Quadratic polynomials over R [on hold]
Do quadratic polynomials over R from a group under composition? Yes or no and why ?
group-theory polynomials
edited Dec 26 at 6:10
Eevee Trainer
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
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put on hold as off-topic by Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde Dec 26 at 15:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
Do quadratic polynomials over R from a group under composition? Yes or no and why ?
group-theory polynomials
edited Dec 26 at 6:10
Eevee Trainer
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde Dec 26 at 15:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde
If this question can be reworded to fit the rules in the help center, please edit the question.
3
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09
add a comment |
Do quadratic polynomials over R from a group under composition? Yes or no and why ?
group-theory polynomials
edited Dec 26 at 6:10
Eevee Trainer
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Do quadratic polynomials over R from a group under composition? Yes or no and why ?
group-theory polynomials
group-theory polynomials
edited Dec 26 at 6:10
Eevee Trainer
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 26 at 6:10
Eevee Trainer
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 26 at 6:10
Eevee Trainer
4,095530
edited Dec 26 at 6:10
Eevee Trainer
4,095530
edited Dec 26 at 6:10
Eevee Trainer
4,095530
4,095530
asked Dec 26 at 6:02
Mustafa Azzurri
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 26 at 6:02
Mustafa Azzurri
12
asked Dec 26 at 6:02
Mustafa Azzurri
12
12
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mustafa Azzurri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde Dec 26 at 15:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde Dec 26 at 15:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Eevee Trainer, Leucippus, mrtaurho, Lee David Chung Lin, Dietrich Burde
If this question can be reworded to fit the rules in the help center, please edit the question.
3
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09
add a comment |
3
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09
3
3
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09
add a comment |
1 Answer
1
active
oldest
votes
Hint: (on the presumption your "R" is really $mathbb{R}$)
For a group to be formed, closure is a requisite, among other things.
Consider $f(x) = x^2$, and the composition of $f$ with itself, i.e. $(f circ f)(x)$.
Also, some notes for the future:
On MSE, it is generally preferred you include in your question your own understanding of the problem, your attempts, and any and all relevant context, i.e. where the problem comes up.
To further drive that point home, people here aren't really here to do your homework for you. They're here for you to learn, not for you to get an easy A. People will just downvote your questions or close them if they're problem-statement questions as yours is (i.e. just the question and literally nothing else from you).
You should really use MathJax to format your questions, which will help with readability (especially the "R"/"$mathbb{R}$" ambiguity as mentioned).
answered Dec 26 at 6:09
Eevee Trainer
4,095530
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Hint: (on the presumption your "R" is really $mathbb{R}$)
For a group to be formed, closure is a requisite, among other things.
Consider $f(x) = x^2$, and the composition of $f$ with itself, i.e. $(f circ f)(x)$.
Also, some notes for the future:
On MSE, it is generally preferred you include in your question your own understanding of the problem, your attempts, and any and all relevant context, i.e. where the problem comes up.
To further drive that point home, people here aren't really here to do your homework for you. They're here for you to learn, not for you to get an easy A. People will just downvote your questions or close them if they're problem-statement questions as yours is (i.e. just the question and literally nothing else from you).
You should really use MathJax to format your questions, which will help with readability (especially the "R"/"$mathbb{R}$" ambiguity as mentioned).
answered Dec 26 at 6:09
Eevee Trainer
4,095530
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
add a comment |
Hint: (on the presumption your "R" is really $mathbb{R}$)
For a group to be formed, closure is a requisite, among other things.
Consider $f(x) = x^2$, and the composition of $f$ with itself, i.e. $(f circ f)(x)$.
Also, some notes for the future:
On MSE, it is generally preferred you include in your question your own understanding of the problem, your attempts, and any and all relevant context, i.e. where the problem comes up.
To further drive that point home, people here aren't really here to do your homework for you. They're here for you to learn, not for you to get an easy A. People will just downvote your questions or close them if they're problem-statement questions as yours is (i.e. just the question and literally nothing else from you).
You should really use MathJax to format your questions, which will help with readability (especially the "R"/"$mathbb{R}$" ambiguity as mentioned).
answered Dec 26 at 6:09
Eevee Trainer
4,095530
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
add a comment |
Hint: (on the presumption your "R" is really $mathbb{R}$)
For a group to be formed, closure is a requisite, among other things.
Consider $f(x) = x^2$, and the composition of $f$ with itself, i.e. $(f circ f)(x)$.
Also, some notes for the future:
On MSE, it is generally preferred you include in your question your own understanding of the problem, your attempts, and any and all relevant context, i.e. where the problem comes up.
To further drive that point home, people here aren't really here to do your homework for you. They're here for you to learn, not for you to get an easy A. People will just downvote your questions or close them if they're problem-statement questions as yours is (i.e. just the question and literally nothing else from you).
You should really use MathJax to format your questions, which will help with readability (especially the "R"/"$mathbb{R}$" ambiguity as mentioned).
answered Dec 26 at 6:09
Eevee Trainer
4,095530
Hint: (on the presumption your "R" is really $mathbb{R}$)
For a group to be formed, closure is a requisite, among other things.
Consider $f(x) = x^2$, and the composition of $f$ with itself, i.e. $(f circ f)(x)$.
Also, some notes for the future:
On MSE, it is generally preferred you include in your question your own understanding of the problem, your attempts, and any and all relevant context, i.e. where the problem comes up.
To further drive that point home, people here aren't really here to do your homework for you. They're here for you to learn, not for you to get an easy A. People will just downvote your questions or close them if they're problem-statement questions as yours is (i.e. just the question and literally nothing else from you).
You should really use MathJax to format your questions, which will help with readability (especially the "R"/"$mathbb{R}$" ambiguity as mentioned).
answered Dec 26 at 6:09
Eevee Trainer
4,095530
edited Dec 26 at 6:17
answered Dec 26 at 6:09
Eevee Trainer
4,095530
answered Dec 26 at 6:09
Eevee Trainer
4,095530
answered Dec 26 at 6:09
Eevee Trainer
4,095530
4,095530
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
add a comment |
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
Thanks for advices I'm new here . Next time I'll post my answer even if it's wrong, also I'll use the Math Jax
– Mustafa Azzurri
Dec 26 at 6:23
add a comment |
3
What if you compose $x^2$ with itself?
– Lord Shark the Unknown
Dec 26 at 6:09