Are there known zeros of the Zeta function off the line 1/2?












3














I've been doing research in information theory that had some superficial connections to the Zeta function, since I was making use of logarithms of complex numbers.



In short, we'd be looking at the Zeta function using values of s produced by powers of the logarithm function:



$zeta(log^n (-1)/x).$



I noticed several zeros for n = 6:



https://www.wolframalpha.com/input/?i=plot+zeta(log%5E6(-1)%2Fx),+x+from+1+to+500



But, I don't know enough about this topic to be sure that this is actually interesting, since I know that at least some of the zeros of this function are considered "trivial". Nonetheless, I thought I'd share this in case some of you found it interesting and had insights.










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  • 3




    $zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
    – Dietrich Burde
    Dec 28 '18 at 15:42






  • 1




    There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
    – Clayton
    Dec 28 '18 at 15:42










  • For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
    – Eric Towers
    Dec 28 '18 at 19:17
















3














I've been doing research in information theory that had some superficial connections to the Zeta function, since I was making use of logarithms of complex numbers.



In short, we'd be looking at the Zeta function using values of s produced by powers of the logarithm function:



$zeta(log^n (-1)/x).$



I noticed several zeros for n = 6:



https://www.wolframalpha.com/input/?i=plot+zeta(log%5E6(-1)%2Fx),+x+from+1+to+500



But, I don't know enough about this topic to be sure that this is actually interesting, since I know that at least some of the zeros of this function are considered "trivial". Nonetheless, I thought I'd share this in case some of you found it interesting and had insights.










share|cite|improve this question




















  • 3




    $zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
    – Dietrich Burde
    Dec 28 '18 at 15:42






  • 1




    There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
    – Clayton
    Dec 28 '18 at 15:42










  • For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
    – Eric Towers
    Dec 28 '18 at 19:17














3












3








3


1





I've been doing research in information theory that had some superficial connections to the Zeta function, since I was making use of logarithms of complex numbers.



In short, we'd be looking at the Zeta function using values of s produced by powers of the logarithm function:



$zeta(log^n (-1)/x).$



I noticed several zeros for n = 6:



https://www.wolframalpha.com/input/?i=plot+zeta(log%5E6(-1)%2Fx),+x+from+1+to+500



But, I don't know enough about this topic to be sure that this is actually interesting, since I know that at least some of the zeros of this function are considered "trivial". Nonetheless, I thought I'd share this in case some of you found it interesting and had insights.










share|cite|improve this question















I've been doing research in information theory that had some superficial connections to the Zeta function, since I was making use of logarithms of complex numbers.



In short, we'd be looking at the Zeta function using values of s produced by powers of the logarithm function:



$zeta(log^n (-1)/x).$



I noticed several zeros for n = 6:



https://www.wolframalpha.com/input/?i=plot+zeta(log%5E6(-1)%2Fx),+x+from+1+to+500



But, I don't know enough about this topic to be sure that this is actually interesting, since I know that at least some of the zeros of this function are considered "trivial". Nonetheless, I thought I'd share this in case some of you found it interesting and had insights.







riemann-zeta zeta-functions riemann-hypothesis






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share|cite|improve this question













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edited Dec 28 '18 at 17:02

























asked Dec 28 '18 at 15:39









Feynmanfan85

425




425








  • 3




    $zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
    – Dietrich Burde
    Dec 28 '18 at 15:42






  • 1




    There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
    – Clayton
    Dec 28 '18 at 15:42










  • For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
    – Eric Towers
    Dec 28 '18 at 19:17














  • 3




    $zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
    – Dietrich Burde
    Dec 28 '18 at 15:42






  • 1




    There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
    – Clayton
    Dec 28 '18 at 15:42










  • For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
    – Eric Towers
    Dec 28 '18 at 19:17








3




3




$zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
– Dietrich Burde
Dec 28 '18 at 15:42




$zeta(-2n)=0$ are "trivial" zeros off the line $1/2$, see this post.
– Dietrich Burde
Dec 28 '18 at 15:42




1




1




There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
– Clayton
Dec 28 '18 at 15:42




There are no known zeros of $zeta(s)$ that don’t occur at a negative even integer (these are the trivial zeros) or have real part $sigma=frac12$. The Riemann Hypothesis states that any zero with real part between $0$ and $1$ will in fact have real part exactly $frac12$.
– Clayton
Dec 28 '18 at 15:42












For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
– Eric Towers
Dec 28 '18 at 19:17




For more on the zeroes and the history of zero finding of the Riemann zeta function, I once geeked out and wrote a fair synopsis.
– Eric Towers
Dec 28 '18 at 19:17










1 Answer
1






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7














The only known zeroes of the zeta function off of the ${1 over 2} + atimes i$ line are the negative even integers, each of which is a zero. These are called trivial zeroes. The Riemann Hypothesis states that all other zeroes lie on that magic line. It is known that at least 40% of them lie there, and none off of it have ever been found.






share|cite|improve this answer























  • Thanks. Just fixed it.
    – William Grannis
    Dec 28 '18 at 15:49










  • Please see my update, thanks.
    – Feynmanfan85
    Dec 28 '18 at 16:57











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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









7














The only known zeroes of the zeta function off of the ${1 over 2} + atimes i$ line are the negative even integers, each of which is a zero. These are called trivial zeroes. The Riemann Hypothesis states that all other zeroes lie on that magic line. It is known that at least 40% of them lie there, and none off of it have ever been found.






share|cite|improve this answer























  • Thanks. Just fixed it.
    – William Grannis
    Dec 28 '18 at 15:49










  • Please see my update, thanks.
    – Feynmanfan85
    Dec 28 '18 at 16:57
















7














The only known zeroes of the zeta function off of the ${1 over 2} + atimes i$ line are the negative even integers, each of which is a zero. These are called trivial zeroes. The Riemann Hypothesis states that all other zeroes lie on that magic line. It is known that at least 40% of them lie there, and none off of it have ever been found.






share|cite|improve this answer























  • Thanks. Just fixed it.
    – William Grannis
    Dec 28 '18 at 15:49










  • Please see my update, thanks.
    – Feynmanfan85
    Dec 28 '18 at 16:57














7












7








7






The only known zeroes of the zeta function off of the ${1 over 2} + atimes i$ line are the negative even integers, each of which is a zero. These are called trivial zeroes. The Riemann Hypothesis states that all other zeroes lie on that magic line. It is known that at least 40% of them lie there, and none off of it have ever been found.






share|cite|improve this answer














The only known zeroes of the zeta function off of the ${1 over 2} + atimes i$ line are the negative even integers, each of which is a zero. These are called trivial zeroes. The Riemann Hypothesis states that all other zeroes lie on that magic line. It is known that at least 40% of them lie there, and none off of it have ever been found.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 28 '18 at 21:04

























answered Dec 28 '18 at 15:42









William Grannis

1,015521




1,015521












  • Thanks. Just fixed it.
    – William Grannis
    Dec 28 '18 at 15:49










  • Please see my update, thanks.
    – Feynmanfan85
    Dec 28 '18 at 16:57


















  • Thanks. Just fixed it.
    – William Grannis
    Dec 28 '18 at 15:49










  • Please see my update, thanks.
    – Feynmanfan85
    Dec 28 '18 at 16:57
















Thanks. Just fixed it.
– William Grannis
Dec 28 '18 at 15:49




Thanks. Just fixed it.
– William Grannis
Dec 28 '18 at 15:49












Please see my update, thanks.
– Feynmanfan85
Dec 28 '18 at 16:57




Please see my update, thanks.
– Feynmanfan85
Dec 28 '18 at 16:57


















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