5-17.21429)^2 + 3times (14-17.21429)^2 + 4times (20.5-17.21429)^2 + 3times (21.5-17.21429)^2$$



          What you are describing as SS Error is calculated as $$(15-13.5)^2 + (14-13.5)^2 + (12-13.5)^2 + (13-13.5)^2 + \ (11-14)^2 + (13-14)^2 + (18-14)^2 + \ (18-20.5)^2 + (25-20.5)^2 + (19-20.5)^2 + (20-20.5)^2 + \ (19-21)^2 + (20-21)^2 + (24-21)^2 $$



          If you add these together, you get the overall sum of squares of differences from the overall mean of about $246.3571$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you a lot for your help. This made things a lot clearer.
            $endgroup$
            – princetongirl818
            Jan 10 at 22:29
















          1












          $begingroup$

          The overall mean is about $17.21429$ while the means for each variety are $13.5,14,20.5,21$



          What you are describing as SS Variety is calculated as $$4times (13.5-17.21429)^2 + 3times (14-17.21429)^2 + 4times (20.5-17.21429)^2 + 3times (21.5-17.21429)^2$$



          What you are describing as SS Error is calculated as $$(15-13.5)^2 + (14-13.5)^2 + (12-13.5)^2 + (13-13.5)^2 + \ (11-14)^2 + (13-14)^2 + (18-14)^2 + \ (18-20.5)^2 + (25-20.5)^2 + (19-20.5)^2 + (20-20.5)^2 + \ (19-21)^2 + (20-21)^2 + (24-21)^2 $$



          If you add these together, you get the overall sum of squares of differences from the overall mean of about $246.3571$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you a lot for your help. This made things a lot clearer.
            $endgroup$
            – princetongirl818
            Jan 10 at 22:29














          1












          1








          1





          $begingroup$

          The overall mean is about $17.21429$ while the means for each variety are $13.5,14,20.5,21$



          What you are describing as SS Variety is calculated as $$4times (13.5-17.21429)^2 + 3times (14-17.21429)^2 + 4times (20.5-17.21429)^2 + 3times (21.5-17.21429)^2$$



          What you are describing as SS Error is calculated as $$(15-13.5)^2 + (14-13.5)^2 + (12-13.5)^2 + (13-13.5)^2 + \ (11-14)^2 + (13-14)^2 + (18-14)^2 + \ (18-20.5)^2 + (25-20.5)^2 + (19-20.5)^2 + (20-20.5)^2 + \ (19-21)^2 + (20-21)^2 + (24-21)^2 $$



          If you add these together, you get the overall sum of squares of differences from the overall mean of about $246.3571$






          share|cite|improve this answer









          $endgroup$



          The overall mean is about $17.21429$ while the means for each variety are $13.5,14,20.5,21$



          What you are describing as SS Variety is calculated as $$4times (13.5-17.21429)^2 + 3times (14-17.21429)^2 + 4times (20.5-17.21429)^2 + 3times (21.5-17.21429)^2$$



          What you are describing as SS Error is calculated as $$(15-13.5)^2 + (14-13.5)^2 + (12-13.5)^2 + (13-13.5)^2 + \ (11-14)^2 + (13-14)^2 + (18-14)^2 + \ (18-20.5)^2 + (25-20.5)^2 + (19-20.5)^2 + (20-20.5)^2 + \ (19-21)^2 + (20-21)^2 + (24-21)^2 $$



          If you add these together, you get the overall sum of squares of differences from the overall mean of about $246.3571$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 9 at 1:11









          HenryHenry

          100k481167




          100k481167












          • $begingroup$
            Thank you a lot for your help. This made things a lot clearer.
            $endgroup$
            – princetongirl818
            Jan 10 at 22:29


















          • $begingroup$
            Thank you a lot for your help. This made things a lot clearer.
            $endgroup$
            – princetongirl818
            Jan 10 at 22:29
















          $begingroup$
          Thank you a lot for your help. This made things a lot clearer.
          $endgroup$
          – princetongirl818
          Jan 10 at 22:29




          $begingroup$
          Thank you a lot for your help. This made things a lot clearer.
          $endgroup$
          – princetongirl818
          Jan 10 at 22:29


















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