How to combine similar characters in a list?












10















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







share|improve this question

























  • If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

    – Mykola Zotko
    Feb 9 at 14:26













  • re.split with the right pattern or itertools.groupby in general should do it.

    – pylang
    Feb 11 at 18:42
















10















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







share|improve this question

























  • If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

    – Mykola Zotko
    Feb 9 at 14:26













  • re.split with the right pattern or itertools.groupby in general should do it.

    – pylang
    Feb 11 at 18:42














10












10








10








I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python







share|improve this question
















I'm trying to combine similar characters that are next to each other that are in a list. I was wondering if there was a Python way to do it? Here's an example:



test = 'hello###_world###test#test123##'

splitter = re.split("(#)", test)

splitter = filter(None, splitter)


Which returns this in the splitter variable:



['hello', '#', '#', '#', '_world', '#', '#', '#', 'test', '#', 'test123', '#', '#']


I'm trying to combine the hashes so the list turns into this:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


Thanks for any help!






python




python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 9 at 4:11









Ajax1234

42.7k42954




42.7k42954










asked Feb 9 at 4:10









GregGreg

543




543













  • If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

    – Mykola Zotko
    Feb 9 at 14:26













  • re.split with the right pattern or itertools.groupby in general should do it.

    – pylang
    Feb 11 at 18:42



















  • If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

    – Mykola Zotko
    Feb 9 at 14:26













  • re.split with the right pattern or itertools.groupby in general should do it.

    – pylang
    Feb 11 at 18:42

















If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

– Mykola Zotko
Feb 9 at 14:26







If you want to combine similar characters your result must be ['h’, ‘e', 'll', 'o', '###'...]. In your case you split the string by repeating #.

– Mykola Zotko
Feb 9 at 14:26















re.split with the right pattern or itertools.groupby in general should do it.

– pylang
Feb 11 at 18:42





re.split with the right pattern or itertools.groupby in general should do it.

– pylang
Feb 11 at 18:42












3 Answers
3






active

oldest

votes


















9














Try:



splitter = re.split("(#+)", test)





share|improve this answer



















  • 1





    It gives an empty string at the end.

    – AkshayNevrekar
    Feb 9 at 4:34






  • 3





    @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

    – DYZ
    Feb 9 at 4:37











  • This works for me. Thanks for the help!

    – Greg
    Feb 9 at 4:43











  • Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

    – pylang
    Feb 11 at 18:39



















6














You can use itertools.groupby:



import itertools

test = 'hello###_world###test#test123##'

new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


Output:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


You can also use re.findall:



import re

result = re.findall('#+|[^#]+', test)


Output:



['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





share|improve this answer


























  • This one also does the job. Thanks for the help!

    – Greg
    Feb 9 at 4:44



















3














Add + at the end of the regular expression and filtering None values will do the trick



>>> import re

>>> test = 'hello###_world###test#test123##'

>>> splitter = re.split("(#+)", test)

>>> splitter

['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']

>>> splitter = list(filter(None, splitter))

>>> splitter

['hello', '###', '_world', '###', 'test', '#', 'test123', '##']

>>>





share|improve this answer
























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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    9














    Try:



    splitter = re.split("(#+)", test)





    share|improve this answer



















    • 1





      It gives an empty string at the end.

      – AkshayNevrekar
      Feb 9 at 4:34






    • 3





      @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

      – DYZ
      Feb 9 at 4:37











    • This works for me. Thanks for the help!

      – Greg
      Feb 9 at 4:43











    • Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

      – pylang
      Feb 11 at 18:39
















    9














    Try:



    splitter = re.split("(#+)", test)





    share|improve this answer



















    • 1





      It gives an empty string at the end.

      – AkshayNevrekar
      Feb 9 at 4:34






    • 3





      @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

      – DYZ
      Feb 9 at 4:37











    • This works for me. Thanks for the help!

      – Greg
      Feb 9 at 4:43











    • Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

      – pylang
      Feb 11 at 18:39














    9












    9








    9







    Try:



    splitter = re.split("(#+)", test)





    share|improve this answer













    Try:



    splitter = re.split("(#+)", test)






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Feb 9 at 4:29









    mingganzmingganz

    33816




    33816








    • 1





      It gives an empty string at the end.

      – AkshayNevrekar
      Feb 9 at 4:34






    • 3





      @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

      – DYZ
      Feb 9 at 4:37











    • This works for me. Thanks for the help!

      – Greg
      Feb 9 at 4:43











    • Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

      – pylang
      Feb 11 at 18:39














    • 1





      It gives an empty string at the end.

      – AkshayNevrekar
      Feb 9 at 4:34






    • 3





      @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

      – DYZ
      Feb 9 at 4:37











    • This works for me. Thanks for the help!

      – Greg
      Feb 9 at 4:43











    • Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

      – pylang
      Feb 11 at 18:39








    1




    1





    It gives an empty string at the end.

    – AkshayNevrekar
    Feb 9 at 4:34





    It gives an empty string at the end.

    – AkshayNevrekar
    Feb 9 at 4:34




    3




    3





    @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

    – DYZ
    Feb 9 at 4:37





    @AkshayNevrekar With splitter = filter(None, splitter) (as in the original post), it does not.

    – DYZ
    Feb 9 at 4:37













    This works for me. Thanks for the help!

    – Greg
    Feb 9 at 4:43





    This works for me. Thanks for the help!

    – Greg
    Feb 9 at 4:43













    Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

    – pylang
    Feb 11 at 18:39





    Yep. I'd just make a habit to use raw strings in general with regex patterns, e.g. `r"(#+)".

    – pylang
    Feb 11 at 18:39













    6














    You can use itertools.groupby:



    import itertools
    
test = 'hello###_world###test#test123##'
    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    You can also use re.findall:



    import re
    
result = re.findall('#+|[^#]+', test)


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





    share|improve this answer


























    • This one also does the job. Thanks for the help!

      – Greg
      Feb 9 at 4:44
















    6














    You can use itertools.groupby:



    import itertools
    
test = 'hello###_world###test#test123##'
    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    You can also use re.findall:



    import re
    
result = re.findall('#+|[^#]+', test)


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





    share|improve this answer


























    • This one also does the job. Thanks for the help!

      – Greg
      Feb 9 at 4:44














    6












    6








    6







    You can use itertools.groupby:



    import itertools
    
test = 'hello###_world###test#test123##'
    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    You can also use re.findall:



    import re
    
result = re.findall('#+|[^#]+', test)


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']





    share|improve this answer















    You can use itertools.groupby:



    import itertools
    
test = 'hello###_world###test#test123##'
    
new_result = [''.join(b) for _, b in itertools.groupby(test, key=lambda x:x == '#')]


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']


    You can also use re.findall:



    import re
    
result = re.findall('#+|[^#]+', test)


    Output:



    ['hello', '###', '_world', '###', 'test', '#', 'test123', '##']






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Feb 9 at 4:47

























    answered Feb 9 at 4:12









    Ajax1234Ajax1234

    42.7k42954




    42.7k42954













    • This one also does the job. Thanks for the help!

      – Greg
      Feb 9 at 4:44



















    • This one also does the job. Thanks for the help!

      – Greg
      Feb 9 at 4:44

















    This one also does the job. Thanks for the help!

    – Greg
    Feb 9 at 4:44





    This one also does the job. Thanks for the help!

    – Greg
    Feb 9 at 4:44











    3














    Add + at the end of the regular expression and filtering None values will do the trick



    >>> import re
    
>>> test = 'hello###_world###test#test123##'
    
>>> splitter = re.split("(#+)", test)
    
>>> splitter
    
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
    
>>> splitter = list(filter(None, splitter))
    
>>> splitter
    
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
    
>>>





    share|improve this answer




























      3














      Add + at the end of the regular expression and filtering None values will do the trick



      >>> import re
      
>>> test = 'hello###_world###test#test123##'
      
>>> splitter = re.split("(#+)", test)
      
>>> splitter
      
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
      
>>> splitter = list(filter(None, splitter))
      
>>> splitter
      
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
      
>>>





      share|improve this answer


























        3












        3








        3







        Add + at the end of the regular expression and filtering None values will do the trick



        >>> import re
        
>>> test = 'hello###_world###test#test123##'
        
>>> splitter = re.split("(#+)", test)
        
>>> splitter
        
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
        
>>> splitter = list(filter(None, splitter))
        
>>> splitter
        
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
        
>>>





        share|improve this answer













        Add + at the end of the regular expression and filtering None values will do the trick



        >>> import re
        
>>> test = 'hello###_world###test#test123##'
        
>>> splitter = re.split("(#+)", test)
        
>>> splitter
        
['hello', '###', '_world', '###', 'test', '#', 'test123', '##', '']
        
>>> splitter = list(filter(None, splitter))
        
>>> splitter
        
['hello', '###', '_world', '###', 'test', '#', 'test123', '##']
        
>>>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Feb 9 at 4:40









        Bodhi94Bodhi94

        987621




        987621






























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