Overlaying two SmoothDensityHistograms
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I want to overlay two objects of SmoothDensityHistogram using Show, in order to highlight a region of the shared plot space. However, the top object completely obscures the bottom one. I tried to set an opacity for the objects, but SmoothDenstiyHistogram does not accept PlotStyle as an argument to pass either Opacity[...] or Directive[Opacity[...]]. Is there a way to make this work?
plotting
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add a comment |
$begingroup$
I want to overlay two objects of SmoothDensityHistogram using Show, in order to highlight a region of the shared plot space. However, the top object completely obscures the bottom one. I tried to set an opacity for the objects, but SmoothDenstiyHistogram does not accept PlotStyle as an argument to pass either Opacity[...] or Directive[Opacity[...]]. Is there a way to make this work?
plotting
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2
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Could you post example code of your histograms?
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– Carl Lange
Jan 16 at 20:15
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@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
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– avikarto
Jan 16 at 20:17
add a comment |
$begingroup$
I want to overlay two objects of SmoothDensityHistogram using Show, in order to highlight a region of the shared plot space. However, the top object completely obscures the bottom one. I tried to set an opacity for the objects, but SmoothDenstiyHistogram does not accept PlotStyle as an argument to pass either Opacity[...] or Directive[Opacity[...]]. Is there a way to make this work?
plotting
$endgroup$
I want to overlay two objects of SmoothDensityHistogram using Show, in order to highlight a region of the shared plot space. However, the top object completely obscures the bottom one. I tried to set an opacity for the objects, but SmoothDenstiyHistogram does not accept PlotStyle as an argument to pass either Opacity[...] or Directive[Opacity[...]]. Is there a way to make this work?
plotting
plotting
asked Jan 16 at 20:14
avikartoavikarto
1418
1418
2
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Could you post example code of your histograms?
$endgroup$
– Carl Lange
Jan 16 at 20:15
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@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
$endgroup$
– avikarto
Jan 16 at 20:17
add a comment |
2
$begingroup$
Could you post example code of your histograms?
$endgroup$
– Carl Lange
Jan 16 at 20:15
$begingroup$
@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
$endgroup$
– avikarto
Jan 16 at 20:17
2
2
$begingroup$
Could you post example code of your histograms?
$endgroup$
– Carl Lange
Jan 16 at 20:15
$begingroup$
Could you post example code of your histograms?
$endgroup$
– Carl Lange
Jan 16 at 20:15
$begingroup$
@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
$endgroup$
– avikarto
Jan 16 at 20:17
$begingroup$
@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
$endgroup$
– avikarto
Jan 16 at 20:17
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You can do this by setting the ColorFunction
to use Opacity
.
Let's define our ColorFunction
, which basically just returns a color for a given plot value:
cf[z_] := Opacity[z, RGBColor[z, 1 - z, 1]]
(You can also wrap any of the ColorData
functions with that Opacity
and it should work)
Now we can use that to show two plots together:
s1 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.2], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
s2 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.5], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
Overlay[{s1, s2}]
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$begingroup$
Perfect, thanks!
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– avikarto
Jan 16 at 20:31
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Do you not want to have something likeColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?
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– JimB
Jan 17 at 4:35
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@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
add a comment |
Your Answer
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
You can do this by setting the ColorFunction
to use Opacity
.
Let's define our ColorFunction
, which basically just returns a color for a given plot value:
cf[z_] := Opacity[z, RGBColor[z, 1 - z, 1]]
(You can also wrap any of the ColorData
functions with that Opacity
and it should work)
Now we can use that to show two plots together:
s1 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.2], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
s2 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.5], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
Overlay[{s1, s2}]
$endgroup$
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Do you not want to have something likeColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?
$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
add a comment |
$begingroup$
You can do this by setting the ColorFunction
to use Opacity
.
Let's define our ColorFunction
, which basically just returns a color for a given plot value:
cf[z_] := Opacity[z, RGBColor[z, 1 - z, 1]]
(You can also wrap any of the ColorData
functions with that Opacity
and it should work)
Now we can use that to show two plots together:
s1 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.2], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
s2 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.5], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
Overlay[{s1, s2}]
$endgroup$
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Do you not want to have something likeColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?
$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
add a comment |
$begingroup$
You can do this by setting the ColorFunction
to use Opacity
.
Let's define our ColorFunction
, which basically just returns a color for a given plot value:
cf[z_] := Opacity[z, RGBColor[z, 1 - z, 1]]
(You can also wrap any of the ColorData
functions with that Opacity
and it should work)
Now we can use that to show two plots together:
s1 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.2], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
s2 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.5], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
Overlay[{s1, s2}]
$endgroup$
You can do this by setting the ColorFunction
to use Opacity
.
Let's define our ColorFunction
, which basically just returns a color for a given plot value:
cf[z_] := Opacity[z, RGBColor[z, 1 - z, 1]]
(You can also wrap any of the ColorData
functions with that Opacity
and it should work)
Now we can use that to show two plots together:
s1 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.2], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
s2 = SmoothDensityHistogram[
RandomVariate[BinormalDistribution[.5], 10], PlotRange -> {-3, 3},
Frame -> None, ColorFunction -> cf]
Overlay[{s1, s2}]
answered Jan 16 at 20:21
Carl LangeCarl Lange
3,8151733
3,8151733
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Do you not want to have something likeColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?
$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
add a comment |
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Do you not want to have something likeColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?
$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Perfect, thanks!
$endgroup$
– avikarto
Jan 16 at 20:31
$begingroup$
Do you not want to have something like
ColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
Do you not want to have something like
ColorFunctionScaling -> False
? Otherwise, the highest values have the same color even if there's a large difference in the "peakedness" of the two densities?$endgroup$
– JimB
Jan 17 at 4:35
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
$begingroup$
@JimB That's a good point - probably a good idea to add your own answer working around that issue.
$endgroup$
– Carl Lange
Jan 17 at 9:03
add a comment |
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2
$begingroup$
Could you post example code of your histograms?
$endgroup$
– Carl Lange
Jan 16 at 20:15
$begingroup$
@CarlLange My histograms are generated from large data files, but any two sets of random data passed into a SmoothDensityHistogram and overlaid will show the issue.
$endgroup$
– avikarto
Jan 16 at 20:17