How can I make a NumberLineLogPlot'?
$begingroup$
I have a piecewise function that is defined in logarithmic intervals, i.e., the different pieces are defined on
{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}
I'd like to visualize the different domains on a number line.
NumberLinePlot
, of course, works, but it looks clumsy as the plot is fully dominated by the last domain an the first one is barely visible:
NumberLinePlot[{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}, {x, 1, 1000}]
So I can use something along the lines of
NumberLinePlot[
{{Log[10, 1] <= x <= Log[10, 10]},
{Log[10, 10] <= x <= Log[10, 100]},
{Log[10, 100] <= x <= Log[10, 1000]}},
{x, Log[10, 1], Log[10, 1000]}]
which results in a much more pleasantly balanced plot:
However, now the number line ticks show the exponents — so in essence I'd like something like NumberLineLogPlot
, but that doesn't exist.
I tried to recreate something like that by abusing LogLogPlot
Show[
MapThread[
LogLogPlot[#1, #2, PlotStyle -> #3] &,
{{1, 2, 4}, {x, #[[1, 1]], #[[1, 3]]} & /@ dx , {Red, Green, Blue}}],
PlotRange -> Automatic, Frame -> {{False, False}, {True, False}}]
Which leads to something like
which is better in terms of the logarithmic x-axis but is quite clumsy in other ways.
Any ideas how to implement a NumberLineLogPlot
nicely?
piecewise ticks numberlineplot loglogplot
$endgroup$
add a comment |
$begingroup$
I have a piecewise function that is defined in logarithmic intervals, i.e., the different pieces are defined on
{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}
I'd like to visualize the different domains on a number line.
NumberLinePlot
, of course, works, but it looks clumsy as the plot is fully dominated by the last domain an the first one is barely visible:
NumberLinePlot[{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}, {x, 1, 1000}]
So I can use something along the lines of
NumberLinePlot[
{{Log[10, 1] <= x <= Log[10, 10]},
{Log[10, 10] <= x <= Log[10, 100]},
{Log[10, 100] <= x <= Log[10, 1000]}},
{x, Log[10, 1], Log[10, 1000]}]
which results in a much more pleasantly balanced plot:
However, now the number line ticks show the exponents — so in essence I'd like something like NumberLineLogPlot
, but that doesn't exist.
I tried to recreate something like that by abusing LogLogPlot
Show[
MapThread[
LogLogPlot[#1, #2, PlotStyle -> #3] &,
{{1, 2, 4}, {x, #[[1, 1]], #[[1, 3]]} & /@ dx , {Red, Green, Blue}}],
PlotRange -> Automatic, Frame -> {{False, False}, {True, False}}]
Which leads to something like
which is better in terms of the logarithmic x-axis but is quite clumsy in other ways.
Any ideas how to implement a NumberLineLogPlot
nicely?
piecewise ticks numberlineplot loglogplot
$endgroup$
add a comment |
$begingroup$
I have a piecewise function that is defined in logarithmic intervals, i.e., the different pieces are defined on
{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}
I'd like to visualize the different domains on a number line.
NumberLinePlot
, of course, works, but it looks clumsy as the plot is fully dominated by the last domain an the first one is barely visible:
NumberLinePlot[{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}, {x, 1, 1000}]
So I can use something along the lines of
NumberLinePlot[
{{Log[10, 1] <= x <= Log[10, 10]},
{Log[10, 10] <= x <= Log[10, 100]},
{Log[10, 100] <= x <= Log[10, 1000]}},
{x, Log[10, 1], Log[10, 1000]}]
which results in a much more pleasantly balanced plot:
However, now the number line ticks show the exponents — so in essence I'd like something like NumberLineLogPlot
, but that doesn't exist.
I tried to recreate something like that by abusing LogLogPlot
Show[
MapThread[
LogLogPlot[#1, #2, PlotStyle -> #3] &,
{{1, 2, 4}, {x, #[[1, 1]], #[[1, 3]]} & /@ dx , {Red, Green, Blue}}],
PlotRange -> Automatic, Frame -> {{False, False}, {True, False}}]
Which leads to something like
which is better in terms of the logarithmic x-axis but is quite clumsy in other ways.
Any ideas how to implement a NumberLineLogPlot
nicely?
piecewise ticks numberlineplot loglogplot
$endgroup$
I have a piecewise function that is defined in logarithmic intervals, i.e., the different pieces are defined on
{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}
I'd like to visualize the different domains on a number line.
NumberLinePlot
, of course, works, but it looks clumsy as the plot is fully dominated by the last domain an the first one is barely visible:
NumberLinePlot[{{1. <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}}, {x, 1, 1000}]
So I can use something along the lines of
NumberLinePlot[
{{Log[10, 1] <= x <= Log[10, 10]},
{Log[10, 10] <= x <= Log[10, 100]},
{Log[10, 100] <= x <= Log[10, 1000]}},
{x, Log[10, 1], Log[10, 1000]}]
which results in a much more pleasantly balanced plot:
However, now the number line ticks show the exponents — so in essence I'd like something like NumberLineLogPlot
, but that doesn't exist.
I tried to recreate something like that by abusing LogLogPlot
Show[
MapThread[
LogLogPlot[#1, #2, PlotStyle -> #3] &,
{{1, 2, 4}, {x, #[[1, 1]], #[[1, 3]]} & /@ dx , {Red, Green, Blue}}],
PlotRange -> Automatic, Frame -> {{False, False}, {True, False}}]
Which leads to something like
which is better in terms of the logarithmic x-axis but is quite clumsy in other ways.
Any ideas how to implement a NumberLineLogPlot
nicely?
piecewise ticks numberlineplot loglogplot
piecewise ticks numberlineplot loglogplot
edited Feb 3 at 15:13
m_goldberg
87.7k872198
87.7k872198
asked Feb 3 at 13:00
Oliver JennrichOliver Jennrich
887411
887411
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Use the option Ticks
intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}};
logIntervals = intervals /. {n_?NumericQ :> Log10[n]}
(* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *)
NumberLinePlot[logIntervals, {x, 0, 3},
Ticks -> {({Log10[#], #} & /@
{1, 2, 5, 10, 20, 50, 100, 200, 500, 1000}), None}]
$endgroup$
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
add a comment |
$begingroup$
You can also transform intervals
into a list of lists and use ListLinePlot
with the option ScalingFunctions
:
lst = MapIndexed[Thread[{#[[1]], #2[[1]]/2}] &, intervals /. LessEqual -> ({#, #3} &)];
Show[ListLinePlot[lst, ScalingFunctions -> {{Log[10, #] &, 10^# &}, None},
Joined -> #] & /@ {True, False}, AspectRatio -> 1/5, Axes -> {True, False}]
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Use the option Ticks
intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}};
logIntervals = intervals /. {n_?NumericQ :> Log10[n]}
(* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *)
NumberLinePlot[logIntervals, {x, 0, 3},
Ticks -> {({Log10[#], #} & /@
{1, 2, 5, 10, 20, 50, 100, 200, 500, 1000}), None}]
$endgroup$
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
add a comment |
$begingroup$
Use the option Ticks
intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}};
logIntervals = intervals /. {n_?NumericQ :> Log10[n]}
(* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *)
NumberLinePlot[logIntervals, {x, 0, 3},
Ticks -> {({Log10[#], #} & /@
{1, 2, 5, 10, 20, 50, 100, 200, 500, 1000}), None}]
$endgroup$
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
add a comment |
$begingroup$
Use the option Ticks
intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}};
logIntervals = intervals /. {n_?NumericQ :> Log10[n]}
(* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *)
NumberLinePlot[logIntervals, {x, 0, 3},
Ticks -> {({Log10[#], #} & /@
{1, 2, 5, 10, 20, 50, 100, 200, 500, 1000}), None}]
$endgroup$
Use the option Ticks
intervals = {{1 <= x <= 10}, {10 <= x <= 100}, {100 <= x <= 1000}};
logIntervals = intervals /. {n_?NumericQ :> Log10[n]}
(* {{0 <= x <= 1}, {1 <= x <= 2}, {2 <= x <= 3}} *)
NumberLinePlot[logIntervals, {x, 0, 3},
Ticks -> {({Log10[#], #} & /@
{1, 2, 5, 10, 20, 50, 100, 200, 500, 1000}), None}]
answered Feb 3 at 14:39
Bob HanlonBob Hanlon
60.8k33597
60.8k33597
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
add a comment |
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
$begingroup$
Nice one! I particularly like the trick with the patternreplacement for the Log
$endgroup$
– Oliver Jennrich
Feb 3 at 15:32
add a comment |
$begingroup$
You can also transform intervals
into a list of lists and use ListLinePlot
with the option ScalingFunctions
:
lst = MapIndexed[Thread[{#[[1]], #2[[1]]/2}] &, intervals /. LessEqual -> ({#, #3} &)];
Show[ListLinePlot[lst, ScalingFunctions -> {{Log[10, #] &, 10^# &}, None},
Joined -> #] & /@ {True, False}, AspectRatio -> 1/5, Axes -> {True, False}]
$endgroup$
add a comment |
$begingroup$
You can also transform intervals
into a list of lists and use ListLinePlot
with the option ScalingFunctions
:
lst = MapIndexed[Thread[{#[[1]], #2[[1]]/2}] &, intervals /. LessEqual -> ({#, #3} &)];
Show[ListLinePlot[lst, ScalingFunctions -> {{Log[10, #] &, 10^# &}, None},
Joined -> #] & /@ {True, False}, AspectRatio -> 1/5, Axes -> {True, False}]
$endgroup$
add a comment |
$begingroup$
You can also transform intervals
into a list of lists and use ListLinePlot
with the option ScalingFunctions
:
lst = MapIndexed[Thread[{#[[1]], #2[[1]]/2}] &, intervals /. LessEqual -> ({#, #3} &)];
Show[ListLinePlot[lst, ScalingFunctions -> {{Log[10, #] &, 10^# &}, None},
Joined -> #] & /@ {True, False}, AspectRatio -> 1/5, Axes -> {True, False}]
$endgroup$
You can also transform intervals
into a list of lists and use ListLinePlot
with the option ScalingFunctions
:
lst = MapIndexed[Thread[{#[[1]], #2[[1]]/2}] &, intervals /. LessEqual -> ({#, #3} &)];
Show[ListLinePlot[lst, ScalingFunctions -> {{Log[10, #] &, 10^# &}, None},
Joined -> #] & /@ {True, False}, AspectRatio -> 1/5, Axes -> {True, False}]
answered Feb 4 at 4:24
kglrkglr
189k10206424
189k10206424
add a comment |
add a comment |
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