Calculating expected payoff from, with $Pr(C>c)$ or $(1 - F(c))$.
Multi tool use
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
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Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
If a seller can earn two payoffs, zero and $Y$.
The cummulative distribution function for earning zero is $F(c)$ and with $1 - F(c)$ it earns $Y$. $F(c)$ is $(C*/C¨)$ and $C$ is a uniform distribution between $0$ and $C¨$.
I know that;
$E[X]= int xdF(x)$.
but this doesn't help me find the expected payoff for $Y$, as it's cdf is $(1-F(c))$.
Can i just calculate;
$E[Y]= int Yd(1-F(c))$
to calculate the expected value of $Y$?
Thanks.
integration probability-distributions expected-value
integration probability-distributions expected-value
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 '18 at 8:18
t.ysn
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 '18 at 8:18
t.ysn
1357
edited Dec 27 '18 at 8:18
t.ysn
1357
edited Dec 27 '18 at 8:18
t.ysn
1357
1357
asked Dec 27 '18 at 3:16
Yasir Khan
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 27 '18 at 3:16
Yasir Khan
1
asked Dec 27 '18 at 3:16
Yasir Khan
1
1
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Yasir Khan is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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