A question concerning Chebyshev's Theorem and the proportion of values.
$begingroup$
I took a quiz about an hour ago and the only questions I erred were ones concerning Chebyshev's theorem. I don't need to discuss them both. Nor do I want the answer. Just a hint where I messed up. Here is the question: According to Chebyshev's theorem, the proportion of values from a data set that is further than 1.5 standard deviations from the mean is at least:
a.) 0.67
b.) 0.17
c.) 1.33
d.) 0.22
Now, I plugged in the 1.5 into the "k" formula.
1-$frac{1}{1.5^2}$
and the answer I get is .55 which is nothing close to the available answers.
statistics standard-deviation
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
$endgroup$
add a comment |
$begingroup$
I took a quiz about an hour ago and the only questions I erred were ones concerning Chebyshev's theorem. I don't need to discuss them both. Nor do I want the answer. Just a hint where I messed up. Here is the question: According to Chebyshev's theorem, the proportion of values from a data set that is further than 1.5 standard deviations from the mean is at least:
a.) 0.67
b.) 0.17
c.) 1.33
d.) 0.22
Now, I plugged in the 1.5 into the "k" formula.
1-$frac{1}{1.5^2}$
and the answer I get is .55 which is nothing close to the available answers.
statistics standard-deviation
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
$endgroup$
add a comment |
$begingroup$
I took a quiz about an hour ago and the only questions I erred were ones concerning Chebyshev's theorem. I don't need to discuss them both. Nor do I want the answer. Just a hint where I messed up. Here is the question: According to Chebyshev's theorem, the proportion of values from a data set that is further than 1.5 standard deviations from the mean is at least:
a.) 0.67
b.) 0.17
c.) 1.33
d.) 0.22
Now, I plugged in the 1.5 into the "k" formula.
1-$frac{1}{1.5^2}$
and the answer I get is .55 which is nothing close to the available answers.
statistics standard-deviation
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
$endgroup$
I took a quiz about an hour ago and the only questions I erred were ones concerning Chebyshev's theorem. I don't need to discuss them both. Nor do I want the answer. Just a hint where I messed up. Here is the question: According to Chebyshev's theorem, the proportion of values from a data set that is further than 1.5 standard deviations from the mean is at least:
a.) 0.67
b.) 0.17
c.) 1.33
d.) 0.22
Now, I plugged in the 1.5 into the "k" formula.
1-$frac{1}{1.5^2}$
and the answer I get is .55 which is nothing close to the available answers.
statistics standard-deviation
statistics standard-deviation
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
edited Oct 16 '16 at 1:11
Martin Sleziak
44.8k9118272
44.8k9118272
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
asked Sep 17 '16 at 18:37
Danny RodriguezDanny Rodriguez
1055
1055
add a comment |
add a comment |
1 Answer
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$begingroup$
There seems to be some problem with words here.
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean is at least $0$. Consider Bernouilli distribution with $p=frac12$
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean in absolute terms is less than $frac{1}{1.5^2} approx 0.444$.
- The proportion of values from a data set that is not further than $1.5$ standard deviations from the mean in absolute terms is at least $1-frac{1}{1.5^2} approx 0.556$.
- The proportion of values from a data set that is more than $1.5$ standard deviations above the mean is less than $frac{1}{1+1.5^2} approx 0.308$.
- The proportion of values from a data set that is not more than $1.5$ standard deviations above the mean is at least $1-frac{1}{1+1.5^2} approx 0.692$.
though as you say, none of these are offered answers.
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
$endgroup$
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
add a comment |
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1 Answer
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1 Answer
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$begingroup$
There seems to be some problem with words here.
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean is at least $0$. Consider Bernouilli distribution with $p=frac12$
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean in absolute terms is less than $frac{1}{1.5^2} approx 0.444$.
- The proportion of values from a data set that is not further than $1.5$ standard deviations from the mean in absolute terms is at least $1-frac{1}{1.5^2} approx 0.556$.
- The proportion of values from a data set that is more than $1.5$ standard deviations above the mean is less than $frac{1}{1+1.5^2} approx 0.308$.
- The proportion of values from a data set that is not more than $1.5$ standard deviations above the mean is at least $1-frac{1}{1+1.5^2} approx 0.692$.
though as you say, none of these are offered answers.
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
$endgroup$
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
add a comment |
$begingroup$
There seems to be some problem with words here.
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean is at least $0$. Consider Bernouilli distribution with $p=frac12$
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean in absolute terms is less than $frac{1}{1.5^2} approx 0.444$.
- The proportion of values from a data set that is not further than $1.5$ standard deviations from the mean in absolute terms is at least $1-frac{1}{1.5^2} approx 0.556$.
- The proportion of values from a data set that is more than $1.5$ standard deviations above the mean is less than $frac{1}{1+1.5^2} approx 0.308$.
- The proportion of values from a data set that is not more than $1.5$ standard deviations above the mean is at least $1-frac{1}{1+1.5^2} approx 0.692$.
though as you say, none of these are offered answers.
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
$endgroup$
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
add a comment |
$begingroup$
There seems to be some problem with words here.
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean is at least $0$. Consider Bernouilli distribution with $p=frac12$
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean in absolute terms is less than $frac{1}{1.5^2} approx 0.444$.
- The proportion of values from a data set that is not further than $1.5$ standard deviations from the mean in absolute terms is at least $1-frac{1}{1.5^2} approx 0.556$.
- The proportion of values from a data set that is more than $1.5$ standard deviations above the mean is less than $frac{1}{1+1.5^2} approx 0.308$.
- The proportion of values from a data set that is not more than $1.5$ standard deviations above the mean is at least $1-frac{1}{1+1.5^2} approx 0.692$.
though as you say, none of these are offered answers.
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
$endgroup$
There seems to be some problem with words here.
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean is at least $0$. Consider Bernouilli distribution with $p=frac12$
- The proportion of values from a data set that is further than $1.5$ standard deviations from the mean in absolute terms is less than $frac{1}{1.5^2} approx 0.444$.
- The proportion of values from a data set that is not further than $1.5$ standard deviations from the mean in absolute terms is at least $1-frac{1}{1.5^2} approx 0.556$.
- The proportion of values from a data set that is more than $1.5$ standard deviations above the mean is less than $frac{1}{1+1.5^2} approx 0.308$.
- The proportion of values from a data set that is not more than $1.5$ standard deviations above the mean is at least $1-frac{1}{1+1.5^2} approx 0.692$.
though as you say, none of these are offered answers.
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
answered Sep 17 '16 at 19:48
HenryHenry
100k480165
100k480165
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
add a comment |
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
$begingroup$
Looks like I need to call my professor then and have a chat with him.
$endgroup$
– Danny Rodriguez
Sep 19 '16 at 5:13
add a comment |
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