Calculating expected payoff from, with $Pr(C>c)$ or $(1 - F(c))$.












0














If a seller can earn two payoffs, zero and $Y$.



The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.



I know that;



$E[X]= int xdF(x)$.



but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.



Can i just calculate;



$E[Y]= int Yd(1-F(c))$



to calculate the expected value of $Y$?



Thanks.










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    0














    If a seller can earn two payoffs, zero and $Y$.



    The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.



    I know that;



    $E[X]= int xdF(x)$.



    but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.



    Can i just calculate;



    $E[Y]= int Yd(1-F(c))$



    to calculate the expected value of $Y$?



    Thanks.










    share|cite|improve this question









    New contributor




    Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0







      If a seller can earn two payoffs, zero and $Y$.



      The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.



      I know that;



      $E[X]= int xdF(x)$.



      but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.



      Can i just calculate;



      $E[Y]= int Yd(1-F(c))$



      to calculate the expected value of $Y$?



      Thanks.










      share|cite|improve this question









      New contributor




      Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      If a seller can earn two payoffs, zero and $Y$.



      The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.



      I know that;



      $E[X]= int xdF(x)$.



      but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.



      Can i just calculate;



      $E[Y]= int Yd(1-F(c))$



      to calculate the expected value of $Y$?



      Thanks.







      integration probability-distributions expected-value






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      share|cite|improve this question









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      share|cite|improve this question








      edited Dec 27 '18 at 8:18









      t.ysn

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      asked Dec 27 '18 at 3:16









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